(x : 4) – 476 = 388

x : 4 = 388 + 476

x : 4 = 864

x = 864 x 4

x = 3456

46+(88-4.x):4=65

(88-4.x):4=65-46

(88-4.x):4=19

88-4.x=19.4

88-4.x=76

4.x=88-76

4.x=12

x=12:4

x=3

912-(476-16.x):7=69

(476-16.x):7=912-69

(476-16.x):7=843

476-16.x=843.7

476-16.x=5901

16.x=476-5901

16.x=(-5425)

x=(-5425):16

x=(-339,0625)

li-ke cho mình nha mình đang cần li-ke

46 + ( 88 - 4x ) : 4 = 65

( 88 - 4x ) : 4= 65- 46

( 88 - 4x ) = 19

( 88 - 4x ) = 19x 4

88-4x = 76

4x = 88- 76

4x = 8

x = 8 : 4

x = 2

C 

C

476 x 476 + 523 x 476 + 476 = 476 x ( 476 + 523 + 1 ) = 476 x 1000 = 476000

\(=476\times476+523\times476+1\times476\)

\(=\left(476+523+1\right)\times476\)

\(=1000\times476\)

\(=476000\)

= 476 x 476 + 523 x 476 + 476 x 1

= 476 x (523 + 476 + 1 )

= 476 x 1000

= 476000

Đáp án C

x - 22x10:2 = 4960

x = 4960 + 110

x = 5070 

a, x-(2+4+6+.........+20)=4960

x-[(2+20):2.10)]=4960

x-110=4960

x=4960+110

x=5070

b,(3+5+7+............+1999)-x=315

[(3+1999):2.999]-x=315

999999-x=315

x=999999-315

x=999684

476 x 24 + 476 + 476 x 75

= 476 x ( 24 + 1 + 75)

= 476 x 100

= 47600

HT và $$$

476 x 24 + 476 + 476 x 75

= 476 x 24 + 476 x 1 + 476 x 75

= 476 x ( 27 + 45 + 1 )

= 476 x 100

= 47600

\(476.24+476+476.75\)

\(=476.\left(24+1+75\right)\)

\(=476.100=47600\)

\(A=\frac{8.4.125.25+96524+476}{10.125.4.25.8}\)

\(A=\frac{1000.100+96524+476}{10.1000.100}\)

\(A=\frac{100000+96524+476}{1000000}\)

\(A=\frac{100000+97000}{1000000}=\frac{197000}{1000000}=\frac{197}{1000}\)

\(A=0,197\)

A = 100000 + 96524 + 4760000

A = 4956524

ý mình là rút gọn phân số này đi và ko cần tính a

Các bước giải chi tiết 

a)  \(\dfrac{392-x}{32}\) + \(\dfrac{390-x}{34}\) + \(\dfrac{388-x}{36}\) = -3

⇔ \(\dfrac{392-x}{32}\)+1+\(\dfrac{390-x}{34}\)+1+\(\dfrac{388-x}{36}\)+1 = 0 

⇔\(\dfrac{424-x}{32}\)+\(\dfrac{424-x}{34}\)+\(\dfrac{424-x}{36}\)=0

⇔\(\left(424-x\right)\)\(\left(\dfrac{1}{32}+\dfrac{1}{34}+\dfrac{1}{36}\right)\)=0

⇔\(424-x\) = 0\(\left(\dfrac{1}{32}+\dfrac{1}{34}+\dfrac{1}{36}\ne\forall x\right)\)

⇔\(x=424\)

b)  \(\dfrac{x-3}{3}\)- \(x\) = \(5-\dfrac{x+1}{4}\)

⇔\(\dfrac{x-3-3x}{3}\) = 5 + \(\dfrac{-\left(x+1\right)}{4}\)

⇔\(\dfrac{-2x-3}{3}\) = 5 + \(\dfrac{-x-1}{4}\)

⇔\(\dfrac{-2x-3}{3}\) = \(\dfrac{20-x-1}{4}\)

⇔\(\dfrac{-2x-3}{3}\) = \(\dfrac{-x+19}{4}\)​​

⇔ \(4\left(-2x-3\right)\) = \(3\left(-x+19\right)\)

⇔\(-8x-12\) = \(-3x+57\)

⇔\(-8x\) = \(-3x+69\)

⇔\(-5x=69\)

⇔ \(x=-\dfrac{69}{5}\)

(392-x)/32+(390-x)/34+(388-x)/36=-3
=>392-x)/32 +1 + (390-x)/34 +1 +(388-x)/36 +1=0
=>(424-x)/32+(424-x)/34+(424-x)/36=0
=>424-x=0(vì 1/32+1/34+1/36 khác 0)
=>x=424