\(\dfrac{2^4.2^6}{\left(2^5\right)^2}-\dfrac{2^5.15^3}{6^3.10^2}\)
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\(\dfrac{2^4.2^6}{\left(2^5\right)^2}-\dfrac{2^5.15^3}{6^3.10^2}\)
Giúp mk nhé, cám ơn!
\(\dfrac{2^4.2^6}{\left(2^5\right)^2}-\dfrac{2^5.15^3}{6^3.10^2}=\dfrac{2^{10}}{2^{10}}-\dfrac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}\)
=\(1-\dfrac{5^3}{5^2}\) = \(1-5=-4\)
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1) thực hiện phép tính
a)\(\dfrac{2^4.2^6}{\left(2^5\right)^2}.2008\)
b)\(\dfrac{2^5.15^3}{6^3.10^2}\)
a) \(\dfrac{2^4.2^6}{\left(2^5\right)^2}.2008\)
\(=\dfrac{2^{\left(4+6\right)}}{2^{5.2}}.2008\)
\(=\dfrac{2^{10}}{2^{10}}.2008\)
\(=1.2008\)
\(=2008\)
b) \(\dfrac{2^5.15^3}{6^3.10^2}\)
\(=\dfrac{2^5.\left(3.5\right)^3}{\left(2.3\right)^3.\left(2.5\right)^2}=\dfrac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}=\dfrac{2^5.3^3.5^3}{2^5.3^3.5^2}=\dfrac{5^3}{5^2}=5\)
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1) \(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
\(=\frac{2^{10}}{2^{10}}-\frac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}\)
\(=1-5=-4\)
ik nhé. tks bạn!
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\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
\(=\frac{2^{10}}{2^{10}}-\frac{2^5.\left(3.5\right)^3}{\left(2.3\right)^3.\left(2.5\right)^2}=1-\frac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}=1-\frac{2^5.3^3.5^3}{2^5.3^3.5^2}=1-5=-4\)
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\(\frac{2^4.2^6}{\left(2^5\right)^2}\)-\(\frac{2^5.15^3}{6^3.10^2}\)
\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
\(=\frac{2^{10}}{2^{10}}-\frac{2^5.5^3.3^3}{2^3.3^3.2^2.5^2}\)
\(=1-\frac{2^5.5^3.3^3}{2^5.3^3.5^2}\)
\(=1-5\)
\(=-4\)
Học tốt
Trả lời:
\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
\(=\frac{2^{10}}{2^{10}}-\frac{2^5.\left(3.5\right)^3}{\left(2.3\right)^3.\left(2.5\right)^2}\)
\(=1-\frac{2^5.3^3.5^3}{2^3.3^3.2^2.5^2}\)
\(=1-\frac{2^5.3^3.5^3}{2^5.3^3.5^2}\)
\(=1-5\)
\(=-4\)
Học tốt
\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
GIÚP MK VỚI
giúp mk với mk tick cho giúp với
Tính x, y
\(3x=y\); \(5y=4z\) và \(6x+7y+8z=456\)
\(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{7}\) và \(2x+3y-z=-14\)
Thực hiện phép tính:
\(\dfrac{2^4.2^6}{\left(2^5\right)^2}\)-\(\dfrac{2^5.15^3}{6^3.10^2}\)
\(\dfrac{x}{3}=\dfrac{y}{5}=\dfrac{z}{7}\) =>\(\dfrac{2x}{6}=\dfrac{3y}{15}=\dfrac{z}{7}\) và 2x+3y-z=-14
Áp dụng dãy tỉ số băng nhau ta có \(\dfrac{2x}{6}=\dfrac{3y}{15}=\dfrac{z}{7}=\dfrac{2x+3y-z}{6+15-7}=\dfrac{-14}{14}=-1\)
=>\(\dfrac{2x}{6}=-1\Rightarrow x=-3\)
\(\dfrac{3y}{15}=-1\Rightarrow y=-5\)
\(\dfrac{z}{7}=-1\Rightarrow z=-7\)
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\(\dfrac{2^4\times2^6}{\left(2^5\right)^2}-\dfrac{2^5\times15^3}{6^3\times10^2}\)
\(=\dfrac{2^{10}}{2^{10}}-\dfrac{2^5\times\left(3\times5\right)^3}{\left(2\times3\right)^3\times\left(2\times5\right)^2}\)
\(=1-\dfrac{2^5\times3^3\times5^3}{2^3\times3^3\times2^2\times5^2}\)
\(=1-5\)
\(=-4\)
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TÍNH:
a)\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
b)\(\frac{1}{2}.\sqrt{100}-\sqrt{\frac{1}{16}}+\left(\frac{1}{3}\right)^0\)
Thực hiện phép tính:
a) \(\left(\frac{1}{3}\right)^{50}.\left(-9\right)^{25}.\frac{2}{3}:4\)
b) \(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
a) (1/3)50 . (-9)25 .2/3:4
= (1/3)50 . [-(3)50] . 2/3 . 1/4
= - (1/3.3)50 . 1/6
= -1 . 1/6 = -1/6
b) (24.26)/(25)2 - (25.153)/(63.102)
= 210/210 - (25.33.53)/(23.33.22.52)
= 1- (25.33.53)/(25.33.52)
= 1- 5
= -4
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