tim so nguyen x biet x=12+43
tim so nguyen x biet -8+/x/=-12
-8+|x|=-12
|x|=-12+8
|x|=-4 mà |x|>=0(với mọi x)
nên \(x\in\phi\)
tim x dua vao quan he uoc boi:
tim so tu nhien x sao cho x-1 la uoc cua 12
tim so tu nhien x sao cho 2x+1 la uoc cua 28
tim so tu nhien x sao cho x+15 la boi cua x+3
tim cac so nguyen x,y sao cho (x+1)(y-2)=3
tim so nguyen x sao cho(x+2).(y-1)=2
tim so nguyen to x vua la uoc cua 275 vua la uoc cua 180
tim so nguyen to x,y biet x+y=12 va UCLL (x:y)=5
tim so tu nhien x,y biet x+y=32 va UCLL (x:y)=8
tim so tu nhien x biet x chia het cho10; xchia het cho12; x chia het cho15 va 100<x<150
tim so x nho nhat khac 0b biet x chia het cho 24 va 30
40 chia het cho x . 56 chia het cho x va x>6
a, Tim so tu nhien x, y biet rang 4<9/x<12/y<18
b, Tim so nguyen x, y biet rang x/2 - 2/y = 1/2
Lam cach nao de ra duoc ket qua nhu vay ha ban?
Tim so nguyen x biet :
-12 (x - 5 ) + 7(3 - x )
tim so nguyen x biet: (-12)^2.x=56+10.38.x
vay x la
tim cac so nguyen x,y,z biet :-6/12=x/8=-7/y=z/-18
Ta có :
\(\frac{-6}{12}=\frac{x}{8}=\frac{-7}{y}=\frac{z}{-18}=\frac{-1}{2}\)
\(\Rightarrow\hept{\begin{cases}\frac{x}{8}=\frac{-1}{2}\Rightarrow x=\left(-4\right)\\\frac{-7}{y}=\frac{-1}{2}\Rightarrow y=14\\\frac{z}{-18}=\frac{-1}{2}\Rightarrow z=9\end{cases}}\)
Vậy ...
tim so nguyen x biet \(\left|18-2.\right|-x+5=12\)
sorry mình sai đề
tim so nguyen x biet:
a, 23-x=19-(-12)
b, x-7=(-2)-8
\(a,23-x=19-\left(-21\right)\)
\(23-x=19+21\)
\(23-x=40\)
\(x=23-40\)
\(x=-17\)
Vậy \(x\in\left\{-17\right\}\)
\(b,x-7=\left(-2\right)-8\)
\(x-7=\left(-2\right)+\left(-8\right)\)
\(x-7=-10\)
\(x=-10+7\)
\(x=-10-\left(-7\right)\)
\(x=-3\)
Vậy \(x\in\left\{-3\right\}\)
a)23-x=19-(-12)
=>23-x=31
x=23-31
x=-8
Vậy x=-8
b)x-7=(-2)-8
x-7=-10
x =(-10)+7
x =-3
Vậy x=-3
a,23-x=19-(-12)
23-x=31
x=23-31
x=-8
b,x-7=(-2)-8
x-7=-10
x =-10+7
x =-3
Nếu đúng k mình nha
tim so nguyen x,y biet
(5+x)(4-y)= 12
Vì (4-y) e ư(12)={1,2,3,4,6,12}
Lập bảng:
4-y | 1 | 2 | 3 | 4 | 6 | 12 |
y | 3 | 2 | 1 | 0 | -2 | -8 |
5+x | 12 | 6 | 4 | 3 | 2 | 1 |
x | 7 | 1 | -1 | -1 | -3 | -4 |
Vậy các cặp số (y,x) cần tìm là:(3,7),(2,1),(1,-1),(0,-1),(-2,-3),(-8,-4)
OK!
12 được phân tích là: 3x4;2x6;1x12
ta có bảng
5+x | 3 | 4 | 2 | 6 | 1 | 12 |
4-y | 4 | 3 | 6 | 2 | 12 | 1 |
x | -2 | -1 | -3 | 1 | -4 | 7 |
y | 0 | 1 | -2 | 2 | -8 | -3 |
(5+x)(4-y)=12
= (5+x).4-(5+x).y=12
=20+4x-(5y+xy)=12
=20+4x-5y-xy=12
=4x-5y-xy=-8...................van van