\(S=\dfrac{3}{10}+\dfrac{3}{11}+\dfrac{3}{12}+\dfrac{3}{13}+\dfrac{3}{14}\)

\(\Rightarrow S< \dfrac{3}{10}+\dfrac{3}{10}+\dfrac{3}{10}+\dfrac{3}{10}+\dfrac{3}{10}\)

\(\Rightarrow S< \dfrac{15}{10}< 2\)

Lại có \(S>\dfrac{3}{14}+\dfrac{3}{14}+\dfrac{3}{14}+\dfrac{3}{14}+\dfrac{3}{14}\)

\(\Rightarrow S>\dfrac{15}{14}>1\)

\(\Rightarrow1< S< 2\)

Tham khảo:

Ta có: \(\dfrac{3}{10}>\dfrac{3}{15}\)

\(\dfrac{3}{11}>\dfrac{3}{15}\)

\(\dfrac{3}{12}>\dfrac{3}{15}\)

\(\dfrac{3}{13}>\dfrac{3}{15}\)

\(\dfrac{3}{14}>\dfrac{3}{15}\)

Do đó: \(\dfrac{3}{10}+\dfrac{3}{11}+\dfrac{3}{12}+\dfrac{3}{13}+\dfrac{3}{14}>\dfrac{3}{15}+\dfrac{3}{15}+\dfrac{3}{15}+\dfrac{3}{15}+\dfrac{3}{15}=1\)

hay 1<S(1)

Ta có: \(\dfrac{3}{11}< \dfrac{3}{10}\)

\(\dfrac{3}{12}< \dfrac{3}{10}\)

\(\dfrac{3}{13}< \dfrac{3}{10}\)

\(\dfrac{3}{14}< \dfrac{3}{10}\)

Do đó: \(\dfrac{3}{11}+\dfrac{3}{12}+\dfrac{3}{13}+\dfrac{3}{14}< \dfrac{3}{10}+\dfrac{3}{10}+\dfrac{3}{10}+\dfrac{3}{10}=\dfrac{12}{10}\)

\(\Leftrightarrow S< \dfrac{15}{10}=\dfrac{3}{2}< 2\)(2)

Từ (1) và (2) suy ra 1<S<2(đpcm)

Bạn làm hay quá

S> 3/15 .5

S>1

S< 3/10x5=3/2 <2 

cậu giải chi tiết hơn đc ko

S=3/10+3/11+3/12+3/13+3/14
S<3/10.5

S<15/10<2

S=3/10+3/11+3/12+3/13+3/14

S>3/14.5

S<15/14>1

Vậy 1<s<2 (ĐPCM)
_Yên tâm cách giải=))Con này đội tuyển toán 6
Nhớ k

giải\(s>\frac{3}{15}+\frac{3}{15}+\frac{3}{15}+\frac{3}{15}+\frac{3}{15}=\frac{15}{15}=1\)

\(s<\frac{3}{10}+\frac{3}{10}+\frac{3}{10}+\frac{3}{10}+\frac{3}{10}=\frac{15}{10}<\frac{20}{10}=2\)

vậy 1<s<2

=>s không thuộc N

Tự hỏi tự mình trả lời lun....?!?!?? :)

@QuynhAnh_Nee: Có một số tài khoản lm như vậy để khoe mẽ đó bn.

\(\frac{3}{10}+\frac{3}{11}+\frac{3}{12}+\frac{3}{13}+\frac{3}{14}\)

\(\Rightarrow\frac{3}{14}+\frac{3}{14}+\frac{3}{14}+\frac{3}{14}+\frac{3}{14}< S< \frac{3}{10}+\frac{3}{10}+\frac{3}{10}+\frac{3}{10}+\frac{3}{10}\)

\(\frac{3}{14}\times5< S< \frac{3}{10}\times5\Rightarrow\frac{15}{14}< S< \frac{3}{2}\)

mà \(\frac{15}{14}>1;\frac{3}{2}< 2\Rightarrow1< S< 2\)

\(S=\dfrac{3}{10}+\dfrac{3}{11}+\dfrac{3}{12}+\dfrac{3}{13}+\dfrac{3}{14}\)

Ta thấy:

\(\dfrac{3}{10}>\dfrac{3}{15}\\\dfrac{3}{11}>\dfrac{3}{15}\\ \dfrac{3}{12}>\dfrac{3}{15}\\ \dfrac{3}{13}>\dfrac{3}{15}\\ \dfrac{3}{14}>\dfrac{3}{15} \)

\(\Rightarrow S=\dfrac{3}{10}+\dfrac{3}{11}+\dfrac{3}{12}+\dfrac{3}{13}+\dfrac{3}{14}>5\cdot\dfrac{3}{15}\\ S=\dfrac{3}{10}+\dfrac{3}{11}+\dfrac{3}{12}+\dfrac{3}{13}+\dfrac{3}{14}>1\left(1\right)\)

Mặt khác:

\(\dfrac{3}{10}< \dfrac{3}{9}\\ \dfrac{3}{11}< \dfrac{3}{9}\\ \dfrac{3}{12}< \dfrac{3}{9}\\ \dfrac{3}{13}< \dfrac{3}{9}\\ \dfrac{3}{14}>\dfrac{3}{9}\)

\(\Rightarrow S=\dfrac{3}{10}+\dfrac{3}{11}+\dfrac{3}{12}+\dfrac{3}{13}+\dfrac{3}{14}< 5\cdot\dfrac{3}{9}\\ S=\dfrac{3}{10}+\dfrac{3}{11}+\dfrac{3}{12}+\dfrac{3}{13}+\dfrac{3}{14}< \dfrac{5}{3}< 2\left(2\right)\)

Từ (1) và (2) ta có: \(1< S< 2\)