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= (-3/17+ -32/17)+(2/15+15/15+1)
=-2+2
=0

a ) 27 51 59 − 7 51 59 − 1 3 = 27 51 59 − 7 51 59 + 1 3 = 20 1 3

b ) 17 29 31 − 3 7 8 − 2 28 31 − 4 . = 17 29 31 − 2 28 31 − 3 7 8 + 4 = 15 1 31 + 1 8 = 15 39 248 .

a )   5 4 9 − 9 7 12 − 4 5 9 = 5 4 9 + 4 5 9 − 9 7 12 = 10 − 9 7 12 = 5 12 .

b ) 8 1 3 + 7 , 8 + 5 2 3 − 1 , 8. = 8 1 3 + 5 2 3 + 7 , 8 − 1 , 8 = 14 + 6 = 20

Đề khó nhìn quá bạn ơi!

Lời giải:

$25\frac{2}{13}-(\frac{15}{17}+15\frac{2}{13)$

$=25+\frac{2}{13}-\frac{15}{17}-15-\frac{2}{13}$

$=(25-15)+(\frac{2}{13}-\frac{2}{13})-\frac{15}{17}$

$=10-\frac{15}{17}=\frac{155}{17}$

`25 2/13 -(15/17 + 15 2/13)`

`= 25 2/13 - 15/17 - 15 2/13`

`=(25 2/13 - 15 2/13) - 15/17`

`= 10 2/13 -15/17`

`= 132/13 - 15/17`

`=2049/221`

ta có : \(\frac{4^{17}+64}{4^{16}+16}=\frac{2^{34}+2^6}{2^{32}+2^4}=\frac{2^6\left(2^{28}+1\right)}{2^4\left(2^{28}+1\right)}=2^2=4\)

Ta có: \(\frac{4^{17}+64}{4^{16}+16}\) = \(\frac{2^{34}+2^6}{2^{32}+2^4}\) = \(\frac{2^6\left(2^{28}+1\right)}{2^4\left(2^{28}+1\right)}\) = \(\frac{2^6}{2^4}\) = \(\frac{64}{16}\) = 4

a) \(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\)

\(=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}\) (dấu chấm là dấu nhân)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\)

\(=1-\frac{1}{7}\)

\(=\frac{6}{7}\)

b) \(\frac{19}{13}+\frac{14}{6}+\frac{1}{9}+\frac{4}{6}+\frac{7}{13}+\frac{17}{9}\)

\(=\left(\frac{19}{13}+\frac{7}{13}\right)+\left(\frac{14}{6}+\frac{4}{6}\right)+\left(\frac{1}{9}+\frac{17}{9}\right)\)

= 2 + 3 + 2

= 7

a) A = \(9\frac{3}{8}-\left(2\frac{3}{5}+2\frac{3}{8}\right)=9\frac{3}{8}-2\frac{3}{5}-2\frac{3}{8}=\left(9\frac{3}{8}-2\frac{3}{8}\right)-2\frac{3}{5}=7-\frac{13}{5}=\frac{22}{5}\)

b) B = \(\left(15\frac{3}{5}+5\frac{3}{4}\right)-8\frac{3}{5}=15\frac{3}{5}+5\frac{3}{4}-8\frac{3}{5}=\left(15\frac{3}{5}-8\frac{3}{5}\right)+5\frac{3}{4}=7+\frac{23}{4}=\frac{51}{4}\)

c) C = \(17\frac{1}{4}-\left(2\frac{3}{7}+7\frac{1}{4}\right)=17\frac{1}{4}-2\frac{3}{7}-7\frac{1}{4}=\left(17\frac{1}{4}-7\frac{1}{4}\right)-2\frac{3}{7}=10-\frac{17}{7}=\frac{53}{7}\)

d) D = \(\left(11\frac{5}{17}+3\frac{5}{7}\right)-4\frac{5}{17}=11\frac{5}{17}+3\frac{5}{7}-4\frac{5}{17}=\left(11\frac{5}{17}-4\frac{5}{17}\right)+3\frac{5}{7}=7+\frac{26}{7}=\frac{75}{7}\)