a) \(6-2x-8=-4\Leftrightarrow2x=2\Leftrightarrow x=1\)

b) \(6⋮x\Rightarrow x=\left\{-6;-3;-2;-1;1;2;3;6\right\}\)

c) \(2x-3=-7\Leftrightarrow2x=-4\Leftrightarrow x=-2\)

d) \(231-x+6=103\Leftrightarrow x=124\)

e) hình như sai đề

f) \(x^3=27\Leftrightarrow x=3\)

g) \(x+2=3\Leftrightarrow x=1\)

h) \(\left(x+5\right)^2=25\Leftrightarrow x+5=5\Leftrightarrow x=0\)

i) \(x^2=9\Leftrightarrow\orbr{\begin{cases}x=-3\\x=3\end{cases}}\)

j) \(14⋮\left(x+3\right)\Rightarrow x=\left\{-17;-10;-5;-4;-2;4;11\right\}\)

a) \(6-2\left(x+4\right)=-4\)

\(\Leftrightarrow6-2x-8=-4\)

\(\Leftrightarrow-2-2x=-4\)

\(\Leftrightarrow-2x=-4+2\)

\(\Leftrightarrow-2x=-2\)

\(\Leftrightarrow x=1\)

Vậy \(x=1\)

b) tự làm.

c) \(2x-15:5=-7\)

\(\Leftrightarrow2x-7,5=-7\)

\(\Leftrightarrow2x=-7+7,5\)

\(\Leftrightarrow2x=0,5\)

\(\Leftrightarrow x=0,25\)

\(\Leftrightarrow x=\dfrac{1}{4}\)

Vậy \(x=\dfrac{1}{4}\)

d) \(231-\left(x-6\right)=1339:13\)

\(\Leftrightarrow231-x+6=103\)

\(\Leftrightarrow237-x=103\)

\(\Leftrightarrow237-x+6=103\)

\(\Leftrightarrow-x=103-237\)

\(\Leftrightarrow-x=-134\)

\(\Leftrightarrow x=134\)

e) đề j mà có 2 dấu bằng >> sai :v

f) \(28-x^3=1\)

\(\Leftrightarrow-x^3=1-28\)

\(\Leftrightarrow-x^3=-27\)

\(\Leftrightarrow x^3=27\)

\(\Leftrightarrow x^3=3^3\)

\(\Leftrightarrow x=3\)

Vậy \(x=3\)

g) \(\left(x+2\right)^3=27\)

\(\Leftrightarrow\left(x+2\right)^3=3^3\)

\(\Leftrightarrow x+2=3\)

\(\Leftrightarrow x=3-2\)

\(\Leftrightarrow x=1\)

Vậy \(x=1\)

h) \(81-\left(x-5\right)^2=56\)

\(\Leftrightarrow-\left(x-5\right)^2=56-81\)

\(\Leftrightarrow-\left(x-5\right)^2=-25\)

\(\Leftrightarrow\left(x-5\right)^2=25\)

\(\Leftrightarrow x-5=\pm5\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=5\\x-5=-5\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=5+5\\x=-5+5\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=0\end{matrix}\right.\)

Vậy \(x_1=0;x_2=10\)

j) \(x^2=9\)

\(\Leftrightarrow x=\pm3\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)

Vậy \(x_1=-3;x_2=3\)

l) tự làm.

1, ta thấy : 1339=13.103  mà 13 là số có 2 chữ số nên thương của phép chia đó là 103

{1339:13=103}

2.gọi số chia là  n               gọi số thương là k

-ta có : 213:n=k(dư 10)      

hay : 213 : n   = k.n+10

suy ra : k.n  = 203 =29.7=7.29

vậy k= 29 ; n=7

2x - 138 = 2³ . 3²

\(\Rightarrow\) x - 69 = 2² . 9 = 4 . 9

\(\Rightarrow\) x - 69 = 36

\(\Rightarrow\) x = 105

231 - (x - 6) = 1339 : 13

\(\Rightarrow\) 231 - (x - 6) = 103

\(\Rightarrow\) x - 6 = 128

\(\Rightarrow\) x = 134

50(x - 3) + 40 = 160

\(\Rightarrow\) 50(x - 3) = 120

\(\Rightarrow\) x - 3 = 2,4

\(\Rightarrow\) x = 5,4

a) \(4^{13}+4^{14}+4^{15}+4^{16}=4^{13}\left(1+4\right)+4^{14}\left(1+4\right)=4^{13}.5+4^{14}.5=5\left(4^{13}+4^{14}\right)⋮5\Rightarrow dpcm\)

c) \(2^{10}+2^{11}+2^{12}+2^{13}+2^{14}+2^{15}\)

\(=2^{10}\left(1+2+2^2\right)+2^{13}\left(1+2+2^2\right)\)

\(=2^{10}.7+2^{13}.7=7\left(2^{10}+2^{13}\right)⋮7\Rightarrow dpcm\)

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