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\(\frac{5}{6}-\left(\frac{2}{5}+\frac{1}{3}\right)\)

=\(\frac{5}{6}-\left(\frac{6}{15}+\frac{5}{15}\right)\)

=\(\frac{5}{6}-\frac{11}{15}\)

=\(\frac{25}{30}-\frac{22}{30}\)

=\(\frac{1}{10}\)

(9+1)+(8+2)+(7+3)+(6+4)+10+5

=10+10+10+10+10+5=45

9+3+2+1+7+8+5+10+6+4= (9+1)+(2+8)+(3+7)+(4+6)+5=10+10+10+10+5=10.4+5=40+5=45

(9+1)+(3+7)+(2+8)+(6+4)+10

=10+10+10+10+10

=50

a) \(\frac{5}{6}-\left(\frac{2}{5}+\frac{1}{3}\right)=\frac{5}{6}-\frac{11}{15}=\frac{1}{10}\)

b) \(\frac{3}{4}-\frac{1}{3}-\frac{1}{6}=\frac{3}{4}-\left(\frac{1}{3}+\frac{1}{6}\right)=\frac{3}{4}-\frac{1}{2}=\frac{1}{4}\)

a, \(\frac{5}{6}-\left(\frac{2}{5}+\frac{1}{3}\right)\)

 \(=\frac{5}{6}-\frac{2}{5}-\frac{1}{3}\)

\(=\frac{25}{30}-\frac{12}{30}-\frac{10}{30}\)

\(=\frac{3}{30}=\frac{1}{10}\)

b. \(\frac{3}{4}-\frac{1}{3}-\frac{1}{6}\)

\(=\frac{3}{4}-\left(\frac{1}{3}+\frac{1}{6}\right)\)

\(=\frac{3}{4}-\frac{9}{18}\)

\(=\frac{3}{4}-\frac{1}{2}\)

\(=\frac{1}{4}\)

\(1,\\ c,\dfrac{17}{6}-\dfrac{3}{7}-\dfrac{5}{6}=\dfrac{17\times7-3\times6-5\times7}{6\times7}=\dfrac{119-18-35}{42}=\dfrac{66}{42}=\dfrac{11}{7}\\ 2,\\ a,\dfrac{6}{9}+\dfrac{3}{15}+\dfrac{7}{15}\\ =\dfrac{6:3}{9:3}+\dfrac{7+3}{15}\\ =\dfrac{2}{3}+\dfrac{10}{15}\\ =\dfrac{2}{3}+\dfrac{2}{3}\\ =\dfrac{2+2}{3}=\dfrac{4}{3}\)

\(b,\dfrac{7}{2}+\dfrac{29}{12}-\dfrac{11}{12}\\ =\dfrac{7}{2}+\left(\dfrac{29}{12}-\dfrac{11}{12}\right)\\ =\dfrac{7}{2}+\dfrac{29-11}{12}\\ =\dfrac{7}{2}+\dfrac{18}{12}\\ =\dfrac{7}{2}+\dfrac{18:6}{12:6}\\ =\dfrac{7}{2}+\dfrac{3}{2}\\ =\dfrac{7+3}{2}=\dfrac{10}{2}=5\)

\(c,\dfrac{26}{25}-\dfrac{3}{5}-\dfrac{2}{5}\\ =\dfrac{26}{25}-\dfrac{3\times5}{5\times5}-\dfrac{2\times5}{5\times5}\\ =\dfrac{26-15-10}{25}\\ =\dfrac{1}{25}\)

Bài 1:
\(\dfrac{17}{6}-\dfrac{3}{7}-\dfrac{5}{6}=\left(\dfrac{17}{6}-\dfrac{5}{6}\right)-\dfrac{3}{7}=2-\dfrac{3}{7}=\dfrac{14}{7}-\dfrac{3}{7}=\dfrac{11}{7}\)
Bài 2:
a/\(\dfrac{6}{9}+\dfrac{3}{15}+\dfrac{7}{15}\)
\(=\dfrac{2}{3}+\left(\dfrac{3}{15}+\dfrac{7}{15}\right)\)
\(=\dfrac{2}{3}+\dfrac{2}{3}\)
\(=\dfrac{4}{3}\)
b/\(\dfrac{7}{2}+\dfrac{29}{12}-\dfrac{11}{12}\)
\(=\dfrac{7}{2}+\left(\dfrac{29}{12}-\dfrac{11}{12}\right)\)
\(=\dfrac{7}{2}+\dfrac{3}{2}\)
\(=5\)
c/\(\dfrac{26}{25}-\dfrac{3}{5}-\dfrac{2}{5}\)
\(=\dfrac{26}{25}-\left(\dfrac{3}{5}+\dfrac{2}{5}\right)\)
\(=\dfrac{26}{25}-1\)
\(=\dfrac{26}{25}-\dfrac{25}{25}\)
\(=\dfrac{1}{25}\)
#Đang Bận Thở

3/4 x 4/5 : 3/5 x 6/7 : 1/7 x 5/6

= 3/4 x 4/5 x 5/3 x 6/7 x7/1 x 5/6

= 5

264,14 : 0,25 : 4

= 264,14 : ( 0,25 x 4 )

= 264,14 : 1

= 264,14 

36,45 : 0,2 x 2 : 5

=  36,45 : ( 2 x 5 ) : 0,2

= 36,45 : 10 : 0,2 

= 3,645 : 0,2

= 18,225

Tính bằng cách thuận tiện:

a. 264,14 : 0,25 : 4

=264,14

b. 36,45 : 0,2 x 2 : 5

=72,9

(3/5+5/8)+(3/4+1/2)=49/40+5/4=99/40

1) \(=\left(\frac{3}{5}+\frac{2}{5}\right).\frac{6}{11}\)

\(=1.\frac{6}{11}\)

\(=\frac{6}{11}\)

2)\(\frac{17}{25}.\left(\frac{11}{19}+\frac{6}{19}+\frac{2}{19}\right)\)

\(=\frac{17}{25}.1\)

\(=\frac{17}{25}\)

2.\(\frac{17}{25}.\frac{11}{19}+\frac{17}{25}.\frac{6}{19}+\frac{17}{25}.\frac{2}{19}=\frac{17}{25}\left(\frac{11}{19}+\frac{6}{19}+\frac{2}{19}\right)\\ =\frac{17}{25}.1\\ =\frac{17}{25}\)