75 nhé bạn

TL :

   ( 15 x 15 ) : 2 x ( 15 x 15 ) : 2 x ( 15 x 15 ) : 2 + ( 0 + 1 + 2 + 2 + 3 + 45 ) x 0

= 0

=> vì : tất cả số nào nhân vs 0 đều = 0

_HT_

1423828.125 

        - ht -

1) \(2x^3-8x=0\)

\(\Leftrightarrow2x\left(x^2-4\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x^2-4=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x^2=4\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=\pm2\end{cases}}\)

Vậy \(x\in\left\{0;\pm2\right\}\)

2) \(2x\left(x-15\right)-4\left(x-15\right)=0\)

\(\Leftrightarrow\left(2x-4\right)\left(x-15\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}2x-4=0\\x-15=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=15\end{cases}}\)

Vậy \(x\in\left\{2;15\right\}\)

1 

\(2x^3-8x=0\)   

\(2x\left(x^2-4\right)=0\)   

\(\orbr{\begin{cases}2x=0\\x^2-4=0\end{cases}}\)   

\(\orbr{\begin{cases}x=0\\x^2=4\end{cases}}\)    

\(\orbr{\begin{cases}x=0\\x=\pm2\end{cases}}\)   

2 

\(2x\left(x-15\right)-4\left(x-15\right)=0\)    

\(\left(2x-4\right)\left(x-15\right)=0\)   

\(\orbr{\begin{cases}2x-4=0\\x-15=0\end{cases}}\)    

\(\orbr{\begin{cases}2x=4\\x=0+15\end{cases}}\)   

\(\orbr{\begin{cases}x=2\\x=15\end{cases}}\)

1) 2x³ - 8x = 0

<=> 2x( x² - 4 ) = 0

<=> 2x( x - 2 )( x + 2 ) = 0

<=> 2x = 0 hoặc x - 2 = 0 hoặc x + 2 = 0

<=> x = 0 hoặc x = ±2

2) 2x( x - 15 ) - 4( x - 15 ) = 0

<=> ( x - 15 )( 2x - 4 ) = 0

<=> x - 15 = 0 hoặc 2x - 4 = 0

<=> x = 15 hoặc x = 2

mà đây là môn toán mà

1) x (x-2016) + 2015 (2016-x) = 0

 x (x-2016) - 2015 (x- 2016) = 0

(x-2015)(x-2016) =0

\(\Rightarrow\orbr{\begin{cases}x-2015=0\\x-2016=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2015\\x=2016\end{cases}}}\)

Vậy x= 2015; 2016

2) -5x (x-15) + (15-x) = 0

-5x (x-15) - (x-15) =0

(-5x -1) (x-15) =0

\(\Rightarrow\orbr{\begin{cases}-5x-1=0\\x-15=0\end{cases}\Rightarrow\orbr{\begin{cases}-5x=1\\x=15\end{cases}\Rightarrow}\orbr{\begin{cases}x=-\frac{1}{5}\\x=15\end{cases}}}\)

Vậy x= -1/5; 15

3) 3x (3x-7) - (7-3x) =0

3x(3x-7) + (3x -7) =0

(3x+1) (3x-7) =0

\(\Rightarrow\orbr{\begin{cases}3x+1=0\\3x-7=0\end{cases}\Rightarrow\orbr{\begin{cases}3x=-1\\3x=7\end{cases}\Rightarrow}\orbr{\begin{cases}x=-\frac{1}{3}\\x=\frac{7}{3}\end{cases}}}\)

Vậy x= -1/3 ; 7/3

a: =>\(x\cdot\left(\sqrt{3}-1\right)=16\)

=>\(x=\dfrac{16}{\sqrt{3}-1}=8\left(\sqrt{3}+1\right)\)

b: =>(x-căn 15)^2=0

=>x-căn 15=0

=>x=căn 15

\(x+5.2-\left(32+15.3:9-15\right)=0\)

\(x+10-\left(32+5-15\right)=0\)

\(x+10-22=0\)

\(x+10=22\)

\(x=12\)

Vậy \(x=12\)

 ( dấu chấm là dấu nhân nhé em )

x + 5,2 - (32 + 15.3:9 - 15) =0

\(x+5.2-\left(32+15\times3\div9-15\right)=0\)

\(\Leftrightarrow x+5.2-32-15\times3\div9+15=0\)

\(\Leftrightarrow x+10-32-15\times\frac{1}{3}+15=0\)

\(\Leftrightarrow x-22-15\times\frac{1}{3}+15=0\)

\(\Leftrightarrow x-22-15\left(\frac{1}{3}-1\right)=0\)

\(\Leftrightarrow x-22-15.\frac{-2}{3}=0\)

\(\Leftrightarrow x-22+10=0\)

\(\Leftrightarrow x-12=0\)

\(\Leftrightarrow x=12\)

Dễ mak 

nhưng mik nhìn đề thấy dài quá nên ko muốn làm 

hihi^_$

Trả lời :

k bình luận linh tinh nx

~HT~

`@` `\text {Ans}`

`\downarrow`

`c)`

`( 34 - 2x ) . ( 2x - 6 ) = 0`

`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

Vậy, `x \in {17; 3}`

`d)`

`( 2019 - x ) . ( 3x - 12 ) =0` `?`

`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)

Vậy, `x \in {2019; 4}`

`e) `

`57 . ( 9x - 27 ) = 0`

`=>`\(9x-27=0\div57\)

`=> 9x - 27 = 0`

`=> 9x = 27`

`=> x = 27 \div 9`

`=> x = 3`

Vậy, `x = 3`

`f)`

`25 + ( 15 - x ) = 30`

`=> 15 - x = 30 - 25`

`=> 15 - x = 5`

`=> x = 15 -5 `

`=> x = 10`

Vậy, `x = 10`

`g) `

`43 - ( 24 - x ) = 20`

`=> 24 - x = 43 - 20`

`=> 24 - x = 23`

`=> x = 24 - 23`

`=> x = 1`

Vậy, `x = 1`

`h) `

`2 . ( x - 5 ) - 17 = 25`

`=> 2 ( x - 5) = 25+17`

`=> 2 ( x - 5) = 42`

`=> x - 5 = 42 \div 2`

`=> x - 5 = 21`

`=> x = 21 + 5`

`=> x = 26`

Vậy, `x = 26`

`i)`

`3 . ( x + 7 ) - 15 = 27`

`=> 3(x + 7) = 27 + 15`

`=> 3(x + 7) = 42`

`=> x +7 = 42 \div 3`

`=> x + 7 = 14`

`=> x = 14 - 7`

`=> x = 7`

Vậy, `x = 7`

`j)`

`15 + 4 . ( x - 2 ) = 95`

`=> 4(x - 2) = 95 - 15`

`=> 4(x - 2) = 80`

`=> x - 2 = 80 \div 4`

`=> x - 2 = 20`

`=> x = 20 + 2`

`=> x = 22`

Vậy, `x = 22`

`k)`

`20 - ( x + 14 ) = 5`

`=> x + 14 = 20 - 5`

`=> x + 14 = 15`

`=> x = 15 - 14`

`=> x = 1`

Vậy, `x = 1`

`l) `

`14 + 3 . ( 5 - x ) = 27`

`=> 3(5 - x) = 27 - 14`

`=> 3(5 - x) = 13`

`=> 5 - x = 13 \div 3`

`=> 5 - x = 13/3`

`=> x = 5- 13/3`

`=> x = 2/3`

Vậy, `x = 2/3.`

`@` `\text {Kaizuu lv uuu}`

nhanh mik tick cho nha

a: x<5 thì 5-x>0

A=5x+5-x+5=4x+10

b: Khi x>=0 thì \(B=5x+10+3x=8x+10\)

Khi x<0 thì B=5x+10-3x=2x+10

d: Khi x>=3 thì \(D=x-3-3x+15=-2x+12\)

Khi x<3 thì D=3-x-3x+15=-4x+18