Đây nhé

b) \(6x^2-13x+5=6x^2-3x-10x+5\)

\(=3x\left(2x-1\right)-5\left(2x-1\right)\)

\(=\left(2x-1\right).\left(3x-5\right)\)

d) \(3x^2-11x+6=3x^2-9x-2x+6\)

\(=3x\left(x-3\right)-2\left(x-3\right)\)

\(=\left(x-3\right)\left(3x-2\right)\)

e) \(-7x^2+11x+6=-7x^2+14x-3x+6\)

\(=-7x\left(x-2\right)-2\left(x-2\right)\)

\(=\left(x-2\right)\left(-7x-2\right)\)

\(6x^2-13x+5=6x^2-3x-10x+5\)

\(=3x\left(2x-1\right)-5\left(2x-1\right)\)

\(=\left(2x-1\right).\left(3x-5\right)\)

\(a,-7x^2+11x+6\)

\(=-7x^2-3x+14x+6\)

\(=-x\left(7x+3\right)+2\left(7x+3\right)\)

\(=\left(2-x\right)\left(7x+3\right)\)

\(b,-x^2-4x-3\)

\(=-\left(x^2+4x+3\right)\)

\(=-\left(x^2+x+3x+3\right)\)

\(=-\left[x\left(x+1\right)+3\left(x+1\right)\right]\)

\(=-\left[\left(x+3\right)\left(x+1\right)\right]\)

\(=\left(-x-3\right)\left(x+1\right)\)

\(A=-7x^2+11x+6\)

\(A=-7x^2+14x-3x+6\)

\(A=-7x\left(x-2\right)-3\left(x-2\right)\)

\(A=\left(x-2\right)\left(-7x-3\right)\)

\(B=-x^2-4x-3\)

\(B=-x^2-x-3x-3\)

\(B=-x\left(x+1\right)-3\left(x+1\right)\)

\(B=\left(x+1\right)\left(-x-3\right)\)

a, − 7x + 11x + 6

= −7x − 3x + 14x + 6

= −x 7x + 3 + 2 7x + 3

= 2 − x 7x + 3 b, − x − 4x − 3

= − x + 4x + 3

= − x + x + 3x + 3

= − x x + 1 + 3 x + 1

= − x + 3 x + 1

= −x − 3 x + 1 2 2 ( ) ( ) ( ) ( ) 2 ( 2 ) ( 2 ) [ ( ) ( )

= [x² - 2.x.\(\frac{11}{2}\) + \(\left(\frac{11}{2}\right)^2\)] - \(\frac{121}{4}\)+ 8 = (x - \(\frac{11}{2}\))² - \(\frac{89}{4}\) =  (x - \(\frac{11}{2}\))² - \(\left(\frac{\sqrt{89}}{2}\right)^2\)

= \(\left(x-\frac{11}{2}-\frac{\sqrt{89}}{2}\right).\left(x-\frac{11}{2}+\frac{\sqrt{89}}{2}\right)\)= \(\left(x-\frac{11+\sqrt{89}}{2}\right).\left(x+\frac{\sqrt{89}-11}{2}\right)\)

a) \(x^3+4x^2-21x\)

\(=x\left(x^2+4x-21\right)\)

\(=x\left(x^2-3x+7x-21\right)\)

\(=x\left[x\left(x-3\right)+7\left(x-3\right)\right]\)

\(=x\left(x-3\right)\left(x+7\right)\)

b) \(5x^3+6x^2+x\)

\(=x\left(5x^2+6x+1\right)\)

\(=x\left(5x^2+5x+x+1\right)\)

\(=x\left[5x\left(x+1\right)+\left(x+1\right)\right]\)

\(=x\left(x+1\right)\left(5x+1\right)\)

c) \(x^3-7x+6\)

\(=x^3+2x^2-3x-2x^2-4x+6\)

\(=x\left(x^2+2x-3\right)-2\left(x^2+2x-3\right)\)

\(=\left(x-2\right)\left(x^2+2x-3\right)\)

\(=\left(x-2\right)\left(x-1\right)\left(x+3\right)\)

d) \(3x^3+2x-5\)

\(=3x^3+3x^2+5x-3x^2-3x-5\)

\(=x\left(3x^2+3x+5\right)-\left(3x^2+3x+5\right)\)

\(=\left(x-1\right)\left(3x^2+3x+5\right)\)

       \(-10x^2+11x+6\)

\(=-10x^2-4x+15x+6\)

\(=-2x\left(5x+2\right)+3\left(5x+2\right)\)

\(=\left(-2x+3\right)\left(5x+2\right)\)

      \(10x^2-4x-6\)

\(=10x^2-10x+6x-6\)

\(=10x\left(x-1\right)+6\left(x-1\right)\)

\(=\left(10x+6\right)\left(x-1\right)\)

\(=2\left(5x+3\right)\left(x-1\right)\)

       \(-10x^2+4x+6\)

\(=-2\left(5x^2-2x-3\right)\)

\(=-2\left[5x^2-5x+3x-3\right]\)

\(=-2\left[5x\left(x-1\right)+3\left(x-1\right)\right]\)

\(=-2\left(x-1\right)\left(5x+3\right)\)

      \(10x^2+7x-6\)

\(=10x^2+12x-5x-6\)

\(=2x\left(5x+6\right)-\left(5x+6\right)\)

\(=\left(5x+6\right)\left(2x-1\right)\)

a, x²-5x+6=(x²-2x)-(3x-6)=x(x-2)-3(x-2)=(x-2)(x-3)

b, 3x²+9x-30=(3x²-6x)+(15x-30)=3x(x-2)+15(x-2)=3(x-2)(x+5)

c, x²-3x+2=(x²-x)-(2x-2)=x(x-1)-2(x-1)=(x-1)(x-2)

a, x^2-5x+6=x^2-2x-3x+6=(x^2-2x)-(3x-6)=x(x-2)-3(x-2)=(x-3)(x-2)

b, 3x^2+9x-30=3x^2-6x+15x-30=(3x^2-6x)+(15x-30)=3x(x-2)+3(x-2)=(3x+3)(x-2)

c, x^2-3x+2=x^2-x-2x+2=(x^2-x)-(2x-2)=x(x-1)-2(x-1)=(x-2)(x-1)

câu b mik lm nhầm nhé

somebody help me 

\(1,2x^2-3x-2\) 

\(=2x^2-4x+x-2\)

\(=2x\left(x-2\right)+\left(x-2\right)\) 

\(=\left(2x+1\right)\left(x-2\right)\) 

\(2,4x^2-7x-2\)

\(=4x^2-8x+x-2\) 

\(=4x\left(x-2\right)+x-2\)

\(\left(4x+1\right)\left(x-2\right)\)