\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{ \left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\frac{2^{20}}{2^{12}}=2^8=256\)

Chúc học tốt :)

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)

\(M=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}\)

\(M=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)

\(M=\frac{2^{20}.\left(2^{10}+1\right)}{2^{12}.\left(1+2^{10}\right)}\)

\(M=\frac{2^{20}}{2^{12}}\)

\(M=2^8=256\)

\(M=\frac{8^{10}+4^{10}=1.074.790.400}{8^4+4^{11}=4.198.400}\)

Vậy 

\(\Rightarrow M=\frac{1.074.790.400}{4.198.400}\)

P/s; Ko chắc đâu nhé

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{12}.2^8\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=2^8\)

8^10 + 4^10 / 8^4 + 4^11

= (2^3)^10 + (2^2)^10 / (2^3)^4 + (2^2)^11

= 2^30 + 2^20 / 2^12 + 2^22

= 2^20 . (2^10 + 1) / 2^12 . (1 + 2^10)

= 2^20 / 2^12

= 2^8

= 256

\(M=\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\frac{2^{20}}{2^{12}}=2^8\)

tách 8 thành 2 mũ 3, 4 thành 2 mũ 2 là sẽ ra nhé 

đáp án là 2 mũ 8 

\(A=\sqrt{\frac{8^{10}+4^{10}}{8^4+4^{11}}}=\sqrt{\frac{2^{30}+2^{20}}{2^{22}+2^{12}}}=\sqrt{\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(2^{10}+1\right)}}=\sqrt{\frac{2^{20}}{2^{12}}}=\sqrt{2^8}=\sqrt{\left(2^4\right)^2}\)\(=2^4=16.\)

#)Giải :

\(A=\sqrt{\frac{8^{10}+4^{10}}{8^4+4^{11}}}=\sqrt{\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}}=\sqrt{\frac{2^{30}\left(2^{10}+1\right)}{2^{12}\left(2^{10}+1\right)}}=\sqrt{\frac{2^{30}}{2^{12}}}=\sqrt{2^8}=\sqrt{256}=16\)

\(M=\sqrt{\frac{8^{10}-4^{10}}{4^{11}-8^4}}\)

\(=\sqrt{\frac{2^{30}-2^{20}}{2^{22}-2^{12}}}\)

\(=\sqrt{\frac{2^{20}\left(2^{10}-1\right)}{2^{12}\left(2^{10}-1\right)}}\)

\(=\sqrt{\frac{2^{20}}{2^{12}}}\)

\(=\sqrt{2^8}\)

\(=2^4\)

\(=16\)

=.= hok tốt!!

\(A=\sqrt{\frac{2^{30}+2^{20}}{2^{12}+2^{22}}}=\sqrt{\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}}=\sqrt{2^{20-12}}=\sqrt{2^8}=2^4=16\)