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a, a+8

b, b+45

= (2√2 - 3√2 + 10)√2 - √5

= 2.(√2)2 - 3.(√2)2 + √10.√2 - √5

= 4 - 6 + √20 - √5 = -2 + 2√5 - √5

= -2 + √5

= 0,2.10.√3 + 2|√3 - √5|

s

= 2√3 + 2(√5 - √3)

= 2√3 + 2√5 - 2√3 = 2√5

Bạn nên gõ đề bằng công thức toán (biểu tượng $\sum$ góc trái khung soạn thảo) để mọi người hiểu đề và hỗ trợ bạn tốt hơn nhé.

Đặt A

Rút gọn: (3 + 1)(3^2 + 1)(3^4 + 1)(3^8 + 1)(3^16 + 1)(3^32 + 1)
A=(3 + 1)(3^2 + 1)(3^4 + 1)(3^8 + 1)(3^16 + 1)(3^32 + 1)
2A=2(3 + 1)(3^2 + 1)(3^4 + 1)(3^8 + 1)(3^16 + 1)(3^32 + 1)
2A=(3-1)(3 + 1)(3^2 + 1)(3^4 + 1)(3^8 + 1)(3^16 + 1)(3^32 + 1)
2A=(3^2-1)(3^2 + 1)(3^4 + 1)(3^8 + 1)(3^16 + 1)(3^32 + 1)
2A=(3^4-1)(3^4 + 1)(3^8 + 1)(3^16 + 1)(3^32 + 1)
2A=(3^8-1)(3^8 + 1)(3^16 + 1)(3^32 + 1)
2A=(3^16-1)(3^16 + 1)(3^32 + 1)
2A=(3^32 - 1)(3^32 + 1)
2A=3^64-1
=>A=(3^64-1) /2

Lời giải :

\(\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)\)

\(=\frac{1}{2}\cdot\left(3-1\right)\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)\)

\(=\frac{1}{2}\cdot\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)\)

\(=\frac{1}{2}\cdot\left(3^4-1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)\)

\(=\frac{1}{2}\cdot\left(3^8-1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)\)

\(=\frac{1}{2}\cdot\left(3^{16}-1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)\)

\(=\frac{1}{2}\cdot\left(3^{32}-1\right)\left(3^{32}+1\right)\)

\(=\frac{1}{2}\cdot\left(3^{64}-1\right)\)

\(=\frac{3^{64}-1}{2}\)

1 tính giá trị biểu thức 

a) Cho x-y=7.Tính giá trị của biểu thức A=x(x+2)+y(y+2)-2xy+37

b) cho x+y=10 và x²+y²=10.Tính x³+y³

giúp mình bài này nữa

\(A=\frac{8.4.125.25+96524+476}{10.125.4.25.8}\)

\(A=\frac{1000.100+96524+476}{10.1000.100}\)

\(A=\frac{100000+96524+476}{1000000}\)

\(A=\frac{100000+97000}{1000000}=\frac{197000}{1000000}=\frac{197}{1000}\)

\(A=0,197\)

A = 100000 + 96524 + 4760000

A = 4956524

ý mình là rút gọn phân số này đi và ko cần tính a

\(A=3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)\)

\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)\)

\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)\)

\(=\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)\)

\(=\left(2^{16}-1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)\)

\(=\left(2^{32}-1\right)\left(2^{32}+1\right)\)

\(=2^{64}-1\)

A = 3( 2² + 1 )( 2⁴ + 1 )( 2⁸ + 1 )( 2¹⁶ + 1 )( 2³² + 1 )

= ( 2² - 1 )( 2² + 1 )( 2⁴ + 1 )( 2⁸ + 1 )( 2¹⁶ + 1 )( 2³² + 1 )

= ( 2⁴ - 1 )( 2⁴ + 1 )( 2⁸ + 1 )( 2¹⁶ + 1 )( 2³² + 1 )

= ( 2⁸ - 1 )( 2⁸ + 1 )( 2¹⁶ + 1 )( 2³² + 1 )

= ( 2¹⁶ - 1 )( 2¹⁶ + 1 )( 2³² + 1 )

= ( 2³² - 1 )( 2³² + 1 )

= 2⁶⁴ - 1

thanks 2 bạn

goi y nha A=1/2.(3^2-1)(3^2+1)....(3^32+1)

a.\(A=\dfrac{x^2-4x+4}{x^3-2x^2-\left(4x-8\right)}=\dfrac{\left(x-2\right)^2}{x^2\left(x-2\right)-4\left(x-2\right)}=\dfrac{\left(x-2\right)^2}{\left(x^2-4\right)\left(x-2\right)}=\dfrac{x-2}{\left(x-2\right)\left(x+2\right)}=\dfrac{1}{x+2}\)

\(A=\dfrac{\left(x-2\right)^2}{x^2\left(x-2\right)-4\left(x-2\right)}\left(x\ne\pm2\right)\\ A=\dfrac{\left(x-2\right)^2}{\left(x-2\right)^2\left(x+2\right)}=\dfrac{1}{x+2}\\ B=\dfrac{x+2-x+\sqrt{x}-1}{\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}\cdot\dfrac{4\sqrt{x}}{3}\left(x>0\right)\\ B=\dfrac{4\sqrt{x}\left(\sqrt{x}+1\right)}{3\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)}=\dfrac{4\sqrt{x}}{3\left(x-\sqrt{x}+1\right)}\)