[3.(x+2):7].4=120
[ 8 x - 120 ÷ 4 ] ×3^3=3^6
123-5 (x+4)=38
(3x- 2^4)×7^3=2×7^4
\(\left[8x-120:4\right]\times3^3=3^6.\)
\(8x-120:4=3^3\)
\(8x-30=27\)
\(8x=27+30\)
\(8x=57\)
\(x=19\)
123 - 5.(x + 4) = 38
123 - 5x - 20 = 38
-5x = 38 - 123 + 20
-5x = -65
x = -65 : -5
x = 13
Vậy x = 13
\(123-5\left(x+4\right)=38\)
\(5\left(x+4\right)=123-38\)
\(5\left(x+4\right)=85\)
\(\left(x+4\right)=17\)
\(x=17-4\)
\(x=13\)
\(\left(3x-2^4\right)\times7^3=2\times7^4\)
\(\left(3x-2^4\right)=2\times7^4:7^3\)
\(\left(3x-2^4\right)=2\times7\)
\(3x-2^4=14\)
\(3x-16=14\)
\(3x=30\)
\(x=30:3\)
\(x=10\)
[ 3 x ( x + 2 ) : 7 ] x 4 = 120
( 3 x ( x + 2 ) : 7 ) x 4 = 120
( 3 x ( x + 2 ) : 7 ) = 120 : 4
3 x ( x + 2 ) : 7 = 30
( x + 2 ) : 7 = 30 : 3
( x + 2 ) : 7 = 10
( x + 2 ) = 10 x 7
x + 2 = 70
x = 70 - 2
x = 68
[ 3 x ( x + 2 ) : 7 ] x 4 = 120
( x + 2 ) : 7 = 120 : 4 :3 = 10
x+ 2 = 10 x 7 = 7
x= 70 - 2 =68
[3×(x+2)÷7]×4=120
\(\left[3\cdot\left(x+2\right):7\right]\cdot4=120\)
\(\Rightarrow3\left(x+2\right):7=30\)
\(\Rightarrow3\left(x+2\right)=210\)
\(\Rightarrow x+2=70\)
\(\Rightarrow x=68\)
Vậy x=68
[ 3 . ( x + 2 ) : 7 ] . 4 = 120
3 . ( x + 2 ) : 7 = 30
3 . ( x + 2 ) = 210
x + 2 = 70
x = 68
Nhớ li ke mk nha
[3x(x+2):7] x 4 = 120
[3x(x+2):7] = 120 : 4
[3x(x+2):7] = 30
3 x (x+2) = 30 x 7
3 x (x+2) = 210
x+2 = 210 : 3
x+2 = 70
x = 70 - 2
x = 68
[3(x+2).7].4=120
[3(x + 2).7].4 = 120
3(x + 2).7 = 120 : 4
3(x + 2) = 30 : 7
x + 2 = \(\frac{30}{7}:3\)
x = \(\frac{10}{7}-2\)
x = \(\frac{5}{7}\)
\(\left[3\left(x+2\right).7\right].4=120\)
\(\Rightarrow3\left(x+2\right)=120:4:7=\frac{30}{7}\)
\(\Rightarrow x+2=\frac{30}{7}.\frac{1}{3}=\frac{10}{7}\)
\(\Rightarrow x=\frac{10}{7}-2=-\frac{4}{7}\)
[3(x+2).7].4=120
=>3(x+2).7 = 120:4=30
=>3(x+2) = 30:7=30/7
=>x+2=30/7:3=10/7
=>x=10/7-2=-4/7
275-(113+x)+63=158 ; [3.(x+2):7].4=120 help
275-(113+x)+63=158
275-(113+x)=95
113+x=175-95
113+x=80
x=80-113
x=33
[3(x+2):7]4=120
3(x+2):7=30
3(x+2)=210
x+2=70
x=68
[3×(x+2)÷7]×4 =120
Tìm x
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Phải bằng bao nhiêu chú
[3×(x+2)÷7]×4=120
Tìm x
[ 3 . ( x + 2 ) : 7 ] . 4 = 120
[ 3 . ( x + 2 ) : 7 ] = 120 : 4
[ 3 . ( x + 2 ) : 7 ] = 30
3 . ( x + 2 ) = 30 . 7
3 . ( x + 2 ) = 210
( x + 2 ) = 210 : 3
( x + 2 ) = 70
x = 70 - 2
x = 68
\(\left[3.\left(x+2\right):7\right].4=120\)
\(3.\left(x+2\right):7=480\)
\(3.\left(x+2\right)=480.7\)
\(3.\left(x+2\right)=3360\)
\(x+2=3360:3\)
\(x+2=1120\)
\(x=1120-2\)
\(x=1118\)
[ 3 x ( x + 2 ) : 7 ] x 4 = 120
[ 3 x ( x + 2 ) : 7 ] = 120 : 4
[ 3 x ( x + 2 ) : 7 ] = 30
[ 3 x ( x + 2 ) ] = 30 x 7
[ 3 x ( x + 2 ) ] = 210
[ ( x + 2 ) ] = 210 : 3
[ ( x + 2 ) ] = 70
x = 70 - 2
x= 68
[ 3 .( x + 2 ) : 7 ] . 4 = 120
\(\left[3.\left(x+2\right):7\right].4=120\)
\(\Leftrightarrow\left[3.\left(x+2\right):7\right]=30\)
\(\Leftrightarrow3.\left(x+2\right)=210\)
\(\Leftrightarrow\left(x+2\right)=70\)
\(\Leftrightarrow x=68\)
Vậy \(x=68\)
[3.(x+2):7]=120:4=30
3.(x+2)=30x7=210
x+2=210:3=7
x=7-2
x=5
vậy x =5
Mik cần gấp [3.(x+2):7].4=120
\(\Leftrightarrow3\left(x+2\right):7=30\)
=>3(x+2)=210
=>x+2=70
hay x=68
\(\left[3\cdot\left(x+2\right)\div7\right]\cdot4=120\)
\(3\cdot\left(x+2\right)\div7=120\div4\)
\(3\cdot\left(x+2\right)\div7=30\)
\(3\left(x+2\right)=30\cdot7\)
\(3\cdot\left(x+2\right)=210\)
x+2=210:3
x+2=70
x=68