1 cong 1
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tinh nhanh tong sau 1 phan 2 cong 1 phan 4 cong 1 phan 8 cong 1 phan 10 cong 1 phan 16 cong 1 phan 32 cong 1 phan 64 cong 1 phan 128
1/2+1/4+1/8+1/10+1/16+1/32+1/64+1/128
=1-1/2+1/2-1/4+1/4-1/6+1/6-1/8+1/8-1/16+1/16-1/32+1/32-1/64+1/64-1/128+1/128
=1-1/128
=127/128
#Sagittarius#
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Tinh nhanh
1/16 cong 1/32 cong 164 cong 1/128 cong 1/256 cong 1/512 cong 1/1024
Lam tung buoc ra nha thanks
1 CONG 3 CONG 5 CONG CONG .......... CONG [ 2x X CONG 1] =169
ko đưa câu hỏi linh tinh lên diễn đàn
MK DAU CO DUA CAU HOI LINH TINH
what???????????????
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tim z,y,z thoa
can x cong can tat ca y tru 1 cong can tat ca z tru 2 bang 1 phan 2 ( x cong y cong z)
tim GTN cua B bang 1 phan x tru can x cong 1
tim x thuoc z de can x cong 1 phan can 3 tru 3 la so nguyen
tinh tong T bang 1 phan can 1 cong can 2 cong 1 phan can 2 cong can 3 cong ... cong den 1 phan can 99 cong can 100
1 CONG 3 CONG 5 CONG ............... CONG [ 2x X 1] CONG 169
gì thế
CAU HOI CHU GI NUA
MK DUNG MAY TINH KHONG CO DAU NEN PHAI LAM THE
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chung to rang
1/1.2 cong 1/2.3 cong 1/3.4 cong ... cong 1/99.100 be hon 1
1 CONG 3 CONG 5 CONG .........CONG [ 2 x X CONG 1] = 169
ai tra loi giup mk voi
chung to rang B = 1/2mu 2 cong 1/3 mu 2 cong 1/4 mu 2 cong 1/5 mu 2 cong 1/6 mu 2cong 1/7 mu 2 cong 1/8 mu2 nho hon 1
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Cho A bang 1 phan 11 cong 1 phan 12 cong 1 phan 13 cong......cong 1 phan 39 cong 1 phan 40
Chung minh A lon hon 3 phan 4
Ta có 1/11; 1/12; 1/13;...; 1/39 > 1/40
\(\Rightarrow\) A = 1/11 + 1/12 + 1/13 +...+ 1/39 +1/40 > 1/40 + 1/40 + 1/40 +...+ 1/40 + 1/40(có 30 số hạng)
A > 30/40
Mà 30/40 =3/4 nên A >3/4
Vậy A > 3/4
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C] [ X-1/2 ] CHIA [ 1/2 CONG 1/6 CONG 1/12 CONG 1/20 ] = 1/3
c) \(\frac{x-\frac{1}{2}}{\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}}=\frac{1}{3}\)
Đặt \(S=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}\)
\(S=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}\)
\(S=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{4}-\frac{1}{5}\)
\(S=1-\frac{1}{5}=\frac{4}{5}\)
Do đó \(\frac{x-\frac{1}{2}}{S}=\frac{1}{3}\)
=> \(x-\frac{1}{2}=\frac{1}{3}S=\frac{1}{3}\cdot\frac{4}{5}=\frac{4}{15}\)
=> \(x=\frac{4}{15}+\frac{1}{2}=\frac{23}{30}\)