1+(1+2)+(1+2+3)+(1+2+3+4)+...+(1+2+3+4+...+2012)
1x2012+2x2012+3x2010+....+2012x1
tinh gia tri bieu thuc tren.(giai giup minh voi,dang voi)
Tinh gia tri cua bieu thuc :
a) A= 5a^3 b^4 voi a = -1, b = 1
b) B = 9a^5 b^2 voi a = -1, b = 2
Giup minh voi minh dang can cuc gap.
Gia tri bieu thuc [3/7 + 2/7] - 1/5 = ............
A 15/35 B 18/35 C 15/7 D 4/9
GIUP MINH VOI MINH DANG CAN GAP
Tinh gia tri bieu thuc
A=5a^3b^8 voi a=-1, b=1
B=-9a^4b^2 voi a=-1, b=2
C=ax+ay+bx+by biet a+b=-3, x+y=17
Minh dang can gap lam cac ban giup minh voi
Thay a = -1 , b=1 vào biểu thức A
=> A = 5.(-1)^3.1^8 = - 5
Thay a = -1 , b= 2 vào biểu thức B
=>B = -9.(-1)^4 . 2^2 = - 36
Ta có :
C = ax + ay + bx + by = a(x+y) + b(x+y) = (x+y)(a+b)
Thay a+b = - 3 , x+y = 17 vào biểu thức C
C = ( -3)(17) = -51
bai2: tinh gia tri cua bieu thuc: 5/6+1/3*2 bang bao nhieu
giup minh voi
`5/6 + 1/3 xx 2`
`= 5/6 + 2/3`
`= 5/6 + 4/6`
`=9/6`
`=3/2`
Tinh gia tri bieu thuc:
1-1/2-1/4-1/8-1/16-1/32=
minh dang gap
nho ket ban voi minh nhe
\(1-\frac{1}{2}-\frac{1}{4}-\frac{1}{8}-\frac{1}{16}-\frac{1}{32}\)
=> 1 - \(\frac{1}{32}\)
= \(\frac{32}{32}-\frac{1}{32}\)
= \(\frac{31}{32}\)
=\(1-\frac{1}{2}-\frac{1}{4}-\frac{1}{8}-\frac{1}{16}-\frac{1}{32}\)
=\(1-\left(\frac{1.16}{2.16}\right)-\left(\frac{1.8}{4.8}\right)-\left(\frac{1.4}{8.4}\right)\left(\frac{1.2}{16.2}\right)-\frac{1}{32}\)
=\(1-\frac{16}{32}-\frac{8}{32}-\frac{4}{32}-\frac{2}{32}-\frac{1}{32}\)
=\(1-\frac{1}{32}\)
=\(\frac{31}{32}\)
cac ban con cach giai nao khac khong
tinh gia tri bieu thuc
( 3/15+1/4+7/20 ) * 17 /9
tat ca tren
5 va 1/3+2/5
giúp gium minh voi nhe
\(\frac{\left(\frac{3}{15}+\frac{1}{4}+\frac{7}{20}\right).\frac{17}{9}}{5\frac{1}{3}+\frac{2}{5}}=\frac{\left(\frac{4+5+7}{20}\right).\frac{17}{9}}{\frac{16}{3}+\frac{2}{5}}\)
= \(\frac{\frac{4.17}{5.9}}{\frac{86}{15}}=\frac{68}{45}:\frac{86}{15}=\frac{34}{129}\)
Tíc nhé! :")
tinh gia tri bieu thuc:
m=1/1+2+1/1+2+3+1/1+2+3+4+1/1+2+3+4+5=....
Giúp mình voi minh can gap lam cac ban oi
1+2+1+2+3+1+2+3+4+1+2+3+4+5
=(1+2)x4+3x3+4x2+5
=3x4+9+8+5
=12+9+8+5
=34
Cho bieu thuc:P=\(\dfrac{\left(a+3\right)^2}{a^2+3a}\times\left(1-\dfrac{6a-18}{a^2-9}\right)\)voi a ≠0;a≠ +-3
a)rut gon bieu thuc P
b)tim gia tri cua a de P= -2
c)tim cac gia tri nguyen cua a de bieu thuc P co gia tri nguyen
mng giup minh voi mai thi rui!
a: \(P=\dfrac{a+3}{a}\cdot\dfrac{a^2-9-6a+18}{\left(a-3\right)\left(a+3\right)}\)
\(=\dfrac{\left(a-3\right)^2}{a\left(a-3\right)}=\dfrac{a-3}{a}\)
b: Để P=-2 thì -2a=a-3
=>-3a=-3
=>a=1
c: Để P nguyên thì a-3 chia hết cho a
=>-3 chia hết cho a
mà a<>0; a<>3; a<>-3
nên \(a\in\left\{1;-1\right\}\)
giup minh voi cam on cac ban . cho x+y=3 .tinh gia tri bieu thuc A= x^2+2xy+y^2-4x-4y+1
\(A=x^2+2xy+y^2-4x-4y+1\)
\(A=\left(x+y\right)^2-4\left(x+y\right)+1\)
\(A=3^2-4.3+1\)
\(A=-2\)
\(x^2+2xy+y^2-4x-4y+\)\(1\)
\(=\left(x^2+2xy+y^2\right)-\left(4x+4y\right)+1\)
\(=\left(x+y\right)^2-4\left(x+y\right)+1\)
Thay x+y = 1, ta có:
\(=3^2-4.3+1=-2\)
Bạn tham khảo cách 2 nhé !
\(x^2+2xy+y^2-4x-4y+1\)
\(=\left(x^2+y^2+1+2xy-2x-2y\right)-2x-2y\)
\(=\left[1-\left(x+y\right)\right]^2-2\left(x+y\right)\)
Thay x+y=1 ta có
\(=\left(1-3\right)^2-2.3\)
\(=-2\)