Tính nhanh A:
A = 2003 x 14 + 1988 + 2001 x 2002
2002 + 2002 x 503 + 504 x 2002
tính nhanh
2003 x 14 + 1988 + 2001 x 2002
2002 + 2002 x 503 + 504 x 2002
P=\(\frac{\left(2002+1\right)\times14+1988+2001\times2002}{2002\times\left(1+503+504\right)}\)
\(=\frac{2002\times14+2002+2001\times2002}{2002\times1008}\)
\(=\frac{2002\times\left(14+1+2001\right)}{2002\times1008}=\frac{2016}{1008}=2\)
tính nhanh: 2003*14+1988+2001*2002/2002+2002*503+504*2002
Tính nhanh :
a) 2003 x 14 + 1988 + 2001 + 2002
2002 + 2002 x 503 + 504 x 2002
b) 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128.
a ) \(\frac{2003\times14+1988+2001+2002}{2002+2002\times503+504\times2002}\)
= \(\frac{\left(2002+1\right)\times14+1988+2001\times2002}{2002\times\left(1+503+504\right)}\)
= \(\frac{2002\times14+14+1998+2001\times2002}{2002\times1008}\)
= \(\frac{2002\times14+2002+2001\times2002}{2002\times1008}\)
= \(\frac{2002\times\left(14+1+2001\right)}{2002\times1008}\)
= \(\frac{2016}{1008}\)
= 2
b ) Đặt A = 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128
=> 2A = 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64
=> 2A - A = ( 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 ) - ( 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 )
=> A = 1/2 - 1/128
A = 63/128
\(b,\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+..+\frac{1}{128}\)
\(=\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^7}=A\)
\(\Rightarrow2A=\frac{1}{2}+\frac{1}{2^2}+..+\frac{1}{2^6}\)
\(\Rightarrow2A-A=\left(\frac{1}{2}+\frac{1}{2^2}+..+\frac{1}{2^6}\right)-\left(\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^7}\right)\)
\(\Rightarrow A=\frac{1}{2}-\frac{1}{2^7}\)
Bài này làm thế nào vậy mọi người
A/E= 2003 x 14 + 1988 + 2001 + 2002 phần
2002 + 2002 x 503 + 504 + 2002
2003 x 14 + 1988 + 2001 x 2002
=28042 + 1988 + 4006002
=4036032
2002 + 2002 x 503 +504 x 2002
=2002 x 1 + 2002 x 503 + 504 x 2002
=2002 x (1 + 503 + 504)
=2002 x 908
=1817816
(2003*14+1988+2001*2002)/(2002+2002*503+504*2002)
(2003*14+1988+2001*2002)/(2002+2002*503+504*2002) = 2
tính nhanh
2003 x 14 + 1998 + 2001 x 2002
2002 + 2002 x + 503 + 504 x 2002
2003*14*1988+2001*2002
2002+2002*503+504*2002
a) 63 759 500
b) 2 018 016
1 . Tính 2003 x 14 + 1998 + 2001 x 2002 phần 2002 + 2002 x 503 + 504 x 2002
cho mình sửa một chút 1998->1988
\(\frac{2003\times14+1998+2001\times2002}{2002+2002\times503+504\times2002}=\frac{\left(2002+1\right)\times14+1998+2001\times2002}{2002\left(1+503+504\right)}=\frac{2002\times14+14+1998+2001\times2002}{2002\times1008}\)=\(\frac{2002\times14+2002\times2001+2002}{2002\times1008}=\frac{2002\left(14+2001+1\right)}{2002\times1008}=\frac{2002\times2016}{2002\times1008}\)=\(\frac{2016}{1008}=\frac{2}{1}=2\)
phân số thì không ra mà chỉ ra số thập phân thôi nha bạn
Kết Quả là: 2,000004955 nha.
2003x14+1988+2001x2002 2002+2002x503+504x2002
(2003*14+1988+2001*2002) / ( 2002 + 2002 * 503 + 2002 * 504 )
Phải giải đầy đủ và trả lời sớm nhất thì mk tick
(2003*14+1988+2001*2002) / ( 2002 + 2002 * 503 + 2002 * 504 )
=4036042:2018016
=2