tìm x
a/ (5 3/8 + x - 7 5/24) : 16 2/3 = 1
bài 1: tìm x
a) 8/23 . 46/24 = 1/3 . x
b) 1/5 : x = 1/5 - 1/7
c) 4/9 - (x - 1/2) mũ 2 = 1/3
d)3,2 . x - (4/5 + 2/3) : 3 2/3 = 7/10
` 8/23 . 46/24 =1/3 .x`
`=>8/23 . 23/12 =1/3 . x`
`=> 1/3 . x=2/3`
`=>x=2/3 : 1/3`
`=>x=2/3 . 3`
`=> x= 6/3`
`=>x=2`
`----`
`1/5 : x= 1/5-1/7`
`=>1/5 : x= 7/35 - 5/35`
`=> 1/5 :x= 2/35`
`=>x= 1/5 : 2/35`
`=>x=1/5 . 35/2`
`=>x=7/2`
`----`
`4/9 - (x-1/2)^2 =1/3`
`=> (x-1/2)^2 =4/9-1/3`
`=> (x-1/2)^2 =4/9- 3/9`
`=> (x-1/2)^2 =1/9`
`=> (x-1/2)^2 = (+- 1/3)^2`
`@ TH1`
`x-1/2=1/3`
`=>x=1/3+1/2`
`=>x= 2/6 + 3/6`
``=>x= 5/6`
`@ TH2`
`x-1/2=-1/3`
`=>x=-1/3 +1/2`
`=>x= -2/6 + 3/6`
`=>x=1/6`
`----`
`3,2 . x-(4/5+2/3) : 3 2/3 = 7/10`
`=> 3,2 . x-22/15 : 11/3 = 7/10`
`=> 3,2 . x-22/15 = 7/10 . 11/3`
`=> 3,2 . x-22/15 =77/30`
`=> 3,2 .x= 77/30 + 22/15`
`=> 3,2 .x=121/30`
`=>x= 121/30. 5/16`
`=>x= 121/96`
Tìm x biết:
1-(\(5\dfrac{3}{8}\)+x\(-7\dfrac{5}{24}\)):(\(-16\dfrac{2}{3}\))=0
`1-(5 3/8+x-7 5/24):(-16 2/3)=0`
`=>1-(5+3/8+x-7-5/24):(-50/3)=0`
`=>1=(x-2-11/6):(-50/3)`
`=>1=(x-11/6):(-50/3)`
`=>x-11/6=-50/3`
`=>x=-89/6`
Vậy `x=-89/6`
\(1-\left(5\dfrac{3}{8}+x-7\dfrac{5}{24}\right):\left(-16\dfrac{2}{3}\right)=0\)
\(\Leftrightarrow1-\left(\dfrac{43}{8}+x-\dfrac{173}{24}\right):\dfrac{50}{3}=0\)
\(\Leftrightarrow1-\left(\dfrac{129}{24}-\dfrac{173}{24}+x\right).\dfrac{3}{50}=0\)
\(\Leftrightarrow1+\dfrac{11}{6}-x.\dfrac{3}{50}=0\)
\(\Leftrightarrow\dfrac{17}{6}-x.\dfrac{3}{50}=0\)
\(\Leftrightarrow x.\dfrac{3}{50}=\dfrac{17}{6}\)
\(\Leftrightarrow x=\dfrac{425}{9}\)
-Chúc bạn học tốt-
\(1-\left(5\dfrac{3}{8}+x-7\dfrac{5}{24}\right):\left(-16\dfrac{2}{3}\right)=0\)
\(1-\left(\dfrac{43}{8}:\dfrac{-50}{3}+x:\dfrac{-50}{3}-\dfrac{173}{24}:\dfrac{-50}{3}\right)=0\)
\(1-\dfrac{-129}{400}-x:\dfrac{-50}{3}+\dfrac{-173}{400}=0\)
\(\left(1+\dfrac{129}{400}+\dfrac{-173}{400}\right)-x:\dfrac{-50}{3}=0\)
\(\dfrac{89}{100}-x:\dfrac{-50}{3}=0\)
\(x:\dfrac{-50}{3}=\dfrac{89}{100}-0\)
\(x:\dfrac{-50}{3}=\dfrac{89}{100}\)
\(x=\dfrac{89}{100}.\dfrac{-50}{3}\)
\(x=\dfrac{-89}{6}\)
Tìm x
1-(5 3/8+X-7 5/24)=-16 2/3
/X+1/5/ -4=3/2
Tìm x,y biết :
a) 1-(5/3/8+x-7/5/24): 16/2/3=0
b) (1/6+2/1/12-10,75).x-7= (2/5+3/8-2,225): 0,1
người ta ko bt thì hỏi , đừng có mak ns mấy câu vô văn hóa thế nhá
Tìm x
a) (-12) .x -14 = -2
b)(-8).x= (-5).(-7) -3
c) (-9) .x + 3 = (-2) . (-7) + 16
a.\(\left(-12\right)x-14=-2\)
\(\left(-12\right)x=-2+14\)
\(\left(-12\right)x=12\)
\(x=12:\left(-12\right)\)
\(x=-1\)
\(b,\left(-8\right)x=\left(-5\right)\left(-7\right)-3\)
\(\left(-8\right)x=35-3\)
\(\left(-8\right)x=32\)
\(x=32:\left(-8\right)\)
\(x=-4\)
\(c,\left(-9\right)x+3=\left(-2\right)\left(-7\right)+16\)
\(\left(-9\right)x+3=14+16\)
\(\left(-9\right)x+3=30\)
\(\left(-9\right)x=30-3\)
\(\left(-9\right)x=27\)
\(x=27:\left(-9\right)\)
\(x=-3\)
Bài 1: Tìm x
x-7/12.x=5/24-3/8.x
(x-1/2).(-3-x/2)=0
x-3/-2=-8/x-3
=) (x-3).(x-3)=(-2).(-8)
(x-3) mũ 2 =16
\(a,x-\dfrac{7}{12}x=\dfrac{5}{24}-\dfrac{3}{8}x\)
\(\Leftrightarrow\dfrac{5}{12}x+\dfrac{3}{8}x=\dfrac{5}{24}\)
\(\Leftrightarrow\dfrac{19}{24}x=\dfrac{5}{24}\Leftrightarrow x=\dfrac{5}{19}\)
Vậy x = 5/19
\(b,\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=0\\-3-\dfrac{x}{2}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-6\end{matrix}\right.\)
Vậy x = 1/2 hoặc x = -6
\(c,\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\)
\(\Leftrightarrow\left(x-3\right)^2=16\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=4\\x-3=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)
Vậy x = 7 hoặc x = -1
Tìm x biết :
3 - ( 5 / 3 / 8 + x - 7 / 5 / 24) : 16 / 2 /3 = 2
\(3-\left(\frac{5}{\frac{3}{8}}+x-\frac{7}{\frac{5}{24}}\right):\frac{16}{\frac{2}{3}}=2\)
\(\Rightarrow3-\left(\frac{40}{3}+x-\frac{168}{5}\right):24=2\)
\(\Rightarrow\left(-\frac{304}{15}+x\right):24=1\)
\(\Rightarrow\frac{-304}{15}+x=24\)
\(\Rightarrow x=\frac{664}{15}\)
\(3-\left(\frac{5}{\frac{3}{8}}+x-\frac{7}{\frac{5}{24}}\right):\frac{16}{\frac{2}{3}}=2\)
\(\left(\frac{40}{3}+x-\frac{28}{5}\right):24=3-2\)
\(\left(\frac{40}{3}+x-\frac{28}{5}\right):24=1\)
\(\frac{40}{3}+x-\frac{28}{5}=1\cdot24\)
\(\frac{116}{15}+x=24\)
\(x=24-\frac{116}{15}\)
\(x=\frac{244}{15}\)
Bài 2: Tìm x
a) x - 2/11 = -5/11
b) x - 1/24 = -1/8 + 5/6
c) 5/8 - x = 1/9 - (-5/4)
d) 8/23 . 46/24 - x = 1/3
e) 1/5 : x = 1/5 + 1/7
a: x=-5/11+2/11=-3/11
b: =>x=-3/24+20/24+1/24=18/24=3/4
c: =>5/8-x=1/9+5/4=4/36+45/36=49/36
=>x=5/8-49/36=-53/72
d: =>2/3-x=1/3
=>x=1/3
e: =>1/5:x=12/35
=>x=7/12
Tìm x
a) 4/5 ( x - 1/3) - \(3\dfrac{1}{2}\)= 50%
b) \(8\dfrac{3}{5}\cdot x-2\dfrac{1}{5}\cdot x=16\%\)
a) \(\dfrac{4}{5}\left(x-\dfrac{1}{3}\right)-3\dfrac{1}{2}=50\%\)
\(\dfrac{4}{5}x-\dfrac{4}{15}-\dfrac{7}{2}=\dfrac{1}{2}\)
\(\dfrac{4}{5}x=\dfrac{1}{2}+\dfrac{7}{2}+\dfrac{4}{15}\)
\(\dfrac{4}{5}x=\dfrac{64}{15}\)
\(x=\dfrac{64}{15}:\dfrac{4}{5}\\ x=\dfrac{16}{3}\)
b) \(8\dfrac{3}{5}.x-2\dfrac{1}{5}.x=16\%\)
\(\dfrac{43}{5}x-\dfrac{11}{5}x=\dfrac{4}{25}\)
\(\dfrac{32}{5}x=\dfrac{4}{25}\)
\(x=\dfrac{4}{25}:\dfrac{32}{5}\)
\(x=\dfrac{1}{40}\)