\(...=2022+2020+\left(-2019+2016-2018+2015-2017+2014\right)+...+\left(6-3+5-2+4-1\right)\)

\(=2022+2020+\left(-3-3-3\right)+\left(-3-3-3\right)+...+\left(-3-3-3\right)+\left(-3-2-1\right)\)

\(=2022+2020+\left(-9\right)+\left(-9\right)+...\left(-9\right)+\left(-6\right)\)

\(=2022+2020+\left(-9\right).\left[\left(2019-9\right):6+1\right].\left[\left(2019+6\right)\right]:2+\left(-6\right)\)

\(=2022+2020+\left(-9\right).336.2025:2+\left(-6\right)\)

\(=2022+2020-3061800-6\)

\(=-3057764\)

A = 2013 x 2012 - 1997

A = ( 2013 x 2012 ) - 1997

A = 4050156 - 1997

A = 4048159

B = 2012 x 2011 + 2015

B = ( 2012 x 2011 ) + 2015

B = 4046132 + 2015

B = 4048147

ko phai ,ma la a=2013*2012-1997 tren 2012*2011+2015 ma

gạch ngang là gạch của phân số phải k? nếu đúng thì là thế này:

A =< 2013*2012-1997>/<2012*2011+2015>

A=<(2011+2)*2012-1997>/<2012*2011+2015>

A=<2012*2011+2012*2-1997>/<2012*2011+2015>

A=<2012*2011+2012*2-1997>/<2012*2011+2015>

A=<1+4024-1997>/<1+2015>=<4025-1997>/<2016>=2018/2016

e k chắc 100% đâu

\(\dfrac{2010}{2011}+\dfrac{2011}{2012}+\dfrac{2012}{2013}+\dfrac{2013}{2011}\)

=1-\(\dfrac{1}{2011}\)+1\(-\dfrac{1}{2012}\)+1-\(\dfrac{1}{2013}\)+1-\(\dfrac{1}{2011}\)

=4-(\(\dfrac{2}{2011}+\dfrac{1}{2012}+\dfrac{1}{2013}\)) < 4 

m=\(\dfrac{2010}{2011}+\dfrac{2011}{2012}+\dfrac{2012}{2013}+\dfrac{2013}{2011}\)

=\(1-\dfrac{1}{2011}+1-\dfrac{1}{2012}+1-\dfrac{1}{2013}+1+\dfrac{2}{2011}\)

=4+\(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}\)

vì:

do \(\dfrac{1}{2011}< 1\)

\(\dfrac{1}{2012}< 1\)

\(\dfrac{1}{2013}< 1\)

nên \(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}< 1-1-1=-1\)

hay \(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}< 0\)

nên 4+\(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}< 4\)

vậy tổng m <4

bài này mình tưởng phải lên cấp 2 mới có thế mà mấy em lớp 4 đã phải làm á

Ta có: 2011+2012/2012+2013

        =(2011/2012+2013)+(2012/2012+2013)

       Vì 2011/2012>2011/2012+2013và 2012/2013>2012/2012+2013

      Suy ra:2011/2012+2012/2013>(2011/2012+2013)+(2012/2012+2013)

            hay A>b

   Vậy A>B

A<B

Mà thật chép đúng đề ko đấy

cảm ơn bạn

Ta có:\(\frac{2010+2011+2012}{2011+2012+2013}=\frac{2010}{2011+2012+2013}+\frac{2011}{2011+2012+2013}+\frac{2013}{2011+2012+2013}\)

MÀ:\(\frac{2010}{2011+2012+2013}< \frac{2010}{2011}\)

\(\frac{2011}{2011+2012+2013}< \frac{2011}{2012}\)

\(\frac{2012}{2011+2012+2013}< \frac{2012}{2013}\)

\(\Rightarrow\frac{2010}{2011}+\frac{2011}{2012}+\frac{2012}{2013}>\frac{2010+2011+2012}{2011+2012+2013}\)

2010/2011+2012+2013>2010+2011+2012/2011+2012+2013

2011/2011+2012+2013>2010+2011+2012/2011+2012+2013

2012/2011+2012+2013>2010+2011+2012/2011+2012+2013

suy ra:2010/2011+2011/2012+2012/2013>2010+2011+2012/2011+2012+2013

A = \(\frac{2011+2012}{2012+2013}=\frac{2011+2012}{4025}\)

Ta có:

\(\frac{2011}{2012}>\frac{2011}{4025}\)

\(\frac{2012}{2013}>\frac{2012}{4025}\)

=> \(\frac{2011}{2012}+\frac{2012}{2013}>\frac{2011}{4025}+\frac{2012}{4025}\)

=> \(B>\frac{2011+2012}{4025}\)

=>\(B>A\)

bạn xem ở đây nhé

Đây

A = B

mình giỏi lắm

IQ vô cực

M<4 :)

với cả đây là bài lớp 5

m bé hơn 4

mà giờ lớp 4 học khó nhở

M=2010/2011+2011/2012+2012/2013+2013/2014
4 = 1+1+1+1
Mà 2010/2011 <1
2011/2012<1
2012/2013<1
2013/2014 <1
=>2010/2011+2011/2012+2012/2013+2013/2014​ < 1+1+1+1 
=> M<4

tích cho chị zới nha

\(\frac{2011\times2012+2013\times21+1991}{2012\times2013-2012\times2012}\)

\(=\frac{2011\times2012+2013\times\left(21+1991\right)}{2012\times2013-2012\times2012}\)

\(=\frac{2011\times2012+2013\times2012}{2012\times2013-2012\times2012}=\frac{2011}{2012}\)