a) 2 nhân 4 cộng 6 nhân x bằng 570
b) x nhân 5 cộng 4 cộng 4 nhân x bằng 918
Tìm y :
a) y x 4 + y x 6 = 570
b) y x 5 + 4 x y = 918
Y × 4 + 6 × Y = 570
Y × ( 4 + 6 ) = 570
Y × 10 = 570
Y = 570 : 10
Y = 57
Y × 5 + 4 × Y = 918
Y × ( 5 + 4 ) = 918
Y × 9 = 918
Y = 918 : 9
Y = 102
tìm x
a, 12:x+5 = 3+25+5
b,170-5* (x+19)=50
c, 11* (x-6) =4* x +11
dấu * là dấu nhân nha
a) 12 : x + 5 = 33
12 : x = 33 - 5
12 : x = 28
x = 12 : 28
x = 1/4
Vậy x = 1/4
b) 5*(x + 19) = 170 - 50
5*(x+19) = 120
x + 19 = 120 : 5
x + 19 = 24
x = 24 - 19
x = 5
Vậy x = 5
c) 11*(x - 6) - 11 = 4*x
11*(x-7) = 4x
11x - 77 = 4x
11x - 4x = 77
7x = 77
x = 11
Vậy x = 11
Tìm x cần gấp
A.12:(x+4).3=6 (dấu chấm là nhân)
B.12:(x+4).3=5
C.12:(x+4).3+18=24
Trả lời
A.12:(x+4).3=6
12:(x+4) =6:3
12:(x+4) =2
x+4 =12:2
x+4 =6
x =6-4
x =2
a) 12 : (x + 4).3 = 6
\(\frac{12}{\left(x+4\right)}.3=6\)
\(\frac{36}{\left(x+4\right)}=6\)
x + 4 = 36 : 6
x + 4 = 6
x = 6 - 4
x = 2
b) 12 : (x + 4).3 = 5
\(\frac{12}{\left(x+4\right)}.3=5\)
\(\frac{36}{\left(x+4\right)}=5\)
x + 4 = 36 : 5
x + 4 = \(\frac{36}{5}\)
x = \(\frac{36}{5}\) - 4
x = \(\frac{16}{5}\)
c) 12 : (x + 4).3 + 18 = 24
\(\frac{12}{\left(x+4\right)}.3+18=24\)
\(\frac{18x+108}{x+4}=24\)
18x + 108 = 24x + 96
18x + 108 - 24x = 96
-6x + 108 = 96
-6x = 96 - 108
-6x = -12
x = -12 : -6
x = 2
a) 12 : (x + 4) . 3 = 6
=>(x + 4) . 3 = 12 : 6
=> (x + 4) . 3 = 2
=> x + 4 = 2 . 3
=> x + 4 = 6
=> x = 2
b) 12 : (x + 4) . 2 = 5
12 : (x + 4) = 5 : 2
12 : (x + 4) = 2,5
x + 4 = 12 : 2,5
x + 4 = 4,8
x = 0,8
c) 12 : (x + 4) . 3 + 18 = 24
=>12 : (x + 4) . 3 = 42
=> 12 : (x + 4) = 42 : 3
=> 12 : (x + 4) = 14
=> x + 4 = 12 : 14
=> x + 4 = 6/7
=> x = 6/7 - 4
=> x = -22/7
Tìm x :
a. x+ 6 và 1/8 =8
b. 11/2 * x = 1/5 :1/3
c. x*3/5 + 2/5 *x =4/9 + 1/3
Chú thích : dấu * là dấu nhân
a: \(x+6\dfrac{1}{8}=8\)
=>\(x+\dfrac{49}{8}=\dfrac{64}{8}\)
=>\(x=\dfrac{64}{8}-\dfrac{49}{8}=\dfrac{15}{8}\)
b: \(\dfrac{11}{2}\cdot x=\dfrac{1}{5}:\dfrac{1}{3}\)
=>\(x\cdot\dfrac{11}{2}=\dfrac{1}{5}\cdot3=\dfrac{3}{5}\)
=>\(x=\dfrac{3}{5}:\dfrac{11}{2}=\dfrac{3}{5}\cdot\dfrac{2}{11}=\dfrac{6}{55}\)
c: \(x\cdot\dfrac{3}{5}+\dfrac{2}{5}\cdot x=\dfrac{4}{9}+\dfrac{1}{3}\)
=>\(x\left(\dfrac{3}{5}+\dfrac{2}{5}\right)=\dfrac{4}{9}+\dfrac{3}{9}\)
=>\(x\cdot1=\dfrac{7}{9}\)
=>\(x=\dfrac{7}{9}\)
Bài 3: Tìm x:
a) x x 4 + 6 x x = 570 b) x x 5 + 4 x x = 918
a) x x 4 + 6 x x = 570
x x (4 + 6) = 570
x x 10 = 570
x = 570 : 10
x = 57
b) x x 5 + 4 x x = 918
x x (5 + 4) = 918
x x 9 = 918
x = 918 : 9
x = 102
Bài 3: Tìm x:
a) x x 4 + 6 x x = 570 b) x x 5 + 4 x x = 918
Bài 3: Tìm x:
a) x x 4 + 6 x x = 570 b) x x 5 + 4 x x = 918
a. X x 4 + 6 x X = 570
X x ( 4+6) = 570
X x 10 = 570
X = 57
b. x x ( 5+4)= 918
x x 9 = 918
x = 918 : 9
x = 102
Tìm x
a, 317- ( x + 317 ) + 43 + ( 9 - 21 )
b, ( 15 - x ) + ( x - 12 ) = 7 - ( 52 + x )
c, 2 . ( x - 5 ) - 3 . ( x - 4 ) = -6 - 45
Dấu ' . ' là dấu nhân nhé các bạn