Tính : C=1/2^2+1/2^4+1/2^6+1/2^8+…+1/2^50
Giúp mik vs ạ, cần gấp
\(A=\frac{\left[\left(25-1\right):1+1\right]\left(25+1\right)}{2}=325.\)
\(B=\frac{\left[\left(51-3\right):2+1\right]\left(51+3\right)}{2}=675\)
\(C=\frac{\left[\left(81-1\right):4+1\right]\left(81+1\right)}{2}=861\)
B = (1 - 1/2) + (1 - 1/4) + (1 - 1/8) + ...+ (1 - 1/512) + (1 - 1/1024)
Mọi ng giúp mik bài này vs ạ. Mik đg cần gấp. Thanks!
c) 2x = 5y và x – y = 15 d)x/2 = y/5 và xy = 10
e)x-1/2 = y-2/3 = z-3/4 và 2x +3y - z = 50
giúp mk vs ạ
c) Ta có:
2x=5y=>x/5=y/2
Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
x/5=y/2=x-y/5-2=15/3=5
=> x=5.5=25; y=5.2=10
d)Đặt x/2=y/5=k
=> x=2k; y=5k=> xy=2k.5k=10k^2=10=> k^2=1=>k=\(\pm\)1
Với k=1=>x=2; y=5
Với k=-1=>x=-2; y=-5
Tính A= 1*2+2*4+3*6+4*8+5*10+6*12/3*4+6*8+9*12+12*16+15*20+18*24
Giúp mik nha m.n mik đang cần gấp ạ😊😊😊😊
Bạn vào:câu hỏi của :Vũ Ngân Hà -olm
\(A=\frac{1\cdot2+2\cdot4+3\cdot6+4\cdot8+5\cdot10+6\cdot12}{3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20+18\cdot24}\)
\(A=\frac{2\cdot3\left[1\cdot2\right]+2\cdot3\left[2\cdot4\right]+2\cdot3\left[3\cdot6\right]+2\cdot3\left[4\cdot8\right]+2\cdot3\left[5\cdot10\right]}{3\cdot4\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}\)
\(A=\frac{\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}{2\cdot3\left[3\cdot4+6\cdot8+9\cdot12+12\cdot16+15\cdot20\right]}=\frac{1}{2\cdot3}=\frac{1}{6}\)
1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111
a.x/5=2/5 , b.3/-8=6/-x , c.1/9=-2x/10 , d.3/x-5=-9/x+2 , e.x/-2=-8/x , g.(x+2)mụ2=-8/x , h.-24/-6=1/3=4/y muj2 mik đg cần gấp ạ ,cảm ơn nhiều
a) \(\dfrac{x}{5}=\dfrac{2}{5}\)
\(\Rightarrow5x=10\)
\(\Leftrightarrow x=2\)
Vậy x = 2
b) ĐKXĐ: \(x\ne0\)
\(\dfrac{3}{-8}=\dfrac{6}{-x}\)
\(\Rightarrow-3x=-48\)
\(\Leftrightarrow x=16\)
Vậy x = 16
c) \(\dfrac{1}{9}=\dfrac{-2x}{10}\)
\(\Rightarrow-18x=10\)
\(\Leftrightarrow x=-\dfrac{5}{9}\)
Vậy \(x=-\dfrac{5}{9}\)
d) ĐKXĐ: \(x\ne0\)
\(\dfrac{3}{x}-5=\dfrac{-9}{x}+2\)
\(\Leftrightarrow\dfrac{3-5x}{x}=\dfrac{-9+2x}{x}\)
\(\Rightarrow3-5x=-9+2x\)
\(\Leftrightarrow7x=12\)
\(\Leftrightarrow x=\dfrac{12}{7}\)
Vậy \(x=\dfrac{12}{7}\)
e) ĐKXĐ: \(x\ne0\)
\(\dfrac{x}{-2}=\dfrac{-8}{x}\)
\(\Rightarrow x^2=16\)
\(\Leftrightarrow x=\pm4\)
Vậy \(x=\pm4\)
a) Ta có: \(\dfrac{x}{5}=\dfrac{2}{5}\)
\(\Leftrightarrow x=\dfrac{2\cdot5}{5}=2\)
Vậy: x=2
b) Ta có: \(\dfrac{3}{-8}=\dfrac{6}{-x}\)
\(\Leftrightarrow-x=\dfrac{6\cdot\left(-8\right)}{3}=-16\)
hay x=16
Vậy: x=16
giúp e vs nha mn, e cần gấp lắm ạ. thanks trc ạ
a, (2^2+1)(2^4+1)(2^8+1)(2^16+1)
b,24(5^2+1)(5^4+1)(5^8+1)(5^16+1)
c,48(7^2+1)(7^4+1)(7^8+1)(7^16+1)
\(\text{a) }\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\\ =\dfrac{3\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}{3}\\ =\dfrac{\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}{3}\\ \\ =\dfrac{\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)}{3}\\ =\dfrac{\left(2^8-1\right)\left(2^8+1\right)\left(2^{16}+1\right)}{3}\\ =\dfrac{\left(2^{16}-1\right)\left(2^{16}+1\right)}{3}\\ =\dfrac{2^{32}-1}{3}\\ \)
\(\text{b) }24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\\ =\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\\ =\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right) \\ =\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\\ =\left(5^{16}-1\right)\left(5^{16}+1\right)\\ =5^{32}-1\\ \)
\(\text{c) }48\left(7^2+1\right)\left(7^4+1\right)\left(7^8+1\right)\left(7^{16}+1\right)\\ =\left(7^2-1\right)\left(7^2+1\right)\left(7^4+1\right)\left(7^8+1\right)\left(7^{16}+1\right)\\ =\left(7^4-1\right)\left(7^4+1\right)\left(7^8+1\right)\left(7^{16}+1\right)\\ =\left(7^8-1\right)\left(7^8+1\right)\left(7^{16}+1\right)\\ =\left(7^{16}-1\right)\left(7^{16}+1\right)\\ =7^{32}-1\)
Tính nhanh:(\(1-\dfrac{1}{2^2}\)).(1-\(\dfrac{1}{3^2}\)).(1-\(\dfrac{1}{4^2}\))...(1-\(\dfrac{1}{10^2}\))
mik đag cần rất gấp giúp mik vs
Giải:
(1-1/22).(1-1/32).(1-1/42).....(1-1/102)
=3/2.2 . 8/3.3 . 15/4.4 . ... . 99/10.10
=1.3.2.4.3.5.....9.11/2.2.3.3.4.4.....10.10
=1.2.3.....9/2.3.4.....10 . 3.4.5....11/2.3.4.....10
=1/10.11/2
=11/20
Chúc bạn học tốt!
Giải phương trình:
a) x+x/x-3+x-2//x+3=2(x^2+6)/x^2-9
b) 2-x/x-1+x-3/x+1=-2x/x^2/x^2-1
Giúp mik vs ạ mik cần gấp
Bạn nên dùng công thức trực quan cho bài toán như thế này nhé.
Các kao nhân giúp toi vs
B1 Tính
A=(0,125)^100*8^111
B=2^13*9^4/6^6*8^3
B2Tìm x
a.
9(x-1)^2-4/9:2/9=1/4
b.(3*x-1)^6=(3x-1)^4
Cảm ơn nhìu!!!!!
Tui cần hơi hơi gấp ạ :((
B1. phân a tui ko bt nha :>
\(B=\frac{2^{13}\cdot9^4}{6^6\cdot8^3}\)
\(=\frac{2^{13}\cdot\left(3^2\right)^4}{\left(2\cdot3\right)^6\cdot\left(2^3\right)^3}\)
\(=\frac{2^{13}\cdot3^8}{2^6\cdot3^6\cdot2^9}\)
\(=\frac{2^{13}\cdot3^8}{2^{15}\cdot3^6}\)
\(=\frac{1\cdot3^2}{2^2\cdot1}\)
\(=\frac{1\cdot9}{4\cdot1}\)
\(=\frac{9}{4}\)