`(28^7 . 5^6 . 15^9)/(14^6 . 25^7 . 6^10)`
`=(2^{14}.7^7. 5^6 .5^9 .3^9)/(2^{6}.7^6. 5^14. 2^10. 3^10)`
`=(2^{14}.3^9. 5^{15}.7^7)/(2^{16}.3^{10}.7^6. 5^14)`
`=(5.7)/(2^2 .3 )`
`=35/12`

\(\frac{4}{7}.\frac{5}{36}.\frac{21}{25}\)

\(=\frac{4.5.21}{7.36.25}\)

\(=\frac{4.5.7.3}{7.4.9.5.5}\)

\(=\frac{3}{9.5}=\frac{3}{3.3.5}=\frac{1}{15}\)

\(\frac{25}{28}:\frac{15}{14}.\frac{6}{7}\)

\(=\frac{25.14.6}{28.15.7}\)

\(=\frac{5.5.14.6}{28.5.3.7}\)

\(=\frac{5.6}{2.3.7}=\frac{5.2.3}{2.3.7}\)

\(=\frac{5}{7}\)

thank you bạn nam giải bài toán đầu tiên nha

\(\dfrac{25}{28}:\dfrac{15}{14}\cdot\dfrac{6}{7}=\dfrac{25}{28}\cdot\dfrac{14}{15}\cdot\dfrac{6}{7}\)

\(=\dfrac{25}{15}\cdot\dfrac{14}{28}\cdot\dfrac{6}{7}=\dfrac{5}{3}\cdot\dfrac{1}{2}\cdot\dfrac{6}{7}\)

\(=\dfrac{5}{7}\)

de vay mak o biet

a) (2/5 x 25/29) + (3/5 x 25/29)
= (50/145) + (75/145)
= 125/145

b) (5/2 x 3/7) - (3/14 : 6/7)
= 15/14 - (3/14 x 7/6)
= 15/14 - 1/2
= (30/28) - (14/28)
= 16/28
= 4/7

c) (15/4 : 5/12) - (6/5 : 11/15)
= (15/4 x 12/5) - (6/5 x 15/11)
= 180/20 - 90/55
= 9 - 18/11
= (99/11) - (18/11)
= 81/11
= 7 4/11

a) (2/3) + (20/21 x 3/2 x 7/5)
= 2/3 + (60/210)
= 2/3 + 2/7
= (14/21) + (6/21)
= 20/21

b) (5/17 x 21/32 x 47/24 x 0)
= 0

c) (11/3 x 26/7) - (26/7 x 8/3)
= (286/21) - (208/21)
= 78/21
= 3 9/21
= 3 3/7

a) (25/8) : x = 5/16
=> (25/8) x (16/5) = x
=> 4 = x

b) x + (7/15) = 6/15
=> x = (6/15) - (7/15)
=> x = -1/15

c) x : (28/49) = 7/12
=> x x (49/28) = 7/12
=> x = (7/12) x (28/49)
=> x = 1/2

a) 6 x x = (5/8) : (3/4)
=> 6x = (5/8) x (4/3)
=> 6x = 20/24
=> 6x = 5/6
=> x = (5/6) / 6
=> x = 5/36

câu,b,không,đủ,thông,tin,nhan,bạn.

5/7 nha bạn 

= 25/28x14/15x6/7

=15/21=5/7

\(\dfrac{tử số}{mẫu số}\)

\(\frac{25}{28}:\frac{15}{14}.\frac{6}{7}\)\(=\frac{25}{28}.\frac{14}{15}.\frac{6}{7}=\frac{5}{7}\)

\(a.\left(-83\right)+302+83\\ =\left(-83+83\right)+302\\ =0+302\\ =302\\ b.14.\left(-7\right)-216:2\\ =-98-108\\ =-206\\ c.56.\left(-32\right)+\left(-68\right).56\\ =56.\left[\left(-32\right)+\left(-68\right)\right]\\ =57.\left(-100\right)\\ =-5700\\ d.2^3-6.\left[25-\left(33-28\right)^2\right]\\ =8-6\left[25-5^2\right]\\ =8-6\left[25-25\right]\\ =8-6.0\\ =8-0\\ =8\\ e.15.\left(-6\right)-420:\left(-4\right)\\ =-90-\left(-105\right)\\ =-90+105\\ =15\)

\(f.63.\left(-52\right)+\left(-48\right).63\\ =63.\left[\left(-52\right)+\left(-48\right)\right]\\ =63.\left(-100\right)\\ =-6300\)

a) \(\dfrac{7}{-25}+\dfrac{8}{25}=\dfrac{-7}{25}+\dfrac{8}{25}=\dfrac{1}{25}\)

\(\dfrac{4}{5}+\dfrac{4}{-18}=\dfrac{4}{5+\left(-18\right)}=\dfrac{4}{-13}=\dfrac{-4}{13}\)

\(\dfrac{7}{21}+\dfrac{9}{-36}=\dfrac{1}{3}+\dfrac{1}{-4}=\dfrac{1}{3+\left(-4\right)}=\dfrac{1}{-1}=1\)

b) \(\dfrac{12}{20}-\dfrac{2}{5}=\dfrac{12}{20}+\left(\dfrac{-2}{5}\right)=\dfrac{3}{5}+\dfrac{-2}{5}=\dfrac{3+\left(-2\right)}{5}=\dfrac{1}{5}\)

\(\dfrac{2}{3}-\dfrac{-5}{6}=\dfrac{2}{3}+\dfrac{5}{6}=\dfrac{4}{6}+\dfrac{5}{6}=\dfrac{9}{6}=\dfrac{3}{2}\)

\(6-\dfrac{3}{20}=6+\dfrac{-3}{20}=\dfrac{60}{60}+\dfrac{-9}{60}=\dfrac{51}{60}\)

c) \(\dfrac{2}{21}.\dfrac{-7}{3}=\dfrac{2.\left(-1\right)}{7.3}=\dfrac{-2}{21}\)

\(\dfrac{27}{28}.\left(-21\right)=\dfrac{27.\left(-21\right)}{28}=\dfrac{-567}{28}\)

\(\dfrac{-15}{7}.\dfrac{-14}{25}=\dfrac{-3.\left(-2\right)}{1.5}=\dfrac{6}{5}\)