mình ko biết

A= 0

B=47/41.[12.(1+1/19-1/37-1/53)/3.(1+1/19-1/37-1/53):4.(1+1/17+1/19+1/2006)/5.(1+1/17+1/19+1/2006)].123/235

=47/41.[4:4/5].123/235

=47/41.5.123/235=3

C=63.10101.37-37.10101.63/1+2+3+...+2006

=0/1+2+3+...+2006=0

CẬU XEM LẠI CHO MÌNH NHA!

\(\frac{636363.37-373737.63}{1+2+3+...+2006}=\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}=\frac{0}{1+2+3+...+2006}=0\)

Mình đảm bảo đúng 100%

Đáp án là 0

Bạn đi làm từng bước

~~~~~~~~~~~~ Chào bạn ~~~~~~~~~~~~~~~~~

$B=636363\cdot37-373737\cdot63$

$=63\cdot10101\cdot37-37\cdot10101\cdot63$

$=0$

ưeqfrety6yhythythyt

B = 636363 . 37 - 373737.63

B = 63. 10101 . 37 - 37. 10101. 63

B = 0 

(Vì cả hai vế đều giống nhau)

\(\frac{636363.37-373737.63}{1+2+3+...+2006}=\frac{63.37.10101-63.37.10101}{1+2+3+...+2006}=0\)

63.10101.37-37.10101.63=0

suy ra phep tinh =0

\(\frac{636363.37-373737.63}{1+2+3+...+2006}\)

\(=\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}\)

\(=\frac{0}{1+2+3+...+2006}\)

\(=0\)

\(\frac{636363.37-373737.63}{1+2+3+...+2006}\)

\(\Rightarrow\)\(\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}\)

\(\Rightarrow\frac{63.37-37.63}{1+2+3+...+2006}\)

\(\Rightarrow\frac{2331-2331}{1+2+3+...+2006}\)

\(\Rightarrow\frac{0}{1+2+3+...+2006}\)

\(=0\)

kết quả = 0 nha bn, vì tử số có kết quả bằng 0 ^^

\(\frac{636363.37-373737.63}{1+2+3+4+...+2006}=\frac{63.10101.37-37.10101.63}{1+2+3+4+...+2006}=\frac{0}{1+2+3+4+...+2006}=0\)

\(A=\frac{636363.37-373737.63}{1+2+3+...+2006}=\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}=\frac{0}{1+2+3+...+2006}=0\)

Tương tự, câu em vừa hỏi, tử số = 0 nên A = 0

                            \(A=\frac{636363.37-373737.63}{1+2+3+...+2006}\)

                           \(A=\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}\)

                         \(A=0\)

                    \(B=1\frac{6}{41}.\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{3}{19}-\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right).\frac{124242423}{237373735}\)

                 \(B=\frac{47}{41}.\left[\frac{4.\left(3+\frac{3}{19}-\frac{3}{37}-\frac{3}{53}\right)}{1.\left(3+\frac{3}{19}-\frac{3}{37}-\frac{3}{53}\right)}:\frac{4.\left(1+\frac{1}{17}+\frac{1}{19}+\frac{1}{2006}\right)}{5.\left(1+\frac{1}{17}+\frac{1}{19}+\frac{1}{2006}\right)}\right].\frac{124242423}{237373735}\)

                 \(B=\frac{47}{41}.\left(4:\frac{4}{5}\right).\frac{124242423}{237373735}\)

                 \(B=\frac{47}{41}.5.\frac{124242423}{237373735}\)

              \(B=\frac{47.5.124242423}{41.237373735}\)

              \(B=\frac{29196969405}{9732323135}\)

            Ủng hộ mk nha !!! ^_^

a) \(A=\frac{636363.37-373737.63}{1+2+3+...+2006}\)

\(A=\frac{10101.63.37-10101.37.63}{1+2+3+...+2006}\)

\(A=\frac{0}{1+2+3+...+2006}\)

\(A=0\)

b) \(B=1\frac{6}{41}\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{3}{19}-\frac{3}{37}-\frac{3}{53}}.\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right).\frac{124242423}{237373735}\)

\(B=\frac{47}{41}.\frac{12}{3}.\left(\frac{1+\frac{1}{19}-\frac{1}{37}-\frac{1}{53}}{1+\frac{1}{19}-\frac{1}{37}-\frac{1}{53}}\right).\frac{4}{5}.\left(\frac{1+\frac{1}{17}+\frac{1}{19}+\frac{1}{2006}}{1+\frac{1}{17}+\frac{1}{19}+\frac{1}{2006}}\right).\frac{123}{235}\)

\(B=\frac{47.4.4.123}{41.5.235}\)

\(B=\frac{47.4.4.41.3}{41.5.47.5}\)

\(B=\frac{4.4.3}{5.5}\)

\(B=\frac{48}{25}\)