\(3\left(2x-3\right)\left(3x+2\right)-2\left(x+4\right)\left(4x-3\right)+9x\left(4-x\right)=0\)

\(\Leftrightarrow x^2-5x+6=0\)

\(\Leftrightarrow\left(x^2-3x\right)+\left(-2x+6\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(x-2\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=3\\x=2\end{cases}}\)

xin lỗi toán lớp 8 thì mk chịu

\(3\left(6x^2-5x-6\right)-2\left(4x^2-13x-12\right)+36x-9x^2=0\)

\(10x^2-15x-18-8x^2+26x+24+36x-9x^2=0\)

\(-7x^2+47x+6=0\Leftrightarrow\orbr{\begin{cases}x=\frac{-47+\sqrt{2377}}{-14}\\x=\frac{-47-\sqrt{2377}}{-14}\end{cases}}\)

a)  8x-75=5x+21

     8x-5x=21+75

      3x=96:3

        x=32

b)     9x+25=-(2x-58)

         9x+25=-2x+58

         9x+2x=58-25

           11x=33

              x=33:11

               x=3

tick mình nha

bn nhấn vào đúng 0 sẽ ra đáp án

a, 8x-5x=21+75

=>3x=96

=>x=32

b, 9x+25=-2x+58

=>9x+2x=58-25

=>11x=33

=>x=3

a) 6x(3x +5)-2x(9x-2)=17

6x3x+6x5-2x9x-2x(-2)=17

\(18x^2\)+30x-\(18x^2\)+4x=17

\(18x^2-18x^2\)+ 34x=17

0 +34x=17

x=17:34

x=0.5

b)2x(3x-1)-3x(2x+11)-70=0

2x3x-2x1-3x2x+3x11-70=0

\(6x^2-2x-6x^2+33x-70=0\)

-2x+33x-70=0

31x-70=0

31x=0+70

31x=70

x=\(\frac{70}{31}\)

(trong câu c dấu . của mình là nhân nha)

c)5x(2x-3)-4(8-3x)=2(3+5x)

5x2x-5x3-4.8+4.3x=2.3+2.5x

\(10x^2-15x-32+12x=6+10x\)

\(10x^2-15x+12x-10x=6+32\)

\(10x^2-13x=38\)

tạm thời mình bí chổ này thông cảm nha bạn

\(a,8x-75=5x+21\)

    \(8x-5x=21+75\)

               \(3x=96\)

                  \(x=32\)

\(b,9x+25=-\left(2x-58\right)\)

    \(9x+25=-2x+58\)

    \(9x+2x=58-25\)

            \(11x=33\)

                 \(x=3\)

\(c,\left(5-x\right).\left(x+2\right)=0\)

\(\Rightarrow\orbr{\begin{cases}5-x=0\\x+2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-2\end{cases}}}\)

a) \(8x-75=5x+21\)

\(8x-5x=21+75\)

\(3x=96\)

\(x=32\)

vậy \(x=32\)

b) \(9x+25=-\left(2x-58\right)\)

\(9x+25=-2x+58\)

\(9x+2x=58-25\)

\(11x=33\)

\(x=3\)

vậy \(x=3\)

c) \(\left(5-x\right)\left(x+2\right)=0\)

\(\Rightarrow\orbr{\begin{cases}5-x=0\\x+2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=5\\x=-2\end{cases}}\)

vậy....

d) \(3.\left|x+3\right|-4=-7-\left(-18\right)\)

\(3.\left|x+3\right|-4=-7+18\)

\(3.\left|x+3\right|=11+4\)

\(3.\left|x+3\right|=15\)

\(\left|x+3\right|=5\)

\(\Rightarrow\orbr{\begin{cases}x+3=5\\x+3=-5\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x=-8\end{cases}}\)

vậy..

\(8x-75=5x+21\)

\(8x-5x=75+21\)

\(3x=96\)

\(x=32\)

Vậy \(x=32.\)

\(9x+25=-\left(2x-58\right)\)

\(9x+25=-2x+58\)

\(9x+2x=-25+58\)

\(11x=33\)

\(x=3\)

Vậy \(x=3.\)

\(15-\left|2x-1\right|=-8\)

\(\left|2x-1\right|=23\)

\(\Rightarrow\orbr{\begin{cases}2x-1=23\\2x-1=-23\end{cases}\Rightarrow}\orbr{\begin{cases}2x=24\\2x=-22\end{cases}}\Rightarrow\orbr{\begin{cases}x=12\\x=-11\end{cases}}\)

Vậy \(x\in\left\{12;-11\right\}\)

8x-5x=75+21

3x=96

x=32

9x+25=-2x+58

9x+2x=58-25

11x=33

x=3

-2x - (x - 7) = 34 - (-x + 25)

-3x+7=34+x-25

-4x=2

x=-1/2

-2x-(x-7)=34-(-x+25)

-2x-x+7=34+x-25

-2x-x+7-34-x+25=0

-4x-2=0

-4x=2

x=\(-\frac{1}{2}\)

#H

Toán tìm x :

-2x - (x - 7) = 34 - (-x + 25)

-3x+7 = 34+x+25

-4x=x+34+25

-4x=x+59

-4x=60

x=-15

25<15x<35

mà x là số nguyên

nên 15x=30

hay x=2

\(\Rightarrow\left[{}\begin{matrix}-2x+12=10\\2x-12=10\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}-2x=-2\\2x=22\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=11\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}-2x+12=10\\-2x+12=-10\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=11\end{matrix}\right.\)