\(\frac{202}{505}\)

\(=\frac{202\div101}{505\div101}\)

\(=\frac{2}{5}\)

\(\frac{202}{505}=\frac{202:101}{505:101}=\frac{2}{5}\)

~~ Chúc bạn học tốt ~~

\(\frac{202}{505}\)= \(\frac{202:101}{505:101}\)= \(\frac{2}{5}\)

Giups mik với 

;-;

= 19/194 nha bn

Chúc học tốt nè !

-18

-18

-90/5= -18

\(=\dfrac{3}{4}\)

9/12

3/4

#include <bits/stdc++.h>
using namespace std;
long long a,b,c,d,tu,mau;
//chuongtrinhcon
long long ucln(long long a,long long b)
{
    long long uocchunglonnhat;
    if (a>b) swap(a,b);
    for (long long i=a; i>=1; i--)
        if ((a%i==0) and (b%i==0))
    {
        uocchunglonnhat=i;
        break;
    }
    return(uocchunglonnhat);
}
//chuongtrinhchinh
int main()
{
    cin>>a>>b>>c>>d;
    tu=a*d+b*c;
    mau=b*d;
    cout<<tu/ucln(tu,mau)<<"/"<<mau/ucln(tu,mau);
    return 0;
}

86/48 = 43/24

43/24

\(\dfrac{86}{48}\)= \(\dfrac{86:2}{48:2}\)=\(\dfrac{43}{24}\)

\(\sqrt{x^2y^3}+y\sqrt{x^4y}-xy\sqrt{y}\)

\(=xy\sqrt{y}+x^2y\sqrt{y}-xy\sqrt{y}\)

\(=x^2y\sqrt{y}\)

giúp mình  nhanh với ạ

72/96 =9/12  

64/48=4/3

132/462=12/42

 a) \(\dfrac{72}{96}\)=\(\dfrac{72:24}{96:24}\)=\(\dfrac{3}{4}\)                                                       b) \(\dfrac{64}{48}\)=\(\dfrac{64:16}{48:16}\)=\(\dfrac{4}{3}\)

 c) \(\dfrac{132}{462}\)=\(\dfrac{132:66}{462:66}\)=\(\dfrac{2}{7}\)