12/13

=3/1.4  + 3/4.7 + 3/7.10 + 3/13.10

=1/1 - 1/4 + 1/4 + 1/7 + 1/7 + 1/10 + 1/10 -  1/13

=8+4/13

=12/13

= \(\dfrac{3}{1.4}+\dfrac{3}{4.7}+\dfrac{3}{7.10}+\dfrac{3}{10.13}\) 

= \(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}=1-\dfrac{1}{13}=\dfrac{12}{13}\)

a) 2/9 - (1/20 + 2/9)

= 2/9 - 1/20 - 2/9

= (2/9 - 2/9) - 1/20

= 0 - 1/20

= -1/20

b) -3/14 + 2/13 + (-25/14) + (-15/13)

= (-3/14 - 25/14) + (2/13 - 15/13)

= -2 - 1

= -3

c) -3/11 + 11/8 - 3/8 + (-8/11)

= (-3/11 - 8/11) + (11/8 - 3/8)

= -1 + 1

= 0

d) 3/8 + (-1/4) - (7/12 - 1/6)

= 1/8 - 5/12

= -7/24

e) (1/3 + 12/67 + 13/41) - (79/67 - 28/41)

= 1/3 + 12/67 + 13/41 - 79/67 + 28/41

= 1/3 + (12/67 - 79/67) + (13/41 + 28/41)

= 1/3 - 1 + 1

= 1/3

Ta có: 
               \(\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+\frac{3}{130}+\frac{3}{208}\)
\(=\frac{3}{1\times4}+\frac{3}{4\times7}+\frac{3}{7\times10}+\frac{3}{10\times13}+\frac{3}{13\times16}\)
 \(=\frac{4-1}{1\times4}+\frac{7-4}{4\times7}+\frac{10-7}{7\times10}+\frac{13-10}{10\times13}+\frac{16-13}{13\times16}\)  \(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+\frac{1}{13}-\frac{1}{16}\)
 \(=1-\frac{1}{16}\)
 \(=\frac{15}{16}\)
 Chắc chắn đúng nhé !

bn hỏi vào đúng những ngày tết lk  

\(\dfrac{3}{4}+\dfrac{3}{28}+\dfrac{3}{70}+\dfrac{3}{130}+\dfrac{3}{208}+\dfrac{3}{304}\\ =\dfrac{3}{1.4}+\dfrac{3}{4.7}+\dfrac{3}{7.10}+\dfrac{3}{10.13}+\dfrac{3}{13.16}+\dfrac{3}{16.19}\\ =1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{19}\\ =1-\dfrac{1}{19}=\dfrac{18}{19}\)

\(\dfrac{3}{4}+\dfrac{3}{28}+\dfrac{3}{70}+\dfrac{3}{130}+\dfrac{3}{208}+\dfrac{3}{304}\)

\(=\dfrac{3}{1\times4}+\dfrac{3}{4\times7}+\dfrac{3}{7\times10}+\dfrac{3}{10\times13}+\dfrac{3}{13\times16}+\dfrac{3}{16\times19}\)

\(=1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{19}\)

\(=1-\dfrac{1}{19}\)

=\(\dfrac{18}{19}\)

1) \(35.18-5.7.28\)

\(=35.18-35.28\)

\(=35.\left(18-28\right)\)

\(=35.\left(-10\right)\)

\(=-350\)

2) \(45-5.\left(12+9\right)\)

\(=45-60-45\)

\(=\left(45-45\right)-60\)

\(=0-60\)

\(=-60\)

3) \(24.\left(16-5\right)-16.\left(24-5\right)\)

\(=\left(384-120\right)-\left(384-120\right)\)

\(=264-264\)

\(=0\)

4) \(13.\left(23+22\right)-3.\left(17+28\right)\)

\(=13.45-3.45\)

\(=\left(13-3\right).45\)

\(=10.45\)

\(=450\)

tk ủng hộ nha!!!!!!!!1

1/ 35 . 18 - 5 . 7 . 28

= 35 . 18 - 35 . 28

= 35 . (18 - 28)

= 35 . (-10)

= -350

2/ 45 - 5 . (12 + 9)

= 5 . 9 - 5 . 12 + 5 . 9

= 5 . (9 - 12 + 9)

= 5 . 6

= 30

3/ 24 . (16 - 5) - 16 . (24 - 5)

= 24 . 16 - 24 . 5 - 16 . 24 - 16 . 5

= (24 . 16 - 16 . 24) - (24 . 5 - 16 . 5)

= 0 - [5 . (24 - 16)]

= 0 - [5 . 8]

= 0 - 40

= -40

4/ 13 . (23 + 22) - 3 . (17 + 28)

= 13 . 45 - 3 . 45

= 45 . (13 - 3)

= 45 . 10

= 450

Xin lỗi, cho mk sửa lại ý 2, các ý còn lại đúng rùi đó!

2/ 45 - 5 . (12 + 9)

= 5 . 9 - 5 . 12 - 5 . 9

= -(5 . 12)

= -60

\(\frac{3}{4}+\frac{3}{28}+\frac{3}{70}+\frac{3}{130}+....+\frac{3}{304}.\)

\(=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+.....+\frac{3}{16.19}\)

\(=\frac{4-1}{1.4}+\frac{7-4}{4.7}+\frac{10-7}{7.10}+\frac{13-10}{10.13}+.....+\frac{19-16}{16.19}\)

\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+....+\frac{1}{16}-\frac{1}{19}\)

\(=1-\frac{1}{19}=\frac{18}{19}\)

3/4+3/28+3/70+3/130+...+3/304

= 3 /1.4 + 3/4.7 + 3/7.10 + 3/10.13 +....+ 3 /16.19

= 1 -1/4 + 1/4 - 1/7 + 1/7 - 1/10 + 1/10 - 1/13 + ...+1/16 - 1/19

= 1 - 1/19

=18/19

3/4+3/28+3/70+3/130+...+3/304

= 3/1.4 + 3/4.7 + 3/7.10 + 3/10.13 + ... + 3/16.19

= 1 - 1/4 + 1/4 - 1/7 + 1/7 - 1/0 + 1/10 - 1/13 + ... + 1/16 - 1/19

= 1 - 1/19

= 18/19