ptich da thuc thanh nhan tu
5x2y + 10xy
x2 - 2xy + y2 - 25
x3 - 8 + 2x ( x - 2 )
x4 + x2y2 + y4
tick ạ
Những câu hỏi liên quan
3.7: Su dung cac hang dang thuc de phan tich cac da thuc sau thanh nhan tu:
a) -y2 + 1/9
b) x4 - 256
c) 9 (x - 3)2 - 4 (x + 1)2
d) 25x2 - 1/81 x2y2
a) \(-y^2+\dfrac{1}{9}\)
\(=-\left(y^2-\left(\dfrac{1}{3}\right)^2\right)\)
\(=-\left(y+\dfrac{1}{3}\right)\left(y-\dfrac{1}{3}\right)\)
b) \(4^4-256\)
\(=4^4-4^4\)
\(=0\)
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c) \(9\left(x-3\right)^2-4\left(x+1\right)^2\)
\(=\left(3x-9\right)^2-\left(2x+2\right)^2\)
\(=\left(3x-9+2x+2\right)\left(3x-9-2x-2\right)\)
\(=\left(5x-7\right)\left(x-11\right)\)
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\(a,=\left(\dfrac{1}{3}-y\right)\left(\dfrac{1}{3}+y\right)\\ b,=\left(x^2-16\right)\left(x^2+16\right)\\ =\left(x-4\right)\left(x+4\right)\left(x^2+16\right)\\ c,=\left[3\left(x-3\right)-2\left(x+1\right)\right]\left[3\left(x-3\right)+2\left(x+1\right)\right]\\ =\left(3x-9-2x-2\right)\left(3x-9+2x+2\right)\\ =\left(x-11\right)\left(5x-7\right)\\ d,=\left(5x-\dfrac{1}{9}xy\right)\left(5x+\dfrac{1}{9}xy\right)=x^2\left(5-\dfrac{1}{9}y\right)\left(5+\dfrac{1}{9}y\right)\)
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ptich da thuc thanh nhan tu
x2-y2 - 2x + 2y
x2 + 4y2 - 25 + 4xy
\(a)\)\(x^2-y^2-2x+2y\)
\(=\left(x^2-2x+1\right)-\left(y^2-2y+1\right)\)
\(=\left(x-1\right)^2-\left(y-1\right)^2\)
\(=\left(x-y\right)\left(x+y-2\right)\)
\(b)\)\(x^2+4y^2-25+4xy\)
\(=\left(x^2+4xy+4y^2\right)-25\)
\(=\left(x+2y\right)^2-25\)
\(=\left(x+2y-5\right)\left(x+2y+5\right)\)
Dumflinz
Phân tich da thuc thanh nhan tu
\(^{^{ }^2}\)x2-2xy+y2-2x+2y
\(=\left(x-y\right)^2-2\left(x-y\right)=\left(x-y\right)\left(x-y-2\right)\)
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phan tich da thuc thanh nhan tu
x^2-x-y^2-y
x^2-2xy+y^2-z^2
bai 32 va 33 sbt
lop 8 bai phan tich da thuc thanh nhan tu bang cach nhom hang tu
Ta có
a, x2-x-y2-y
=x2-y2-(x+y)
=(x-y)(x+y) - (x+y)
=(x+y)(x-y-1)
b, x2-2xy+y2-z2
=(x-y)2-z2
=(x-y-z)(x-y+z)
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con bai 32, 33 neu ban tra loi duoc minh h them
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a, ptich da thuc thanh nhan tu : x(x-y) + 2(x-y)
b, tính nhanh gtbt x2 - 6xy + 9y2 tại x = 16 và y = 2
tick nha ạh
a, x(x-y)+2(x-y)=(x-y)(x+2)
b, \(x^2-6xy+9y^2=\left(x-3y\right)^2\)Thay x=16, y=2 có
\(x^2-6xy+9y^2=\left(x-3y\right)^2=\left(16-2\cdot3\right)^2=10^2=100\)
1) x3-x2+2x-2 4) ax-2x-a2+2a 7) x2-6xy-25z2+9y2
2) x2-y2+2x+2y 5) 2xy +3z+6y+xz 8) x3-2x2+x
3) x2/4+2xy+4y2-25 6) x2y2+yz+y3+zx2 9) x4+4
phan tich da thuc thanh nhan tu (x^2+2x+3).(2x^2+2x+5)-8
x^2 - 2xy + y^2 - z^2 phan tich da thuc thanh nhan tur
\(x^2-2xy+y^2-z^2\\=(x^2-2xy+y^2)-z^2\\=(x-y)^2-z^2\\=(x-y-z)(x-y+z)\)
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(x^2+x)^2+3(x^2+x)+2
x^2+2xy+y^2+2x+2y-15
phan tich da thuc thanh nhan tu