M = 4/31.7 + 6/7.41+ 9/10.41 + 7/10.57
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B=4/31.7+6/7.41+9/10.41+7/10.57
\(B=\frac{4}{31.7}+\frac{6}{7.41}+\frac{9}{10.41}+\frac{7}{10.57}\)
\(\frac{B}{5}=\frac{4}{31.35}+\frac{6}{35.41}+\frac{9}{41.50}+\frac{7}{50.57}\)
\(\frac{B}{5}=\frac{1}{31}-\frac{1}{35}+\frac{1}{35}-\frac{1}{41}+\frac{1}{41}-\frac{1}{50}+\frac{1}{50}-\frac{1}{57}\)
\(B=5\left(\frac{1}{31}-\frac{1}{57}\right)=5\cdot\frac{26}{1767}=\frac{130}{1767}\)
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C = 4 / 31 .7 + 6/ 7.41 + 9/10.41 + 7/10.57
A=4/7.31+6/7.41+9/10.41+7/10.57+13/57.14
`Answer:`
\(A=\frac{4}{7.31}+\frac{6}{7.41}+\frac{9}{10.41}+\frac{7}{10.57}\)
\(=\frac{5.4}{5.\left(7.31\right)}+\frac{5.6}{5.\left(7.41\right)}+\frac{5.9}{5.\left(10.41\right)}+\frac{5.17}{5.\left(10.57\right)}\)
\(=\frac{20}{35.31}+\frac{30}{35.41}+\frac{45}{50.41}+\frac{35}{50.57}\)
\(=5.\left(\frac{4}{35.31}+\frac{6}{35.41}+\frac{9}{50.41}+\frac{7}{50.57}\right)\)
\(=5.\left(\frac{1}{31}-\frac{1}{35}+\frac{1}{35}-\frac{1}{41}+\frac{1}{41}-\frac{1}{50}+\frac{1}{50}-\frac{1}{57}\right)\)
\(=5.\left(\frac{1}{31}-\frac{1}{57}\right)\)
\(=5.\frac{26}{1767}\)
\(=\frac{130}{1767}\)
Cho M=\(\frac{4}{31.7}+\frac{6}{7.41}+\frac{9}{10.41}+\frac{7}{10.57}\)
Và N = \(\frac{7}{19.31}+\frac{5}{19.45}+\frac{3}{23.43}+\frac{11}{23.57}\)
Tính \(\frac{M}{N}\)
Cho M=4/31.7+6/4.41+9/10.41+7/10.57
và N=7/19.31+5/19.43+3/23.43+11/23.57
tính M/N
A=4/19.31+6/7.41 +9/10.41+ 7/10.57
Tính A
Cho M=\(\frac{4}{31.7}+\frac{6}{7.41}+\frac{9}{10.41}+\frac{7}{10.57}\) và N=\(\frac{7}{19.31}+\frac{5}{19.43}+\frac{3}{23.43}+\frac{11}{23.57}\)
Tính tỉ số \(\frac{M}{N}\).
Bài 5: Thực hiện phép tính \(\dfrac{4}{7.31}+\dfrac{6}{7.41}+\dfrac{9}{10.41}+\dfrac{7}{10.57}\)
=4/217+6/287+9/410+7/570
=130/1767
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\(\frac{4}{7.31}+\frac{6}{7.41}+\frac{9}{10.41}+\frac{7}{10.57}=?\)