Bài 1:

a) \(\Rightarrow3x^2+3x-2x^2-4x+x+1=0\)

\(\Rightarrow x^2=-1\left(VLý\right)\Rightarrow S=\varnothing\)

b) \(\Rightarrow\left(x-2020\right)\left(2x-1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=2020\\x=\dfrac{1}{2}\end{matrix}\right.\)

c) \(\Rightarrow\left(x-10\right)\left(x+2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=10\\x=-2\end{matrix}\right.\)

d) \(\Rightarrow\left(x+4\right)^2=0\Rightarrow x=-4\)

e) \(\Rightarrow\left(x+6\right)\left(x-7\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=-6\\x=7\end{matrix}\right.\)

f) \(\Rightarrow\left(5x-4\right)\left(5x+4\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)

Bài 2:

a) \(\Rightarrow3x\left(x^2-4\right)=0\Rightarrow3x\left(x-2\right)\left(x+2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)

b) \(\Rightarrow x\left(x-2\right)+5\left(x-2\right)=0\Rightarrow\left(x-2\right)\left(x+5\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\)

B18:

1) \(\left(a-b+c\right)-\left(a+c\right)=a-b+c-a-c=-b\)

2) \(\left(a+b\right)-\left(b-a\right)+c=a+b-b+a+c=2a+c\)

3) \(-\left(a+b-c\right)+\left(a-b-c\right)=-a-b+c+a-b-c=-2b\)

4) \(a\left(b+c\right)-a\left(b+d\right)=ab+ac-ab-ad=ac+ad=a\left(c-d\right)\)

5) \(a\left(b-c\right)+a\left(d+c\right)=ab-ac+ad+ac=ab+ad=a\left(b+d\right)\)

1/ (a -  b + c) - (a + c) = a - b + c - a - c

                                   = (a - a) + (c - c) - b = -b

2/ (a + b) - (b - a) + c = a + b - b + a + c

                                  = (a + a) + (b - b) + c = 2a + c

3/ - (a + b - c) + (a - b - c) = -a - b + c + a - b - c

                                         = (-a + a) - (b + b) + (c - c) = -2b

4/ a(b + c) - a(b + d) = ab + ac - ab - ad

                                 = (ab - ab) + (ac - ad)

                                 = a(c - d)

5/ a(b - c) + a(c + d) = ab - ac + ac + ad

                                 = (ab + ad) + (-ac + ac)

                                 = a(b + d)

Có cần chị trả lời cho ko chó

ĐÁP ÁN C

A=100 + 98 + 96 + ... + 2 - 9 7 - 95 - .. -1

=  100 + (98 - 97) + (96-95) + ... +  + ... + (2 - 1)

= 100 + 1 + 1 + 1 +.. +1

= 100 + 1 x49

= 100 + 49 

= 149

B=1 + 2 - 3 - 4 + 5 + 6 - .... -299 - 330 +301 + 302 

 =( 1 + 2 - 3) + ( -4 + 5 + 6 -7 )  +... +(298 - 299 -300 +301 ) + 302

= 0 + 0 + .. + 0 + 302

= 302 

\(A.3x-\frac{3}{2}-5x+\frac{10}{3}=1\)

\(3x-\frac{3}{2}-5x=-\frac{7}{3}\)

\(3x-5x=-\frac{7}{3}+\frac{3}{2}\)

\(-2x=-\frac{5}{6}\)

\(x=-\frac{5}{6}:\left(-2\right)\)

\(x=\frac{5}{12}\)