Tính:
34 + 2 + 3 = … | 56 – 4 + 6 = … | 86 – 6 + 4 = … |
64 + 3 – 5 = … | 78 – 3 – 3 = … | 52 + 0 – 2 = … |
Tính:
34 + 2 + 3 = … | 56 – 4 + 6 = … | 86 – 6 + 4 = … |
64 + 3 – 5 = … | 78 – 3 – 3 = … | 52 + 0 – 2 = … |
\(\frac{3}{34}+\frac{34}{34}\times\frac{3}{4}\div5=\)
\(\frac{23}{3}\times\frac{56}{6}+\frac{86}{78}=\)
\(\frac{3}{45}\div\frac{1}{4}=\)
\(\frac{5}{34}-\frac{3}{6}=\)
Các bạn giải giùm mình nhé!
Mình mới học lớp 3
\(\frac{3}{34}+\frac{34}{34}.\frac{3}{4}=\frac{3}{34}+1.\frac{3}{4}=\frac{3}{34}+\frac{3}{4}=\frac{57}{68}\)
\(\frac{23}{3}.\frac{56}{6}+\frac{86}{78}=\frac{23}{3}.\frac{28}{3}+\frac{43}{39}=\frac{644}{9}+\frac{28}{3}=\frac{728}{9}\)
\(\frac{3}{45}:\frac{1}{4}=\frac{1}{15}.4=\frac{4}{15}\)
\(\frac{5}{34}-\frac{3}{6}=\frac{5}{34}-\frac{1}{2}=\frac{3}{4}\)
Giúp mình với nha
Bài 3. Tính hợp lý :
1) 84 + 245 + 16 2) 467 + 238 + 533 + 762 + 3465 3) 1 + 3 + 5 + 7 + … + 199 4) 8. 4. 34. 125. 25 5) (44. 52. 60) : (11. 13. 15) 6) 129. 172 – 73. 129 + 129 7) 78. 31 + 78. 24 + 22. 72 + 78. 17 | 8) 48. 55 + 52. 167 – 52. 112 9) 3. 25. 8 + 4. 6. 37 + 2. 38. 12 10) (2100 – 42) : 21 11) (64 + 27 + 28 + 29) : 32 12) 86. 8585 – 85. 8686 13) 1 - 2 + 3 - 4 + 5 - 6 + … + 101 14*) 1 + 2 – 3 – 4 + 5 + 6 – 7 – 8 +…+ 413 + 414 |
1+2+3+4+5+6+7+8+9+0+1+2+3+4+5+6+7+8+9+9+8+7+6+5+4+3+2+1+1+34+4+6+7+8+97+6+4+3+32+4+57+7+8+8+6+65+4+3+3+46+7+8+7+64+3+3+5+68+8+6+3+3+5+78+8+6+54+5+7+8+852+3+5+89+8+5+45+7×9×9×9×9×9×9×9×9×9×9×9×8×8×7×9×9×7×7×87×7×8×7×7×8×7×7×8
Bài 1. Tính hợp lý
1) (–12) +6.(–3)
2) (36 -2020) + (2019 -136) – 27
3) (144 – 97) – (244 – 197)
4) (–24).13 – 24.( –3)
5) 54+55+56+57+58-(64+65+66+67+68)
6) 24(16 – 5) – 16(24 – 5)
7) 47.(23 + 50) – 23.(47 + 50)
8) (-31). 47 + (-31). 52 + (-31)
Bài 2: Tìm số nguyên x, biết:
1)-17-(2x-5)=-6
2) 10-2(4-3x)=-4
3)-12+3(-x+7)=-18
4)-45:[5.(-3-2x)]=3
5) x.(x+3)=0
6) (x-2).(x+4)=0
7) x.(x+1).(x-3)=0
Bài 1:
1) Ta có: \(\left(-12\right)+6\cdot\left(-3\right)\)
\(=-12-18\)
=-30
2) Ta có: \(\left(36-2020\right)+\left(2019-136\right)-27\)
\(=36-2020+2019-136-27\)
\(=1-100-27\)
\(=-126\)
3) Ta có: \(\left(144-97\right)-\left(244-197\right)\)
\(=144-97-244+197\)
\(=-100+100=0\)
4) Ta có: \(\left(-24\right)\cdot13-24\cdot\left(-3\right)\)
\(=-24\cdot13+24\cdot3\)
\(=24\cdot\left(-13+3\right)\)
\(=24\cdot\left(-10\right)=-240\)
5) Ta có: \(54+55+56+57+58-\left(64+65+66+67+68\right)\)
\(=54+55+56+57+58-64-65-66-67-68\)
\(=\left(54-64\right)+\left(55-65\right)+\left(56-66\right)+\left(57-67\right)+\left(58-68\right)\)
\(=\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)\)
=-50
6) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)
\(=24\cdot16-24\cdot5-16\cdot24+16\cdot5\)
\(=-24\cdot5+16\cdot5\)
\(=5\cdot\left(-24+16\right)\)
\(=-5\cdot8=-40\)
7) Ta có: \(47\cdot\left(23+50\right)-23\cdot\left(47+50\right)\)
\(=47\cdot23+47\cdot50-23\cdot47-23\cdot50\)
\(=47\cdot50-23\cdot50\)
\(=50\cdot\left(47-23\right)\)
\(=50\cdot24=1200\)
8) Ta có: \(\left(-31\right)\cdot47+\left(-31\right)\cdot52+\left(-31\right)\)
\(=-31\cdot\left(47+52+1\right)\)
\(=-31\cdot100=-3100\)
Bài 2:
1) Ta có: \(-17-\left(2x-5\right)=-6\)
\(\Leftrightarrow-17-2x+5+6=0\)
\(\Leftrightarrow-2x-6=0\)
\(\Leftrightarrow-2x=6\)
hay x=-3
Vậy: x=-3
2) Ta có: \(10-2\left(4-3x\right)=-4\)
\(\Leftrightarrow10-8+6x+4=0\)
\(\Leftrightarrow6x+6=0\)
\(\Leftrightarrow6x=-6\)
hay x=-1
Vậy: x=-1
3) Ta có: \(-12+3\left(-x+7\right)=-18\)
\(\Leftrightarrow-12-3x+21+18=0\)
\(\Leftrightarrow-3x+27=0\)
\(\Leftrightarrow-3x=-27\)
hay x=9
Vậy: x=9
4) Ta có: \(-45:\left[5\cdot\left(-3-2x\right)\right]=3\)
\(\Leftrightarrow5\cdot\left(-3-2x\right)=-15\)
\(\Leftrightarrow-2x-3=-3\)
\(\Leftrightarrow-2x=0\)
hay x=0
Vậy: x=0
5) Ta có: x(x+3)=0
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-3\right\}\)
6) Ta có: (x-2)(x+4)=0
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)
Vậy: \(x\in\left\{2;-4\right\}\)
7) Ta có: \(x\left(x+1\right)\left(x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\\x=3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-1;3\right\}\)
Bài 1:
1) Ta có: (−12)+6⋅(−3)(−12)+6⋅(−3)
=−12−18=−12−18
=-30
2) Ta có: (36−2020)+(2019−136)−27(36−2020)+(2019−136)−27
=36−2020+2019−136−27=36−2020+2019−136−27
=1−100−27=1−100−27
=−126
Tớ chcs cậu học thật giỏi nha !
1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9 * 10 * 11 * 12 * 13 * 14 * 15 * 16 * 17 * 18 * 19 * 20 * 21 * 22 * 23 * 24 * 25 * 26 * 27 * 28 * 29 * 30 * 31 * 32 * 33 * 34 * 35 * 36 * 37 * 38 * 39 * 40 * 41 * 42 * 43 * 44 * 45 * 46 * 47 * 48 * 49 * 50 * 51 * 52 * 53 * 54 * 55 * 56 * 57 * 58 * 59 * 60 * 61 * 62 * 63 * 64 * 65 * 66 * 67 * 68 * 69 * 70 * 71 * 72 * 73 * 74 * 75 * 76 * 77 * 78 * 79 * 80 * 81 * 82 * 83 * 84 * 85 * 86 * 87 * 88 * 89 * 90 * 91 * 92 * 93 * 94 * 95 * 96 * 97 * 98 * 99 * 100 bằng bao nhiêu?
Bài 2: Tính nhanh
a) 29 + 132 + 237 + 868 + 3
b) 35 . 34 + 35 . 86 + 65 . 75 + 65 . 5
c) 3 . 25 . 8 + 4 . 37 . 6 + 2 . 38 . 12
d) 12 . 53 + 53 . 172 – 53 . 84
Bài 3: Thực hiện phép tính (tính hợp lí nếu có thể)
a) 4 . 52 – 18 : 32
b) 32. 22 - 32 . 19
c) 24 . 5 - [131- (13 - 4)2]
d) 5871: [928 – ( 247 - 82) . 5] + 21750
Giúp mình với !!!
Bài 2: Tính nhanh
a) 29 + 132 + 237 + 868 + 3
= 29+(132+858)+(237+3)
=29+990+240
=1259
29+132+237+868+3
29+(132+868)+(237+3)
29+1000+240
29+(1000+240)
29+1240
1269
bài 2 :
a) 29 + 132 + 237 + 868 + 3
= 29 +(132 + 868)+(237 + 3)
= 29 + 1000 + 240
=1269
b) 35 . 34 + 35 . 86 + 65 . 75 + 65 . 5
= 35 .(34 + 86)+ 65 .(75 + 5)
= 35 . 120 + 65 . 80
= 4200 + 5200
= 9400
c) 3 . 25 . 8 + 4 . 37 . 6 + 2 . 38 .12
khum bít làm hehe
d) 12 . 53 + 53 . 172 - 53 . 84
= 53 . (12 + 172 - 84)
= 53 . 100
= 5300
Bài 3:
a) 4 . 52 - 18 : 32 hình như câu này sai đề
b) 32 . 22 - 32 . 19
= 32 . (22 - 19)
= 32 . 3
= 96
c) 24 . 5 - [131- (13 - 4)^2] = 24 . 5 - [131 - 9^2] = 24. 5 - [131 - 81] = 24 . 5 - 50 = 120 - 50 = 70 d) 5871: [928 – ( 247 - 82) . 5] + 21750 = 5871 : [928 - 165 . 5] + 21750 = 5871 : [928 - 825] + 21750 = 5871 : 103 + 21750 = 57 + 21750 = 218071+2+4+5+3+5+7+5+5+52+78+85+572+78+78+78+78+78+57-2578-78-8787+587-87+578-45+278-278-86-87-37-8-8-8+78-8-+78-82+78-86
10645 nha chúc bạn học tốt
1+2+3+4+5+6+7+7+8+9+10+11+12+13+14+45+15+16+17+18+19+20+21-56+56+48+52+78+84+54+2545+455+1454+1256-23+56+586=
1+2+3+4+....-56+56+48.......-23+56+586=6928
Đặt tính rồi tính:
a) 14 x 6 20 x 5 34 x 7 66 x 6
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b) 86 : 2 63 : 3 80 : 4 83 : 4
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