\(=\dfrac{7^{2073}}{7^{2001}}+\dfrac{7^{2072}}{7^{2001}}=7^{72}+7^{71}\)

\(=7^{72}+7^{71}\)

câu hỏi???

`5^12 .25^4 .125^3 .625^2=5^12 . (5^2)^4 . (5^3)^3 . (5^4)^2 =5^12 .5^8 .5^9 .5^8=5^37`

-.-

gì mà lớn thế

1253 : 2 = 626 ( dư 1 )

1253:2=626.5

k minh nhe

= 626,5

đúng 100%

duyệt lẹ

∛27 - ∛-8 - ∛125 = ∛33 - ∛(-2)3 - ∛53

= 3 - (-2) - 5 = 3 + 2 - 5 = 0

23458508+387=23458895

= 23458895 nhe ban

đáp án là :23458913

\(\left(125^3.7^5-175^5:5\right):2016^{2017}\)

= \(\left[\left(5^3\right)^3.7^5-\left(5^2.7\right)^5:5\right]:2016^{2017}\)

= \(\left[5^{3.3}.7^5-5^{2.5}.7^5:5\right]:2016^{2017}\)

= \(\left[5^9.7^5-5^{10}.7^5:5\right]:2016^{2017}\)

= \(\left[5^9.7^5-5^9.7^5\right]:2016^{2017}\)

= \(0:2016^{2017}\)

= \(0\)

\(\dfrac{125^3\cdot7^5-175^5:5}{2016^{2017}}\)

\(=\dfrac{5^9\cdot7^5-5^{10}\cdot7^5:5}{2016^{2017}}\)

\(=\dfrac{5^9\cdot7^5-5^9\cdot7^5}{2016^{2017}}\)

=0

a, 98

b, 102

c, 56

Nhớ tích cho mình nha! ☺

A)98

B)102

C)56

Hết

a98  b102     c56                                                                                                    

3456795+1253-142+125125125+654654=129237685

nhầm bạn đúng rồi

3456795 + 1253 -142 + 125125125 + 654654 = 129237685