pt da thuc thanh nhan tu
5x(x-y) + 12x-12y
x2 + 2xy - 9 + y2
tick ạ
phan tich da thuc thanh nhan tu
9-x^2+2xy-y^2
\(=3^2-\left(x-y\right)^2=\left[3-\left(x-y\right)\right]\left[3+\left(x-y\right)\right]=\left(3-x+y\right)\left(3+x-y\right)\)
\(9-x^2+2xy-y^2\)
\(=9-\left(x^2-2xy+y^2\right)\)
\(=3^2-\left(x-y\right)^2\)
\(=\left(3-x+y\right)\left(3-x-y\right)\)
x^2 - 2xy + y^2 - z^2 phan tich da thuc thanh nhan tur
\(x^2-2xy+y^2-z^2\\=(x^2-2xy+y^2)-z^2\\=(x-y)^2-z^2\\=(x-y-z)(x-y+z)\)
phan tich da thuc thanh nhan tu
x^2-x-y^2-y
x^2-2xy+y^2-z^2
bai 32 va 33 sbt
lop 8 bai phan tich da thuc thanh nhan tu bang cach nhom hang tu
Ta có
a, x2-x-y2-y
=x2-y2-(x+y)
=(x-y)(x+y) - (x+y)
=(x+y)(x-y-1)
b, x2-2xy+y2-z2
=(x-y)2-z2
=(x-y-z)(x-y+z)
con bai 32, 33 neu ban tra loi duoc minh h them
phan tich thanh cac nhan tu da thuc
x^2-25+y+2xy
phan tich da thuc thanh nhan tu
a) xy-y2+2x-2y
b) x2+2xy+y2-9
a, = (xy-y^2) + (2x-2y) = y(x-y) + 2.(x-y) = (x-y).(y+2)
b, = (x+y)^2 - 9 = (x+y-3).(x+y+3)
\(xy-y^2-2x-2y\)
=(xy-y).(2x-2y)
=y(x-y).2(x-y)
=(x-y).(y-2)
phan tich da thuc thanh nhan tu
x^2+6x+9
10x-25-x^2
8x^3-1/8
8x^3+12x^2+6xy^2+y^3
\(a,x^2+6x+9\)
\(=\left(x+3\right)^2\)
\(b,10x-25-x^2\)
\(=-\left(x^2-10x+25\right)\)
\(=-\left(x-5\right)^2\)
\(c,8x^3-\frac{1}{8}\)
\(=8x^3-\left(\frac{1}{2}\right)^3\)
\(=\left(8x-\frac{1}{2}\right)\left(64x^2+4x+\frac{1}{4}\right)\)
\(d,8x^3+12x^2+6xy^2+y^3\)
\(=2\left(4x^3+6x^2+3xy^2+\frac{1}{2}y^3\right)\)
hok tốt!
Điệp viên 007 sai c
c, \(8x^3-\frac{1}{8}=\left(2x\right)^3-\left(\frac{1}{2}\right)^3=\left(2x-\frac{1}{2}\right)\left(4x^2+x+\frac{1}{4}\right)\)
Phan tich da thuc thanh nhan tu
x2-2xy+y2-3x+3y
=(x^2-2xy-y^2)-(3x-3y)
=(x-y)^2-3(x-y)
=(x-y)(x-y-3)
Phan tich da thuc thanh nhan tu x2_2xy+y2-9z2
x^2-2xy+y^2-9z^2
=(x-y)^2-9z^2
=(x-y)^2-(3z)^2
=(x-y-3z)(x-y+3z)
16y^2-4x^2-12x-9
phan tich da thuc thanh nhan tu chung
\(16y^2-4x^2-12x-9=16y^2-\left(4x^2+12x+9\right)=\left(4y\right)^2-\left(2x+3\right)^2\)\(=\left[4y-\left(2x+3\right)\right]\left(4y+2x+3\right)=\left(4y-2x-3\right)\left(4y+2x+3\right)\)