tìm x : a) (x + 1)^3 + (3 - 2)^3 = 2x^3 + 2(2x - 1)^2 - 9
b) (3x^3+24) : (x+2) + (2x^3−54) : (x^2+3x+9) = 6
Tìm x, biết:
a) (x-3)(x^2+ 3x +9)+x(2+x)(2x-x)=1
b) (x+3)^3 -x(3x+1)^2+(2x+1)(4x-2x+1)=54
Tìm x
a,(x+3)3-x(2x+1)2+(2x+1)(4x2-2x+1)-3x2=54
b,(x-3)3-(x-3)(x2+3x+9)+6(x+1)2+3x2=33
tìm x biết
a) (x+3)2-x(3x+1)2+(2x+1)(4x2-2x+1)-2x2=54
b)(x+3)3-(x-3)(x2+3x+9)+6(x+1)2+3x2=-33
a) \(\left(x+3\right)^2-x\left(3x+1\right)^2+\left(2x+1\right)\left(4x^2-2x+1\right)-2x^2=54\)
=> x2 + 6x + 9 - x(9x2 + 6x + 1) + (2x)3 + 13 - 2x2 = 54
=> x2 + 6x + 9 - 9x3 - 6x2 - x + 8x3 + 1 - 2x2 = 54
=> (-9x3 + 8x3) + (x2 - 6x2 - 2x2) + (6x - x) + (9 + 1) = 54
=> -x3 - 7x2 + 5x + 10 = 54
=> -(x3 + 7x2 - 5x - 10) = 54
=> phương trình vô nghiệm
b) (x + 3)3 - (x - 3)(x2 + 3x + 9) + 6(x + 1)2 + 3x = -33
=> x3 + 9x2 + 27x + 27 - (x3 - 33) + 6(x2 + 2x + 1) + 3x = -33
=> x3 + 9x2 + 27x + 27 - x3 + 27 + 6x2 + 12x + 6 + 3x = -33
=> (x3 - x3) + (9x2 + 6x2) + (27x + 12x + 3x) + (27 + 27 + 6) = -33
=> 15x2 + 42x + 60 = -33
=> 15x2 + 42x + 60 + 33 = 0
=> 15x2 + 42x + 93 = 0
=> 3(5x2 + 14x + 31) = 0
=> 5x2 + 14x + 31 = 0
=> không tìm được x
Chủ đề 1: Thực hiện phép tính
1) (2x+3).(2x-3)-4x.(x+5)
2) 6/x2 - 9 + 5/x-3 + 1/x+3
3)5x.(x-3)+(x-2)2
4) 4x/x+2 - 3x/x-2 + 12x/ x2 - 4
5) x(x+2) - ( x-3)(x+3)
6) 1/3x-2 + -4/3+2 + 6-3x/9x2 - 4
7)2x.(3x-1)+(x+2)2
8) 6/x+3 - 6/x-3 + 9x+9/x2 - 9
9) (2x - 5)2 - x(4x-13)
10) x-1/x + 4/x+8 + 8/x2 + 8x
11) (2x+1)2 + (x-5)(x+5)-x(5x+7)
12) 6/x2-9 + 5/x-3 + 1/x+3
13) 6x(5x-2)+(2x+3)2
14) x/x-2 + -2/x-3 + x(1-x)/x2-9
15) (x-2)2-x(x+5)
16) 2/x+3 + 3/x-3 + -6/x2-9
17) 3x(x-3) + (3x-1)2
\(\left(2x+3\right)\left(2x-3\right)-4x\left(x+5\right)=4x^2-9-4x^2-20x=-20x-9\)
\(5x\left(x-3\right)+\left(x-2\right)^2=5x^2-15x+x^2-4x+4=6x^2-19x+4\)
\(x\left(x+2\right)-\left(x-3\right)\left(x+3\right)=x^2+2x-\left(x^2-9\right)=x^2+2x-x^2+9=2x+9\)
tìm x,biết
a) (x+3)3 - x(3x+1)2 + (2x+1)(4x2 - 2x + 1) - 3x2 = 54
b) (x-3)3 - (x-3)(x2+3x+9) + 6(x+1)2 + 3x2 = -33
\(\left(x-3\right)\left(x^2-6x+9-x^2-3x-9\right)+9x^2+12x+39=0\)
\(\Leftrightarrow-9x\left(x-3\right)+9x^2+12x+39=0\)
\(\Leftrightarrow39x+39=0\Rightarrow x=-1\)
Câu a bạn tính ra rồi giải nha
Tìm x
a,(x+3)3-x(2x+1)2+(2x+1)(4x2-2x+1)-3x2=54
b,(x-3)3-(x-3)(x2+3x+9)+6(x+1)2+3x2=33
a: \(\left(x+3\right)^3-x\left(2x+1\right)^2+\left(2x+1\right)\left(4x^2-2x+1\right)-3x^2=54\)
\(\Leftrightarrow x^3+9x^2+27x+27+8x^3+1-3x^2-x\left(2x+1\right)^2=54\)
\(\Leftrightarrow9x^3+6x^2+27x+28-4x^3-4x^2-x-54=0\)
\(\Leftrightarrow5x^3+2x^2+26x-26=0\)
\(\Leftrightarrow x\simeq0,835\)
b: \(\left(x-3\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+6\left(x+1\right)^2+3x^2=33\)
\(\Leftrightarrow x^3-9x^2+27x-27-x^3+27+6x^2+12x+6+3x^2=33\)
\(\Leftrightarrow39x-21=33\)
=>39x=54
hay x=18/13
Tìm x biết
a) x(x-5) (x+5)-(x+2) (x2-2x+4)=3
b) (x+3)3-x(3x+1)2+(2x+1) (4x2-2x+1)-3x2=54
c) (x-3)2-(x-3) (x2+6x+9)+6(x+1)2+3x2=-33
\(a.x\left(x-5\right)\left(x+5\right)-\left(x+2\right)\left(x^2-2x+4\right)=3\)
\(\Leftrightarrow x\left(x^2-5^2\right)-\left(x^3+2^3\right)=3\)
\(\Leftrightarrow x^3-25x-x^3-8=3\)
\(\Leftrightarrow x^3-x^3-25x=8+3\)
\(\Leftrightarrow x=\frac{11}{-25}\)
Vậy x có nghiệm là \(\frac{-11}{25}.\)
\(\)
Rút gọn biểu thức:
1.(x+3)(x^2-3x+9)-(54+x^2)
2.(a+b)^2-(a-b)^2
3.(x-3)(x+3)-(x-3)^2
4.(2x+1)^2+2(2x+1)(3x-1)+(3x-1)^2.
Bài 1 : Tìm thương Q và dư R sao cho A= B.Q+R biết ;
a) A = \(x^4+3x^3+2x^2-x-4\) và B = \(x^2-2x+3\)
b) A = \(2x^3-3x^2+6x-4\) và B = \(x^2-x+3\)
c) A = \(2x^4+x^3+3x^2+4x+9\) và B = \(x^2+1\)
d) A = \(2x^3-11x^2+19x-6\) và B = \(x^2-3x+1\)
c) A= \(2x^4-x^3-x^2-x+1\) và B = \(x^2+1\)