(x^2-5)(x^2-25)<0
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20 tháng 12 2021 lúc 20:26
Phân tích đa thức \(x^2\) + 2xy + \(y^2\)- 25 thành nhân tử. Kết quả là:
A. (x + y - 5)(x – y + 5). B. (x + y - 5)(x + y + 5).
C. (x + y - 25)(x – y + 25). D. (x + y - 25)(x + y + 25).
\(\frac{x+5}{x-5}+\frac{x-5}{x+5}=\frac{2\left(x^2+25\right)}{x^2-25}\)
(\(\dfrac{x^2-5x}{x^2-25}\)-1):(\(\dfrac{25-x^2}{x^2+2x-15}\)-\(\dfrac{x+3}{x+5}\)-\(\dfrac{x-3}{x-5}\))
1/ (left(-dfrac{2}{3}right)^2 x dfrac{-9}{8} - 25% x dfrac{-16}{5} 2/ -1dfrac{2}{5} x 75% + dfrac{-7}{5} x 25% 3/ -2dfrac{3}{7} x (-125%) + dfrac{-17}{7} x 25% 4/ (-2)^3 x (dfrac{3}{4} x 0.25) : (2dfrac{1}{4} - 1dfrac{1}{6})
Đọc tiếp
1/ (\(\left(-\dfrac{2}{3}\right)\)\(^2\) x \(\dfrac{-9}{8}\) - 25% x \(\dfrac{-16}{5}\)
2/ -1\(\dfrac{2}{5}\) x 75% + \(\dfrac{-7}{5}\) x 25%
3/ -2\(\dfrac{3}{7}\) x (-125%) + \(\dfrac{-17}{7}\) x 25%
4/ (-2)\(^3\) x (\(\dfrac{3}{4}\) x 0.25) : (2\(\dfrac{1}{4}\) - 1\(\dfrac{1}{6}\))
1) Ta có: \(\left(-\dfrac{2}{3}\right)^2\cdot\dfrac{-9}{8}-25\%\cdot\dfrac{-16}{5}\)
\(=\dfrac{4}{9}\cdot\dfrac{-9}{8}-\dfrac{1}{4}\cdot\dfrac{-16}{5}\)
\(=\dfrac{-1}{2}+\dfrac{4}{5}\)
\(=\dfrac{-5}{10}+\dfrac{8}{10}=\dfrac{3}{10}\)
2) Ta có: \(-1\dfrac{2}{5}\cdot75\%+\dfrac{-7}{5}\cdot25\%\)
\(=\dfrac{-7}{5}\cdot\dfrac{3}{4}+\dfrac{-7}{5}\cdot\dfrac{1}{4}\)
\(=\dfrac{-7}{5}\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=-\dfrac{7}{5}\)
3) Ta có: \(-2\dfrac{3}{7}\cdot\left(-125\%\right)+\dfrac{-17}{7}\cdot25\%\)
\(=\dfrac{-17}{7}\cdot\dfrac{-5}{4}+\dfrac{-17}{7}\cdot\dfrac{1}{4}\)
\(=\dfrac{-17}{7}\cdot\left(\dfrac{-5}{4}+\dfrac{1}{4}\right)\)
\(=\dfrac{17}{7}\)
4) Ta có: \(\left(-2\right)^3\cdot\left(\dfrac{3}{4}\cdot0.25\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
\(=\left(-8\right)\cdot\left(\dfrac{3}{4}\cdot\dfrac{1}{4}\right):\left(\dfrac{9}{4}-\dfrac{7}{6}\right)\)
\(=\left(-8\right)\cdot\dfrac{3}{16}:\dfrac{54-28}{24}\)
\(=\dfrac{-3}{2}\cdot\dfrac{24}{26}\)
\(=\dfrac{-72}{52}=\dfrac{-18}{13}\)
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\(\dfrac{-4+25}{x^2-25}-\dfrac{2x^2+x}{x^2-25}-\dfrac{2x}{5-x}\)
\(\dfrac{-4+25}{x^2-25}-\dfrac{2x^2+x}{x^2-25}-\dfrac{2x}{5-x}\)
= \(\dfrac{-4+25}{x^2-25}-\dfrac{2x^2+x}{x^2-25}+\dfrac{2x\left(x+5\right)}{x^2-25}\)
= \(\dfrac{-4+25-2x^2-x+2x^2+10x}{x^2-25}\)
= \(\dfrac{21+9x}{x^2-25}\)
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(12/25)^x=(5/3)^-2-(-3/5)^4
(12/25)^x=144/625
(12/25)^x=(12/25)^2
=>x=2
tìm số nguyên x biết (x^2+5):(x^2-25)=0
b,(x^2-5):(x^2-25)<0
a, => x^2+5 = 0
=> x^2=-5 ( vô lí vì x^2 >= 0)
=> ko tồn tại x tm bài toán
b, Vì x^2-5 > x^2-25
Mà (x^2-5): (x^2-25) < 0
=> x^2-5 >0 và x^2-25 <0
=> 5 < x^2 < 25
=> \(x>\sqrt{5}\)hoặc \(x< -\sqrt{5}\) và -5 < x < 5
=> -5 < x < -\(\sqrt{5}\)hoặc \(\sqrt{5}\)< x < 5
k mk nha
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1, (2x-5)62=x(2x-5)
2, x^2- 25=x(2x-5)
3, 25(x-2)^2=16(3x+1)^2
a) 25 - y^2 = 8(x+2009)^2 \Leftrightarrow 8(x+2009)^2 + y^2 = 25
Do y^2 \geq 0 \Rightarrow (x+2009)^2 \leq 25/8
\Rightarrow x+2009 =0 hoặc 1
Nếu x+2009 = 1 \Rightarrow 25 - y^2 = 1\Rightarrow y^2 = 26 (không tìm được y)
Nếu x+2009 = \Rightarrow 25 - y^2 = 0\Rightarrow y^2 = 25, y=5
Vậy (x=0;y=5)
1) 444 x 5 = 222 x 2 x 5 = 222 x 10 = 2220
a.Đúng b.Sai
2) 282 x 5 = 280 + 2 x 5 = 280 x 10 = 2800
a.Đúng b. Sai
3) 4 x 8 x 7 x 25 = (8 x 7) x (25 x4) = 56 x 100 = 5600
a.Đúng b.Sai
4) 25 x 8 x 9 = (25 x 4) x (4 x 9) = 100 x 36 = 3600
a.Đúng b.Sai
1. 444 x 5 = 222 x 2 x 5 = 222 x 10 = 2220
2. 282 x 5 = 280 + 2 x 5 = 280 x 10 = 2800
3. 4 x 8 x 7 x 25 = (8 x 7) x (25 x4) = 56 x 100 = 5600
4. 25 x 8 x 9 = (25 x 4) x (4 x 9) = 100 x 36 = 3600
a.Đúng b.Sai
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