tinh gia tri bieu thuc
a)\(\left|111-324\right|+\left|-2-415\right|+\left|354-123\right|\)
b)\(\left|-2^3+5^2-35\right|-\left|3^4-2^5-12^2\right|\)
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tính giá trị biểu thức a) left|111-324right|+left|-2-415right|+left|354-123right|b) left|-2^3+5^2-35right|-left|3^4-2^5-12^2right|c) 1frac{13}{15}.0,75-left(frac{104}{195}+25%right).frac{24}{47}-3frac{12}{13}:3 d) left(2frac{1}{3}-1frac{1}{9}right):4-frac{3}{4}e)6-frac{left(2,3+5:6,25right).7}{8.0,0125+6,9}g)45frac{10}{63}-44frac{25}{84}
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tính giá trị biểu thức
a) \(\left|111-324\right|+\left|-2-415\right|+\left|354-123\right|\)
b) \(\left|-2^3+5^2-35\right|-\left|3^4-2^5-12^2\right|\)
c) \(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
d) \(\left(2\frac{1}{3}-1\frac{1}{9}\right):4-\frac{3}{4}\)
e)\(6-\frac{\left(2,3+5:6,25\right).7}{8.0,0125+6,9}\)
g)\(45\frac{10}{63}-44\frac{25}{84}\)
Tinh gia tri bieu thuc:
\(D=\left(\frac{3}{2}\right)^2+\left(\frac{1}{4}\right)^2-\left(\frac{1}{2}\right)^3\)
D = \(\frac{9}{4}+\frac{1}{16}-\frac{1}{8}\)
D = \(\frac{35}{16}\)
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\(D=\left(\frac{3}{2}\right)^2+\left(\frac{1}{4}\right)^2-\left(\frac{1}{2}\right)^3\)
\(D=\frac{9}{4}+\frac{1}{16}-\frac{1}{8}\)
\(D=\frac{37}{16}-\frac{1}{8}\)
\(D=\frac{35}{16}.\)
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a, biet x+y=0
tinh gia tri bieu thuc : M=\(x^4-xy^3+x^3y-y^4-1\)
b, biet xyz=2 va x+y+z=0
tinh gia tri bieu thuc : M= \(\left(x+y\right)\left(y+2\right)\left(x+2\right)\)
a/ \(M=x^4-xy^3+x^3y-y^4-1\)
\(\Leftrightarrow M=x^3\left(x+y\right)-y^3\left(x+y\right)-1\)
Mà \(x+y=0\)
\(\Leftrightarrow M=x^3.0-y^3.0-1\)
\(\Leftrightarrow M=-1\)
Vậy ...
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A=\(\frac{\left(1^3+2^3+3^3+...+10^3\right)\cdot\left(x^2+y^2\right)\cdot\left(x^3+y^3\right)\cdot\left(x^4+y^4\right)}{1^2+2^2+3^2+...+10^2}\)
Tinh gia tri bieu thuc
\(E=\left(25\%+\dfrac{1}{3}+0,75\right):\left(4\dfrac{3}{4}-3\dfrac{1}{2}\right)\)
tinh gia tri bieu thuc
\(=\left(\dfrac{1}{4}+\dfrac{1}{3}+\dfrac{3}{4}\right):\left(4+\dfrac{3}{4}-3-\dfrac{1}{2}\right)\)
\(=\dfrac{4}{3}:\left(1+\dfrac{1}{4}\right)=\dfrac{4}{3}:\dfrac{5}{4}=\dfrac{16}{15}\)
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Tinh hop ly gia tri cac bieu thuc sau
a) \(\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{2}:\frac{7}{12}\right).\frac{4}{5}\)
b) \(\left(\frac{377}{-231}-\frac{123}{89}+\frac{34}{791}\right).\left(\frac{1}{6}-\frac{1}{8}-\frac{1}{24}\right)\)
Cho 2 so thuc a, b thoa man dieu kien ab= 1, a+ b\(\ne\)0. Tinh gia tri bieu thuc :
P= \(\frac{1}{\left(a+b\right)^3}\left(\frac{1}{a^3}+\frac{1}{b^3}\right)+\frac{3}{\left(a+b\right)^4}\left(\frac{1}{a^2}+\frac{1}{b^2}\right)+\frac{6}{\left(a+b\right)^3}\left(\frac{1}{a}+\frac{1}{b}\right)\)
Tinh gia tri bieu thuc :
\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(=\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{999}\right).0\)
\(=0\)
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\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{9999}\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)=\(\left(\frac{1}{99}+\frac{12}{999}+\frac{123}{9999}\right).0=0\)
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Tinh hop ly gia tri bieu thuc sau
\(\left(1-\frac{1}{3}\right)\left(1-\frac{1}{5}\right)\left(1-\frac{1}{7}\right)\left(1-\frac{1}{9}\right)\left(1-\frac{1}{2}\right)\left(1-\frac{1}{4}\right)\left(1-\frac{1}{6}\right)\left(1-\frac{1}{8}\right)\left(1-\frac{1}{10}\right)\)
(1-1/3)x(1-1/5)x(1-1/7)x(1-1/9)x(1-1/2)x(1-1/4)x(1-1/6)x(1-1/8)x(1-1/10)
=2/3x4/5x6/7x8/9x1/2x3/4x5/6x7/8x9/10
=2x4x6x8x1x3x5x7x9 /3x5x7x9x2x4x6x8x10
=1/10