\(\dfrac{x-6}{50}+\dfrac{x-6}{51}=\dfrac{x-6}{52}+\dfrac{x-6}{53}\)

\(\Rightarrow\dfrac{x-6}{51}+\dfrac{x-6}{50}-\dfrac{x-6}{52}-\dfrac{x-6}{53}=0\)

\(\Rightarrow\left(x-6\right)\left(\dfrac{1}{50}+\dfrac{1}{51}-\dfrac{1}{52}-\dfrac{1}{53}\right)=0\)

\(\Rightarrow x-6=0\) \(\Rightarrow x=6\)

  Vậy ...

jjjjjjbbb

x-6/50+x-6/51=x-6/52+x-6/53

x+x-x-x=6/50+6/51-6/52-6/53

0x=6/50+6/51-6/52-6/53(vô ly)

=>ko tồn tại giá trị x

giúp mình với

a] -567 + 113 - 113567 - 2011

   = -454 - 113567 - 2011

   = -114021 - 2011= -116032

B] -137 x [52 + 47+1]

    = -137 x 100

    = -13700

C] 15 x [16 - 222] - 16 x [222 + 15] 

   = 15 x [-206] - 16 x 237

   =  -3090 - 3792

   =  -6882

Câu 1: D

Câu 2: B

Câu 19: C

Câu 20: A

Câu 21: D

D

B

C

A

D

D

B

C

A

D

???///

x:125=\(\frac{69}{115}\)

x=\(\frac{69}{115}\times125\)

x=75

mình ko biết làm

75nhe

`x xx 95 + x + x : 0,25 = 7963`

`x xx (95 + 1 + 4) = 7963`

`x xx 100 = 7963`

`=> x = 79,63`.

\(x\times\left(95+1+4\right)=7963\)

\(100\times x=7963\)

\(x=79,63\)

\(=>x\left(95+1+4\right)=7963\)

\(x=\dfrac{7963}{95+1+4}=\dfrac{7963}{100}=79,63\)