290-10.(2018^0+3^5:3^2)

=290-10.(1+243:9)

=290-10.(1+27)

=290-10.28

=290-280

=10

71-50:[5+3.(57-6.7)]

300

300

= 300 

\(32:\left\{160:\left[300-\left(175+21\times5\right)\right]\right\}=32:\left[160:\left(300-280\right)\right]=32:\left(160:20\right)=32:8=4\)

  32 : { 160 : [ 300 - ( 175 + 21 . 5) ] }

=32 : { 160 : [ 300 -        280          ] }

=32 : { 160 :       20                         }

=32 :        8

=4 

k mình nha ^^

   32 : {160 : [300 - (175 + 21.5)]}

= 32 : {160 : [300 - (175 + 105)]}

= 32 : {160 : [300 - 280]}

= 32 : {160 : 20}

= 32 : 8

= 4

a,  15 . { 32 : [ 6 - 5 + 5 ( 9 : 3 ) ] + 3 } - 2018 0

= 15.{32:[1+15]+3}–1

= 15.5–1

= 74

b,  25 . { 2 7 : [ 12 - 4 + 2 2 . 16 : 2 3 ] - 2 4 }

= 25.{128:[8+4.2]–16}

= 25.24

= 600

c,  2019 . { 101 - 1000 : [ 2 2 . 2 3 + 5 6 : 5 3 - 6 2 : 11 - 2018 0 ] }

= 2019.{101–1000:[(32+125–36):11–1]}

= 2019.{101–1000:[121:11–1]}

= 2019.{101–1000:10}

= 2019.1

= 2019

32 . {160 : [ 300 - (175 + 21 . 5) ] }

= 32 . {160 : [ 300 - 280 ] }

= 32 . {160 : 20}

= 32 . 8

= 256

Trả lời 

184

sai thì bỏ đi

a: =(375-175)+(369-169)+...+(207-7)

=200+200+...+200

=200*[(375-207)/2+1]

\(=200\cdot85=17000\)

b: \(=\left(24-11\right)+\left(32-19\right)+\left(40-27\right)+...+\left(336-323\right)\)

\(=13\cdot\left[\left(336-24\right):8+1\right]=13\cdot40=520\)

c: \(=\left(5-2\right)+\left(8-4\right)+\left(11-6\right)+...+\left(140-92\right)\)

=3+4+5+...+48

Số số hạng là (48-3):1+1=45+1=46(số)

Tổng là: (48+3)*46/2=51*23=1173

d: \(=\left(300-285\right)+\left(295-278\right)+\left(290-271\right)+...+\left(100-5\right)+10\)

=15+17+19+...+95+10

Số số lẻ trong khoảng từ 15 đến 95 là:

(95-15):2+1=41(số)

Tổng của dãy số trên là:

10+(95+15)*41/2

=10+55*41

=2265

a: \(20-\left[30-\left(5-1\right)^2\right]\)

\(=20-\left[30-4^2\right]\)

\(=20-14=6\)

b: \(71+\dfrac{50}{5+3\left(57-6\cdot7\right)}\)

\(=71+\dfrac{50}{5+3\cdot\left(57-42\right)}\)

\(=71+\dfrac{50}{5+3\cdot15}=71+\dfrac{50}{50}=72\)

c: \(4\cdot\left\{270:\left[50-\left(2^5+45:5\right)\right]\right\}\)

\(=4\cdot\left\{270:\left[50-32-9\right]\right\}\)

\(=4\cdot\left\{\dfrac{270}{50-41}\right\}=4\cdot\dfrac{270}{9}=4\cdot30=120\)

d: \(411-\left[\dfrac{\left(107+3\right)}{5}-2^2\right]\)

\(=411-\left[\dfrac{110}{5}-4\right]\)

=410-22+4

=410-18

=392

e: \(450-5\left[3^2\left(7^5:7^3-41\right)-12\right]+18\)

\(=450-5\left[9\cdot\left(7^2-41\right)-12\right]+18\)

\(=450-5\cdot\left[9\cdot8-12\right]+18\)

=468-5*60

=468-300

=168

f:

\(102-150:\left[18-2\cdot\left(10-8\right)^2\right]+1018^0\)

\(=102-150:\left[18-2\cdot4\right]+1\)

\(=103-\dfrac{150}{18-8}=103-15=88\)