a,5xy+z-5x-yz=(5xy-5x)-(yz-z)=5x(y-1)-z(y-1)=(y-1)(5x-z)                                                                      b, y²(a-b)+b-a=y²(a-b)-a(a-b)=(y²-1)(a-b)=(y-1)(y+1)(a-b)

5 x² - 5xy+2x−2y = 2x ( x - y) + 2( x - y) = 2( x + 1)( x - y)

a) \(5x^2+5xy-x-y\)

\(=5x.\left(x+y\right)-\left(x+y\right)\)

\(=\left(x+y\right)\left(5x-1\right)\)

b) \(5x^2-10y+5y^2-20z^2\)

\(=5.\left(x^2-2y+y^2-4z^2\right)\)

Đề sai ở đâu đó.

c) \(4x^2-y^2+4x+1\)

\(=\left(4x+4x^2+1\right)-y^2\)

\(=\left(2x+1\right)^2-y^2\)

\(=\left(2x+y+1\right)\left(2x-y+1\right)\)

5x² - 5xy + 4y - 4x

= 5x ( x - y ) - 4 ( x - y )

= ( 5x - 4 ) ( x - y )

( x + y )³ + ( x - y )³

= 2x³ + 6xy²

= 2x ( x² + 3y² )

5 x^2 - 5xy + 4y - 4x 

= 5x ( x - y ) - 4 ( x - y ) 

= ( x - y ) ( 5x - 4 ) 

( x + y )^3 + ( x - y )^3 

= \(x^3+3x^2y+3xy^2+y^3+x^3-3x^2y+3xy^2-y^3\) 

= \(2x^3+6xy^2\) 

=\(2x\left(x^2+3y^2\right)\) 

\(5x^3-5xy^2+10xy-5x\)

\(=5x\left(x^2-y^2+2y-1\right)\)

\(=5x\left[x^2-y^2+y+y-1\right]\)

\(=5x\left[x^2-y\left(y-1\right)+\left(y-1\right)\right]\)

\(=5x\left[x^2-\left(y+1\right)\left(y-1\right)\right]\)

\(=5x\left[x^2-\left(y^2-1^2\right)\right]\)

\(=5x\left[\left(x-y\right)\left(x+y\right)+1\right]\)

Lâu k làm, sai thông cảm 

Answer:

\(5x^3-5xy^2+10xy-5x\)

\(=5x\left(x^2-y^2+2y-1\right)\)

\(=5x[x^2-\left(y^2-2y+1\right)]\)

\(=5x[x^2-\left(y-1\right)^2]\)

\(=5x\left(x-y+1\right)\left(x+y-1\right)\)

\(\left(x^2-2xy+y^2\right)+81\)

em.........

bó tay 

a, 5x^2 +5xy - x - y 

= 5x ( x+ y ) - (x + y)

= ( 5x - 1)(x + y)

b, 2x^2  + 3x - 5 

= 2x^2 - 2x + 5x - 5 

= 2x( x - 1) + 5( x - 1)

= ( 2x + 5 )(x- 1 )

c; 16x - 5x^2 - 3 

c, = - ( 5x^2 - 16x + 3 )

   = - ( 5x^2 - x - 15x + 3 )

= - [ x(5x - 1 ) - 3 (5x - 1) ]

= - ( x- 3)(5x -  1 )