Câu 1 : x²-y²+2yz-z²=-(y²-2yz+z²-x²)                    Câu 2: x²-2xy+y²-xz+yz=(x²-2xy+y²)-xz+yz

                                 =-(y-z)² -x²                                                                   =(x-y)²-z(x-y)

                                        =-(y-z-x)(y-z+x)                                                            =(x-y)(x-y-z)

2.|3|.x-1+1=5 
6x=5
x=5/6

\(a.2^6.\left(x-2\right)=104\)

\(x-2=104:2^6\)

\(x-2=1,652\)

\(x=1,625+2\)

\(x=3,625\)

\(b.2\times4^{x+1}=128\)

\(4^{x+1}=128:2\)

\(4^{x+1}=64\)

\(4^{x+1}=4^3\)

\(\Rightarrow x+1=3\)

\(x=3-1\)

\(\Leftrightarrow x=3\)

\(c.227-5\left(x+8\right)=3^6:3^3\)

\(227-5\left(x+8\right)=3^3\)

\(227-5\left(x+8\right)=27\)

\(5\left(x+8\right)=227-27\)

\(5\left(x+8\right)=200\)

\(x+8=200:5\)

\(x+8=40\)

\(x=40-8\)

\(x=32\)

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thx bn

x² - z² + y² - 2xy

= (x² - 2xy + y² )- z²

= (x-y)² - z²

= (x-y-z)(x-y+z) 

(7*x-11)^3 = 2^5 * 5^2 +200

(7*x-11)^3 = 32*25+200

(7*x-11)^3=800+200

(7*x-11)^3=1000

=>(7*x-11)^3=(1000)^3

7*x-11=1000

7x=1000+11

7x=1011

x=1011/7

(7.x-11)^3=2^5.5^2+200

(7.x-11)^3=32.25+200

(7.x-11)^3=800+200

(7.x-11)^3=1000

(7.x-11)^3=10^3

7x-11=10

7x=10+11

7x=21

x=21/7

x=3

(7.x-11)\(^{ }\)