= -97/1176 ^{lớp 4 học số âm à???}

-97/1176 

-97/1176 

\(=\dfrac{3}{7}\times\left(\dfrac{1}{5}+\dfrac{2}{3}-\dfrac{1}{8}\right)\\ =\dfrac{3}{7}\times\left(\dfrac{24}{5\times24}+\dfrac{2\times40}{3\times40}-\dfrac{15}{8\times15}\right)\\ =\dfrac{3}{7}\times\left(\dfrac{24+80-15}{120}\right)\\ =\dfrac{3}{7}\times\dfrac{89}{120}\\ =\dfrac{89}{280}\)

\(\dfrac{3}{7}\times\dfrac{1}{5}+\dfrac{2}{3}\times\dfrac{3}{7}-\dfrac{3}{7}\times\dfrac{1}{8}\)
\(=\dfrac{3}{7}\times\left(\dfrac{1}{5}+\dfrac{3}{7}-\dfrac{1}{8}\right)\)
\(=\dfrac{3}{7}\times\dfrac{56+120-35}{280}\)
\(=\dfrac{3}{7}\times\dfrac{141}{280}\)
\(=\dfrac{423}{1960}\)

2/7

11/21

2/7

11/21

2/7

11/21

-6/35

1/5x (4/7- 3/7- 1)=1/5x -6/7= -6/35

\(-\dfrac{6}{35}\)

\(\dfrac{1}{5}\times\dfrac{4}{7}+\dfrac{3}{7}\times\dfrac{1}{5}-\dfrac{1}{5}\)

\(=\dfrac{4}{35}+\dfrac{3}{35}-\dfrac{1}{5}\)

\(=\dfrac{7}{35}-\dfrac{1}{5}\)

\(=\dfrac{1}{5}-\dfrac{1}{5}\)

\(=0\)

0

Mik có sửa lại đề

C1: \(\dfrac{6}{7}\times\dfrac{1}{2}+\dfrac{6}{7}\times\dfrac{1}{4}=\dfrac{3}{7}+\dfrac{3}{14}=\dfrac{6}{14}+\dfrac{3}{14}=\dfrac{9}{14}\)

C2:\(\dfrac{6}{7}\times\dfrac{1}{2}+\dfrac{6}{7}\times\dfrac{1}{4}=\dfrac{6}{7}\times\left(\dfrac{1}{2}+\dfrac{1}{4}\right)=\dfrac{6}{7}\times\left(\dfrac{2}{4}+\dfrac{1}{4}\right)=\dfrac{6}{7}\times\dfrac{3}{4}=\dfrac{9}{14}\)

3/7(4/5+2/5-1/5=3/7x1/5=3/35

3/7*4/5+3/7*2/5-3/7*1/5=3/7

đúng thì k cho mình nha

\(\frac{3}{7}.\frac{4}{5}+\frac{3}{7}.\frac{2}{5}-\frac{3}{7}.\frac{1}{5}=\frac{3}{7}\left(\frac{4}{5}+\frac{2}{5}-\frac{1}{5}\right)\)

                                               \(=\frac{3}{7}.1\)

                                                =\(\frac{3}{7}\)

5/6 x 1/7 - 1/7 x 1/6

= 1/7 x (5/6 - 1/6)

= 1/7 x 2/3

= 2/21

8/15 : 4/5 x 3/2

= 2/3 x 3/2

= 1

a: =1/7(5/6-1/6)=1/7x2/3=2/21

b: =8/15x5/4x3/2=1

`5/6xx1/7-1/7xx1/6`

`= 1/7 xx (5/6-1/6)`

`= 1/7 xx 2/3`

`= 2/21`

`8/15: 4/5 xx3/2`

`= 2/3 xx 3/2`

`= 1`