a) \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{0,3\cdot10}{16\cdot10}=\dfrac{3}{160}\)

b) \(\dfrac{17\cdot5-17}{3-20}=\dfrac{17\cdot\left(5-1\right)}{-17}=\dfrac{1\cdot4}{-1}=-4\)

a)

\(\dfrac{8\cdot5-8\cdot2}{16}=\dfrac{8\left(5-2\right)}{16}=\dfrac{3}{2}\)

b)

\(\dfrac{17\cdot5-17}{3-20}=\dfrac{17\left(5-1\right)}{-17}=\dfrac{4}{-1}=-4\)

\(\frac{8.5-8.2}{16}\)

\(=\frac{8.\left(5-2\right)}{8.2}=\frac{8.3}{8.2}=\frac{3}{2}\)

\(\frac{8.5-8.2}{16}\)

\(=\frac{8.\left(5-2\right)}{16}\)

\(=\frac{8.3}{16}\)

\(=\frac{4.2.3}{4.4}\)

\(=\frac{6}{4}=\frac{3}{2}\)

\(\frac{8.5-8.2}{16}=\frac{8.\left(5-2\right)}{8.2}=\frac{8.3}{8.2}=\frac{1.3}{1.2}\)

                                                                       =  \(\frac{3}{2}\)

Hoc tốt

\(\dfrac{-63}{72}=\dfrac{-7}{8}\)

\(\dfrac{20}{-140}=\dfrac{-1}{7}\)

\(\dfrac{3.10}{5.24}=\dfrac{30}{120}=\dfrac{1}{4}\)

\(\dfrac{3.7.11}{22.9}=\dfrac{231}{198}=\dfrac{7}{6}\)

\(\dfrac{8.5-8.2}{16}=\dfrac{24}{16}=\dfrac{3}{2}\)

\(\dfrac{11.4-11}{2-13}=\dfrac{33}{-11}=-3\)

a. \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{3}{160}\)

b. \(\dfrac{2\cdot14}{7\cdot8}=\dfrac{1\cdot2}{1\cdot4}=\dfrac{2}{4}=\dfrac{1}{2}\)

c. \(\dfrac{11\cdot4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{1\cdot3}{-1}=-3\)

d. \(\dfrac{49+7\cdot49}{49}=\dfrac{49\cdot\left(1+7\right)}{49}=\dfrac{8}{1}=8\)

*Rút gọn :

`(8.5-8.2)/16=(8.(5-2))/(8.2)=(8.3)/(8.2)=3/2`

`(11.4-11)/(2-13)=(11.(4-1))/(-11)=(11.3)/(-1.11)=3/(-1)=-3`

*Quy đồng :

- Ta có : `-3=(-3)/1`

UCLN(2,1)=2

$\to\begin{cases} \dfrac32=\dfrac32\\\dfrac{-3}1=\dfrac{-6}2\end{cases}$

ai đó giúp mình với

\(\frac{-1997\cdot1996+1}{-1995\cdot\left(-1997\right)+1996}\)

\(=\frac{-1997\cdot\left(1995+1\right)+1}{1995\cdot1997+1996}\)

\(=\frac{-1997\cdot1995+\left(-1997\right)+1}{1995\cdot1997+1996}\)

\(=\frac{-1997\cdot1995+\left(-1996\right)}{1995\cdot1997+1996}\)

\(=-1\)

\(\frac{-1997.1996+1}{-1995.\left(-1997\right)+1996}\)

\(=\frac{-1997.1996+1}{1995.1997+1996}\)

\(=\frac{-1997.\left(1995+1\right)+1}{1995.1997+1996}\)

\(=\frac{-1997.1995+-1997+1}{1995.1997+1996}\)

\(=\frac{1995.-1997+-1996}{1995.1997+1996}\)

\(=\frac{-\left(1995.1997+1996\right)}{1995.1997+1996}\)

\(=-1\)

D

B

a/ \(-\frac{81}{504}=-\frac{9}{56};-\frac{10101}{101010}=\frac{-1}{10}\)

b/ \(\frac{72\cdot5+72\cdot3}{144\cdot2+144\cdot6}=\frac{72\left(5+3\right)}{144\left(2+6\right)}=\frac{8}{2\cdot8}=\frac{1}{2}\)

\(\frac{-81}{504}=-\frac{81:9}{504:9}=-\frac{9}{56}\)

\(\frac{-10101}{101010}=\frac{-10101:10101}{101010:10101}=\frac{-1}{10}\)

\(\frac{72.5+72.3}{144.2+144.6}=\frac{72.\left(5+3\right)}{144\left(2+6\right)}=\frac{72.8}{144.8}=\frac{72.8}{72.2.8}=\frac{1}{2}\)

a. -9/56;-1/10

b 1/2