\(8{{\rm{x}}^3} - 36{{\rm{x}}^2}y + 54{\rm{x}}{y^2} - 27{y^3} = {\left( {2{\rm{x}}} \right)^3} - 3.\left( {2{\rm{x}}} \right).3y + 3.2{\rm{x}}.{\left( {3y} \right)^2} - {\left( {3y} \right)^3} = {\left( {2{\rm{x}} - 3y} \right)^3}\)

(77 x 54 - 54 x 75): 54 + 720 : 36 x 2

=[54*(77-75)]:54+720:36*2

=[54*2]:54+20*2

=[54:54]*2+40

=2+40

=42

=108/54+20*2

=2+40

=42

(77 x 54 - 54 x 75): 54 + 720 : 36 x 2

=[54*(77-75)]:54+720:36*2

=[54*2]:54+20*2

=[54:54]*2+40

=2+40

=42

Đề bài lạ thế!

\(A=-\frac{8}{5}x^3+\frac{36}{5}x^2y-\frac{54}{5}xy^2+\frac{27}{5}y^3\)

\(=-\frac{1}{5}\left(8x^3-36x^2y+54xy^2-27y^3\right)\)

=\(-\frac{1}{5}\left(\left(2x\right)^3-3.\left(2x\right)^2.3y+3.2x.\left(3y\right)^2-\left(3y\right)^3\right)\)

\(=-\frac{1}{5}\left(2x-3y\right)^3=-\frac{1}{5}.4^3=-\frac{64}{5}\)

\(\begin{array}{l}8{x^3} - 36{x^2}y + 54x{y^2} - 27{y^3}\\ = {\left( {2x} \right)^3} - 3.{\left( {2x} \right)^2}.3y + 3.\left( {2x} \right).{\left( {3y} \right)^2} - {\left( {3y} \right)^3}\\ = {\left( {2x - 3y} \right)^3}\end{array}\)

a)

b)

2 x 31 x 12+ 4 x 6 x 42 + 8 x 3 x 27 = 24 x 31 + 24 x 42 + 24 x 27 = 24 x (27 + 31 + 42) = 24 x 100 = 2400

b) 36 x 28 + 36 x 82 + 64 x 69 + 64 x 41 = 36 x (28 + 82)  + 64 x (69 + 41) = 36 x 110 + 64 x 110 = 110 x (64 + 36) = 110 x 100 = 11000

a)      \(27 + 54x + 36{x^2} + 8{x^3} = {3^3} + {3.3^2}.2x + 3.3.{\left( {2x} \right)^2} + {\left( {2x} \right)^3} = {\left( {3 + 2x} \right)^3}\)

b)      \(64{x^3} - 144{x^2}y + 108x{y^2} - 27{y^3} = {\left( {4x} \right)^3} - 3.{\left( {4x} \right)^2}.3y + 3.4x.{\left( {3y} \right)^2} - {\left( {3y} \right)^3} = {\left( {4x - 3y} \right)^3}\)

Lời giải:

a. < 

b. > 

c. <

\(a,=\left(x+4\right)^2\\ b,=\left(x-6\right)^2\\ c,=-\left(4x^2-4x+1\right)=-\left(2x-1\right)^2\\ d,=\left(x-1\right)^3\)