16 . 25 + 196 : 49 = 4 2 . 5 2 + 14 2 : 7 2

= 4.5 + 14:7 = 20 + 2 = 22

Lời giải:

$=\sqrt{4^2}.\sqrt{5^2}+\sqrt{14^2}: \sqrt{7^2}$

$=4.5+14:7=20+2=22$

400+4 =404

\(\sqrt{16}=4\)

\(\sqrt{49}=7\)

\(\sqrt{121}=11\)

\(\sqrt{169}=13\)

\(\sqrt{196}=14\)

trả lời 

\(\sqrt{16}\);\(\sqrt{49}\);\(\sqrt{121}\);\(\sqrt{169}\);\(\sqrt{196}\)

chúc bn hok tốt 

Cảm ơn bạn

\(=20+\frac{14}{7}=20+2=22\)

0,25 = (0,5)²

\(\dfrac{1}{49}\) = (\(\dfrac{1}{7}\))²

- \(\dfrac{27}{125}\) = (- \(\dfrac{3}{5}\))³

 \(\dfrac{81}{16}\) = ( \(\dfrac{9}{4}\))²

\(\dfrac{169}{196}\) = (\(\dfrac{13}{14}\))²

Cạnh hình vuông là: `28:4=7(m)`

Diện tích hình vuông là: \(7\times7=49(m^2)\)

     `->` Không có đáp án.

d nhé bạn nhưng 49m² nhé k phải 49 cm2 đâu

a: \(=4\cdot5+14:7\)

=20+2

=22

a: \(A=\dfrac{1-\dfrac{1}{\sqrt{49}}+\dfrac{1}{49}-\dfrac{1}{\left(7\sqrt{7}\right)^2}}{\dfrac{\sqrt{64}}{2}-\dfrac{4}{7}+\left(\dfrac{2}{7}\right)^2-\dfrac{4}{343}}\)

\(=\dfrac{1-\dfrac{1}{7}+\dfrac{1}{49}-\dfrac{1}{343}}{4-\dfrac{4}{7}+\dfrac{4}{49}-\dfrac{4}{343}}\)

\(=\dfrac{1-\dfrac{1}{7}+\dfrac{1}{49}-\dfrac{1}{343}}{4\left(1-\dfrac{1}{7}+\dfrac{1}{49}-\dfrac{1}{343}\right)}=\dfrac{1}{4}\)

b: \(M=1-\dfrac{5}{\sqrt{196}}-\dfrac{5}{\left(2\sqrt{21}\right)^2}-\dfrac{\sqrt{25}}{204}-\dfrac{\left(\sqrt{5}\right)^2}{374}\)

\(=1-\dfrac{5}{14}-\dfrac{5}{84}-\dfrac{5}{204}-\dfrac{5}{374}\)

\(=1-5\left(\dfrac{1}{14}+\dfrac{1}{84}+\dfrac{1}{204}+\dfrac{1}{374}\right)\)

\(=1-5\left(\dfrac{1}{2\cdot7}+\dfrac{1}{7\cdot12}+\dfrac{1}{12\cdot17}+\dfrac{1}{17\cdot22}\right)\)

\(=1-\left(\dfrac{5}{2\cdot7}+\dfrac{5}{7\cdot12}+\dfrac{5}{12\cdot17}+\dfrac{5}{17\cdot22}\right)\)

\(=1-\left(\dfrac{1}{2}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{17}+\dfrac{1}{17}-\dfrac{1}{22}\right)\)

\(=1-\left(\dfrac{1}{2}-\dfrac{1}{22}\right)\)

\(=1-\dfrac{11-1}{22}=1-\dfrac{10}{22}=\dfrac{12}{22}=\dfrac{6}{11}\)