tìm x biết: 1+2x/36 = 1+4x/48 = 1+6x/6x
Những câu hỏi liên quan
1. Tìm x biết
a. 1440:[41-(2x-5)] =2^4 x3
b, 3x(1-4x)+2x(6x-1) =x-18
c, (2x+1)^3 -72 = (-45)
d, 4^2x-1 +18 = 48+36
e, Tìm x thuốc Z để 2x-1/ x-3 nguyên
1e) Để \(\frac{2x-1}{x-3}\) nguyên thì \(2x-1⋮x-3\)
\(\Leftrightarrow2x-6+5⋮x-3\)
\(\Leftrightarrow2\left(x-3\right)+5⋮x-3\)
Do \(2\left(x-3\right)⋮x-3\) \(\Rightarrow5⋮x-3\)
\(\Rightarrow x-3\in\left\{-5;-1;1;5\right\}\)
\(\Leftrightarrow x\in\left\{-2;2;4;8\right\}\)
Vậy:...................
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: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )30 b) 2x(3-2x) + 2x(2x-1)15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)1 d) (x+2) (x+2)- (x -3)(x+1) 9
e) (4x+1)(6x-3) 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) 14
Đọc tiếp
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )=30 b) 2x(3-2x) + 2x(2x-1)=15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)=1 d) (x+2) (x+2)- (x -3)(x+1) = 9
e) (4x+1)(6x-3) = 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) =14
`@` `\text {Ans}`
`\downarrow`
`a)`
`3x(4x-1) - 2x(6x-3) = 30`
`=> 12x^2 - 3x - 12x^2 + 6x = 30`
`=> 3x = 30`
`=> x = 30 \div 3`
`=> x=10`
Vậy, `x=10`
`b)`
`2x(3-2x) + 2x(2x-1) = 15`
`=> 6x- 4x^2 + 4x^2 - 2x = 15`
`=> 4x = 15`
`=> x = 15/4`
Vậy, `x=15/4`
`c)`
`(5x-2)(4x-1) + (10x+3)(2x-1) = 1`
`=> 5x(4x-1) - 2(4x-1) + 10x(2x-1) + 3(2x-1)=1`
`=> 20x^2-5x - 8x + 2 + 20x^2 - 10x +6x - 3 =1`
`=> 40x^2 -17x - 1 = 1`
`d)`
`(x+2)(x+2)-(x-3)(x+1)=9`
`=> x^2 + 2x + 2x + 4 - x^2 - x + 3x + 3=9`
`=> 6x + 7 =9`
`=> 6x = 2`
`=> x=2/6 =1/3`
Vậy, `x=1/3`
`e)`
`(4x+1)(6x-3) = 7 + (3x-2)(8x+9)`
`=> 24x^2 - 12x + 6x - 3 = 7 + (3x-2)(8x+9)`
`=> 24x^2 - 12x + 6x - 3 = 7 + 24x^2 +11x - 18`
`=> 24x^2 - 6x - 3 = 24x^2 + 18x -11`
`=> 24x^2 - 6x - 3 - 24x^2 + 18x + 11 = 0`
`=> 12x +8 = 0`
`=> 12x = -8`
`=> x= -8/12 = -2/3`
Vậy, `x=-2/3`
`g)`
`(10x+2)(4x- 1)- (8x -3)(5x+2) =14`
`=> 40x^2 - 10x + 8x - 2 - 40x^2 - 16x + 15x + 6 = 14`
`=> -3x + 4 =14`
`=> -3x = 10`
`=> x= - 10/3`
Vậy, `x=-10/3`
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tìm x biết
a) (6x-3) (2x+4) + (4x-1) (5-3x) = -21
b) 6x (3x+5) - 2x (9x-2) + (17-x) (x-1) + x (x-18) =0
c) (15-2x) (4x+1) - (13-4x) (2x-3) - (x-1) (x+2) + x2=52
d) (8x-3) (3x+2) - (4x+7) (x+4) = (2x+1) (5x-1) - 33
Rút gọn hết ta được :
a/ 41x - 17 = -21
=> 41x = -4 => x = 4/41
b/ 34x - 17 = 0
=> 34x = 17
=> x = 17/34 = 1/2
c/ 19x + 56 = 52
=> 19x = -4
=> x = -4/19
d/ 20x2 - 16x - 34 = 10x2 + 3x - 34
=> 10x2 - 19x = 0
=> x(10x - 19) = 0
=> x = 0
hoặc 10x - 19 = 0 => 10x = 19 => x = 19/10
Vậy x = 0 ; x = 19/10
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Rút gọn hết ta được :
a/ 41x - 17 = -21
=> 41x = -4 => x = 4/41
b/ 34x - 17 = 0
=> 34x = 17
=> x = 17/34 = 1/2
c/ 19x + 56 = 52
=> 19x = -4
=> x = -4/19
d/ 20x 2 - 16x - 34 = 10x 2 + 3x - 34
=> 10x 2 - 19x = 0
=> x(10x - 19) = 0
=> x = 0 hoặc 10x - 19 = 0
=> 10x = 19
=> x = 19/10
Vậy x = 0 ; x = 19/10
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a) ( 6x - 3 ) ( 2x + 4 ) + ( 4x - 1 ) ( 5 - 3x ) = -21
<=> 12x2 + 24x - 6x - 12 + 20x - 12x2 - 5 + 3x = -21
<=> 41x = -21 + 12 + 5
<=> 41x = -4
<=> x = -4/41
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Xem thêm câu trả lời
Tìm số nguyên x, biết:a)
1
2
x
:
8
−
1
14
b)
25
30
2
x
+
3
6
c)
6
x
−
3...
Đọc tiếp
Tìm số nguyên x, biết:
a) 1 2 = x : 8 − 1 14
b) 25 30 = 2 x + 3 6
c) 6 x − 3 = 9 2 x − 7
d) − 7 x + 1 = 6 x + 27
a) (x: 8 - l).2 = 1.14 nên x : 8 - 1 = 7. Do đó x = 64.
b) (2x + 3).30 = 25.6 nên 2x + 3 = 5. Do đó x = 1.
c) 6.(2x - 7) = 9.(x - 3) nên 12x - 42 = 9x - 27.
Do đó 3x = 15. Vậy x = 5.
d) -7.(x + 27) = 6.(x + l) nên -7x - 189 = 6x + 6.
Do đó 13x = -195. Vậy x = -15.
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d,5x+10/4x-8.4-2x/x+2
Bài 2: rút gọn
a, 6x ² y ³/8x ³y ²
b, x ³-x/3x+3
c, x ²+3xy/x ²-9y ²
d, x ²+4x+4/3x+6
Bài 3: Thực hiện phép tính
a, (x/x-3+(9-6x/x ²-3x)
b, 1/x-1/x+1
c, (x-12/6x-36)+(6/x ²-6x)
d, (6x-3/x):(4x ²-1/3x ²)
e, (x+y/2x-2y)-(x-y/2x+2y)-(y ²+x ²/y ²-x ²)
f, 7x+6/2x(x+7)-3x+6/2x ²+14x
g, (2/x+2-4/x ²+4x+4):(2/x ²-4+1/2-x)
tìm x biết:
1/2x +1/6x+1/12x+1/20x+1/30x+1/42x=36
=1/x*(1/2+1/6+1/12+1/20+1/30+1/42).
Ta có:
1/2+1/6+1/12+1/20+1/30+1/42.
=1/1*2+1/2*3+1/3*4+1/4*5+1/5*6+1/6*7.
=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7.
=1-1/7.
=6/7.
=>1/x*6/7=36.
=>1/x=36:6/7=42.
=>x=1/42.
Vậy x=1/42.
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Tìm x biết
1. 2(5x-8)-3(4x-5)=4(3x-4)+11
2. (2x+1)2-(4x-1).(x-3)-15=0
3. (3x-1).(2x-7)-(1-3x).(6x-5)=0
1) \(\Rightarrow10x-16-12x+15=12x-16+11\)
\(\Rightarrow14x=4\Rightarrow x=\dfrac{2}{7}\)
2) \(\Rightarrow4x^2+4x+1-4x^2+13x-3-15=0\)
\(\Rightarrow17x=17\Rightarrow x=1\)
3) \(\Rightarrow\left(3x-1\right)\left(2x-7+6x-5\right)=0\)
\(\Rightarrow\left(2x-3\right)\left(3x-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
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2: Ta có: \(\left(2x+1\right)^2-\left(4x-1\right)\left(x-3\right)-15=0\)
\(\Leftrightarrow4x^2+4x+1-4x^2+12x+x-3-15=0\)
\(\Leftrightarrow17x=17\)
hay x=1
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bài 1
tìm x
a, 5(x+3)-6x-2x^2=0
b, 6x(x^2-2)-(2-x^2)=0
c, 4x(x-2017)-x+2017=0
d, 12x=x^2+36
bài 1 : tìm x
b, x(2x-5)+(4x mũ 3 - 6x mũ 2 - 6x):(-2x)=19
=>2x^2-5x-2x^2+3x+3=19
=>-2x=16
=>x=-8
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