1+2+2^2+2^3+......+2^98. hay so sanh S voi 5*2^98
giup voiiiii dang hoc online!!!!!!
S=2/3+2/15+2/35+2/63+2/99+...+2/9603 hay so sanh voi 1
Cho S=1+3^2+3^4+3^6+.......+3^98+3^100.
So sanh 8S+1 voi 2^152
Tim so du cua S khi chia cho 10.
1) Voi A,B la cac so tuy y , hay tinh : (a+b)(a2 - ab + b2)
2) so sanh ket qua vua tinh duoc voi a3 +b3 .
Nhanh nhanh nha may ban oi!Dang can gap
1: \(\left(a+b\right)\left(a^2-ab+b^2\right)\)
\(=a^3-a^2b+ab^2+a^2b-ab^2+b^3\)
\(=a^3+b^3\)
2: \(a^3+b^3=\left(a+b\right)\left(a^2-ab+b^2\right)\)
S=1+2+22+23+...+298+299;
T=2100:2
Hay so sanh S va T [ khong tinh ra ket qua ]
a. So sanh 2 phan so:A= 2015/2016+2016/2017+2017/2018 va B = 2015+2016+2017/2016+2017+2018
b.1/2.4+1/4.6+........+1/(2x-2).2x = 1/8
c.Cho A = 1/4+1/9+1/16+...+1/81+1/100 . Chung minh rang : A > 65/132
d.Cho B = 12/(2 . 4 ) ^ 2 + 20/ (4 . 6) ^2 + ...........+ 388/ ( 96 . 98 ) ^ 2 + 396/ ( 98 . 100 ) ^2 .Hay so sanh B voi 1 /4
Cho S= 1/5+2/52+3/53+.....+2015/52015. so sanh voi 1/3
\(5S=1+\frac{2}{5}+\frac{3}{5^2}+...+\frac{2015}{5^{2014}}\Rightarrow4S=1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{2014}}-\frac{2015}{5^{2015}}\)
Đặt B = \(1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{2014}}\)
=> 5B = \(5+1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{2013}}\)
=> 4B = \(5-\frac{1}{5^{2014}}
so sanh A va B voi 0
A = 1. ( - 2 ) . 3 . ( - 4 ) ..... . 99 . ( -100 )
B = 1 . ( - 2 ) . 3 . ( - 4 ) . ... . (-98) . 99
A có 50 thừa số âm
=> A > 0
b) CÓ 49 thừa số âm
=> B < 0
A có 50 thừa số âm
=> A > 0
B có 49 thừa số âm
=> B < 0
tick nha
Khong lam phep tinh hay so sanh:
a.[-1]*[-2]*[-3]*...*[-2009] voi 0
b.[-1]*[-2]*[-3]*...*[-10] voi 1*2*3*...*9*10
Cho S=1+2+2^2+2^3+.....+2^9
So sanh S voi 5.2^8
S = 1 + 2 + 2 ^ 2 + 2 ^ 3 + ... + 2 ^ 9
2S = 2 + 2 ^ 2 + 2 ^ 3 + 2 ^ 4 + .... + 2 ^ 10
2S - S = ( 2 + 2 ^ 2 + 2 ^ 3 + 2 ^ 4 + .... + 2 ^ 10 )
- ( 1 + 2 + 2 ^ 2 + 2 ^ 3 + ... + 2 ^ 9 )
S = 2 ^ 10 - 1
S = 2 ^ 8 . 2 ^ 2 - 1
S = 2 ^ 8 . 4 - 1
S < 2 ^ 8 . 1 < 5 . 2 ^ 8
Vậy S < 5 . 2 ^ 8