a) 5.3²⁰²³ = 50.3²⁰²³ - 5.9ˣ

5.9ˣ = 50.3²⁰²³ - 5.3²⁰²³

5.(3²)ˣ = 5.3²⁰²³.(10 - 1)

5.(3²)ˣ = 5.3²⁰²³.9

3²ˣ = 3²⁰²³.3²

3²ˣ = 3²⁰²⁵

2x = 2025

x = 2025/2

b) 2.3ˣ + 5.3ˣ⁺¹ = 153

3ˣ.(2 + 5.3) = 153

3ˣ.17 = 153

3ˣ = 153/17

3ˣ = 9

3ˣ = 3²

x = 2

a) 3^{x + 2} + 5.3^{x + 1} = 648

<=> 3^{x + 1}.8 = 648

<=> 3^{x + 1} = 81

<=> 3^{x + 1} = 3⁴ 

<=> x + 1 = 4

<=> x = 3

Sửa lại đề: b) 2^{2x + 1}  + 2^{2x + 4} = 3².8⁴

<=> 2^{2x + 1}.9 = 3² . 8⁴ 

<=> 2^{2x + 1} = 8⁴ 

<=> 2^{2x + 1}  = 2¹² 

<=> 2x + 1 = 12 

<=> \(x=\dfrac{11}{2}\)

3^x-1+5.3^x-1=162

=>3^x-1.(1+5)=162

=>3^x-1.6=162=>3^x-1=162:6=27=3³

=>x-1=3=>x=4

5^x+5^x+2=650

=>5^x+5^x.5²=650

=>5^x.(1+25)=650

=>5^x.26=650=>5^x=650:26=25=5²

=>x=2

Ta co

\(3^x:9+5.3^x.3=408\)

\(3^x.\frac{1}{9}+15.3^x=408\)

\(3^x.\left(\frac{1}{9}+15\right)=408\)

\(3^x\cdot\frac{136}{9}=408\)

\(3^x=27\)

\(\Rightarrow3^x=3^3\)

\(\Rightarrow x=3\)

\(2^{x+2}-2^x=96\)

\(\Rightarrow2^x\cdot2^2-2^x=96\)

\(\Rightarrow2^x\left(2^2-1\right)=96\)

\(\Rightarrow2^x\left(4-1\right)=96\)

\(\Rightarrow2^x\cdot3=96\)

\(\Rightarrow2^x=96:3\)

\(\Rightarrow2^x=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

\(5^x+5^{x+1}=750\)

\(\Rightarrow5^x+5^x\cdot5=750\)

\(\Rightarrow5^x\left(1+5\right)=750\)

\(\Rightarrow5^x\cdot6=750\)

\(\Rightarrow5^x=750:6\)

\(\Rightarrow5^x=125\)

\(\Rightarrow5^x=5^3\)

\(\Rightarrow x=3\)

\(2^{x+3}+2^x=144\)

\(\Rightarrow2^x\cdot2^3+2^x=144\)

\(\Rightarrow2^x\left(2^3+1\right)=144\)

\(\Rightarrow2^x\cdot9=144\)

\(\Rightarrow2^x=144:9\)

\(\Rightarrow2^x=16\)

\(\Rightarrow2^x=2^4\)

\(\Rightarrow x=4\)

2x+ 3= x+ 2
2x- x= 2- 3
x= -1
vậy x=-1
b) \(3^{x-1}+5.3^{x-1}=162 \) 

\(3^{x-1}.\left(1+5\right)=162\)

\(3^{x-1}.6=162\)

\(3^{x-1}=162:6\)\(\Rightarrow3^{x-1}=27\)

\(3^{x-1}=3^3\)

\(\Rightarrow x-1=3\)

\(\Rightarrow x=4\)

giúp mk vs xin các bạn 

please

=(((((