36

TICH NHE

Y x 5 + 2 + 4 + 6 + ..... + 18 = 270   

Y x 5 + ( 2 + 4 + 6 + ..... + 18 ) = 270

Y x 5 + ( ( 2 + 18 ) + ( 4 + 16 ) + ( 6 + 14 ) + ( 8 + 12 ) + 10 ) = 270

Y x 5 + ( 20 + 20 + 20 + 20 + 10 ) = 270

Y x 5 + ( 20 x 4 + 10 ) = 270

Y x 5 + 80 = 270

Y x 5 = 270 - 80

Y x 5 = 190

      Y = 190 : 5

      Y = 39  

Trước tiên ta tính tổng 2 + 4 + 6 + ...... + 18 

Số các số hạng là (18 - 2) : 2 + 1 = 9 (số)

Tổng là: 9 x (2 + 18) = 180

y x 5 + 180 = 270

y x 5 = 270 - 180 = 90

y = 90 : 5 = 18 

y x ( 5 + 2 + 4 + 6 + ... + 18 ) = 270

tìm tổng của ( 5 +) 2 + 4 + 6 + ... + 18

số số hạng : ( 18 - 2 ) : 2 + 1 = 9 

tổng : ( 18 + 2 ) x 9 : 2 = 90

= y x 90 = 270

  = 270 : 9

y = 30

Số số hạng là:

(18 - 2) : 2 + 1 = 9 (số)

Tổng là:

9 x ( 2 + 18) = 180

y x 5 +180 = 270

y x 5 = 270 - 180 = 90

y = 90 : 5 = 18

Vì vậy y bằng 18 nên 18 x 5 + 2 + 4 + 6 + ....... + 18 = 270

y.5+(2+4+6+...+18) = 270

        y.5+(18+2).9:2=270

                   y.5+90=270

                        y.5=180

                           y=36

Tuyệt vời bn trả lời đúng rùi đó

18.2

đúng luôn

18,2

Tik cho mk nha............cảm ơn

18,2 nha tick mik đi,mik đg cần gấp

\(\frac{270.450+135.505.2}{2+4+6+...+16+18}\)

\(=\frac{270.450+135.2.505}{2.\left(1+2+3+...+8+9\right)}\)

\(=\frac{270.450+270.505}{2.\left(1+9\right).9:2}\)

\(=\frac{270.\left(450+505\right)}{10.9}=\frac{270.955}{90}=3.955=2865\)

a: \(20-\left[30-\left(5-1\right)^2\right]\)

\(=20-\left[30-4^2\right]\)

\(=20-14=6\)

b: \(71+\dfrac{50}{5+3\left(57-6\cdot7\right)}\)

\(=71+\dfrac{50}{5+3\cdot\left(57-42\right)}\)

\(=71+\dfrac{50}{5+3\cdot15}=71+\dfrac{50}{50}=72\)

c: \(4\cdot\left\{270:\left[50-\left(2^5+45:5\right)\right]\right\}\)

\(=4\cdot\left\{270:\left[50-32-9\right]\right\}\)

\(=4\cdot\left\{\dfrac{270}{50-41}\right\}=4\cdot\dfrac{270}{9}=4\cdot30=120\)

d: \(411-\left[\dfrac{\left(107+3\right)}{5}-2^2\right]\)

\(=411-\left[\dfrac{110}{5}-4\right]\)

=410-22+4

=410-18

=392

e: \(450-5\left[3^2\left(7^5:7^3-41\right)-12\right]+18\)

\(=450-5\left[9\cdot\left(7^2-41\right)-12\right]+18\)

\(=450-5\cdot\left[9\cdot8-12\right]+18\)

=468-5*60

=468-300

=168

f:

\(102-150:\left[18-2\cdot\left(10-8\right)^2\right]+1018^0\)

\(=102-150:\left[18-2\cdot4\right]+1\)

\(=103-\dfrac{150}{18-8}=103-15=88\)

1: =72/90+65/90=137/90

2: =24/56-77/56=-53/56

3: =-7/10+4/5=1/10

4: =15/100-4/100=11/100

5: =4/6-5/6=-1/6

6: =10/40-15/40-76/40=-81/40

7: =-9/10+7/18

=-81/90+35/90=-46/90=-23/45

8: =27/90-55/90=-28/90=-14/45

9: =36/60-50/60-35/60=-49/60

10: =-4/9+5/6-3/8

=-32/72+60/72-27/72

=1/72

\(1,\dfrac{4}{5}+\dfrac{13}{18}=\dfrac{72}{90}+\dfrac{65}{90}=\dfrac{137}{90}\)

\(2,\dfrac{3}{7}-\dfrac{11}{8}=\dfrac{24}{56}-\dfrac{77}{56}=\dfrac{-53}{56}\)

\(3,-\dfrac{7}{10}-\left(-\dfrac{4}{5}\right)=-\dfrac{7}{10}-\left(-\dfrac{8}{10}\right)=\dfrac{1}{10}\)

\(4,\dfrac{3}{20}-\dfrac{1}{25}=\dfrac{75}{500}-\dfrac{20}{500}=\dfrac{55}{500}=\dfrac{11}{100}\)

\(5,\dfrac{2}{3}-\dfrac{5}{6}=\dfrac{12}{18}-\dfrac{15}{18}=-\dfrac{3}{18}=-\dfrac{1}{6}\)

\(6,\dfrac{1}{4}+\left(-\dfrac{3}{8}\right)-\dfrac{19}{10}=\dfrac{8}{32}+\left(-\dfrac{12}{32}\right)-\dfrac{19}{10}=-\dfrac{4}{32}-\dfrac{19}{10}\)

\(=-\dfrac{1}{8}-\dfrac{19}{10}=-\dfrac{10}{80}-\dfrac{152}{80}=-\dfrac{162}{80}=-\dfrac{81}{40}\)

\(7,-\dfrac{9}{10}-\left(-\dfrac{7}{18}\right)=-\dfrac{162}{180}-\left(-\dfrac{70}{180}\right)=-\dfrac{92}{180}=-\dfrac{23}{45}\)

\(8,\dfrac{3}{10}-\dfrac{11}{18}=\dfrac{54}{180}-\dfrac{110}{180}=-\dfrac{56}{180}=-\dfrac{14}{45}\)

\(9,\dfrac{3}{5}-\dfrac{5}{6}+\left(-\dfrac{7}{12}\right)=\dfrac{18}{30}-\dfrac{25}{30}+\left(-\dfrac{7}{12}\right)=-\dfrac{7}{30}+\left(-\dfrac{7}{12}\right)\)

\(=-\dfrac{84}{360}+\left(-\dfrac{210}{360}\right)=-\dfrac{294}{360}=-\dfrac{49}{60}\)

\(10,-\dfrac{4}{9}-\dfrac{-5}{6}-\dfrac{3}{8}=-\dfrac{24}{54}-\dfrac{-45}{54}-\dfrac{3}{8}\)

\(=\dfrac{21}{54}-\dfrac{3}{8}=\dfrac{7}{18}-\dfrac{3}{8}=\dfrac{56}{144}-\dfrac{54}{144}=\dfrac{2}{144}=\dfrac{1}{72}\)

`@mt`