a) Đúng

b) Sai

c) Đúng

a) Đ

b) S

c) Đ

a. 96 : 8 : 2 = 6

96 : ( 8 x 2 ) = 6

96 : 8 : 2 = 96 : ( 8 x 2 )

b. 81 : 9 : 3 = 3

81 : ( 9 x 3 ) = 3

81 : 9 : 3 = 81 : ( 9x 3)

\(4\left(3-2x^2\right)-96:\left(-8\right)=112\)

=>\(4\left(3-2x^2\right)+12=112\)

=>\(4\left(3-2x^2\right)=100\)

=>\(3-2x^2=25\)

=>\(2x^2=-22\)

=>\(x^2=-11\)(vô lý)

Vậy: \(x\in\varnothing\)

Để giải phương trình này, ta cần chuyển vế và rút gọn:

⇔⇔⇔⇔​4(3−2x2)+896​=11212−8x2+12=112−8x2=88x2=−11x=±−11​​

Cảm ............. ơn 

Đã...................liếc

Qua.................liếc 

Lại ...................coi 

Tui ...................ghi 

Cái .......................thứ 

Nhảm ...................,rùi 

Này ........................Cầu 

Cho .........................ai

Thấy .........................cái 

Này ..............................sẽ 

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Cả ?................,,...,...............năm 

Ai ..........................................mà 

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Tớ .........................................?..............đẹp 

Hơn.............................và 

Xinh.......................hơn

Áp dụng tính chất dãy tỉ số bằng nhau, ta có:

\(\frac{x}{3}=\frac{y}{8}=\frac{z}{5}\Rightarrow\frac{4x}{12}=\frac{3y}{24}=\frac{2z}{10}=\frac{4x+4y-2z}{12+24-10}=\frac{96}{26}=\frac{48}{13}\)

\(\Rightarrow x=\frac{48}{13}\times3=\frac{144}{13}\)

    \(y=\frac{48}{13}\times8=\frac{384}{13}\)

   \(z=\frac{48}{13}\times5=\frac{240}{13}\)

Vậy ....

Áp dụng t/c DTSBN ta có:

\(\frac{x}{3}=\frac{y}{8}=\frac{z}{5}=\frac{4x+3y-2z}{4.3+3.8-2.5}=\frac{48}{13}\)

\(\Rightarrow\hept{\begin{cases}\frac{x}{3}=\frac{48}{13}\Rightarrow x=\frac{144}{13}\\\frac{y}{8}=\frac{48}{13}\Rightarrow y=\frac{384}{13}\\\frac{z}{5}=\frac{48}{13}\Rightarrow z=\frac{240}{13}\end{cases}}\)

Vậy \(x=\frac{144}{13};y=\frac{384}{13};z=\frac{240}{13}\)

hok tốt!

a. Đ

b. S

tham khảo nek: https://olm.vn/hoi-dap/detail/9664557962.html

a) x - 96 = (433 - x) - 15

x - 96 = 433 - x - 15

2x = 433 - 15 + 96

2x = 514

x = 257

b) 7x (-x-10) = 0

\(\Leftrightarrow\orbr{\begin{cases}7x=0\\-x-10=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-10\end{cases}}\)

c) 17 (3x - 6) (2x - 8) = 0

(3x - 6) (2x - 8) = 0

\(\Leftrightarrow\orbr{\begin{cases}3x-6=0\\2x-8=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}3x=6\\2x=8\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=4\end{cases}}\)

\(\Rightarrow\left(\frac{x+2}{98}+1\right)+\left(\frac{x+4}{96}+1\right)=\left(\frac{x+6}{94}+1\right)+\left(\frac{x+8}{92}+1\right)\)

\(\Rightarrow\frac{x+100}{98}+\frac{x+100}{96}=\frac{x+100}{94}+\frac{x+100}{92}\)

\(\Rightarrow\frac{x+100}{98}+\frac{x+100}{96}-\frac{x+100}{94}-\frac{x+100}{92}=0\)

\(\Rightarrow\left(x+100\right)\left(\frac{1}{98}+\frac{1}{96}-\frac{1}{94}-\frac{1}{92}\right)=0\)

\(\Rightarrow x+100=0\)

\(\Rightarrow x=0-100=-100\)

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