Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang tong sau lon hon 1
N = \(\frac{21}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-1}{45}+\frac{-1}{50}\)
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Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang cac tong sau lon hon 1
N = \(\frac{21}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-1}{45}+\frac{-1}{50}\)
Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang cac tong sau lon hon 1
M = \(\frac{3}{7}+\frac{3}{8}+\frac{3}{10}\)
Khong thuc hien phep tinh de tim ket qua.Hay chung minh rang cac tong sau lon hon 1
M = \(\frac{3}{7}+\frac{3}{8}+\frac{3}{10}\)
Chứng minh tổng sau lớn hơn 1 : \(P=\frac{41}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-11}{45}+\frac{-1}{36}\)
\(P=\frac{41}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-11}{45}+\frac{-1}{36}=\frac{41}{36}>\frac{36}{36}=1\)
Vậy P > 1.
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khong thuc hien phep tinh,hay tim y trong tung phep tinh sau day(nho giai thich do nha)
y+17,28=17,28\(\frac{18}{9}\)x y =2y:6=0\(5\frac{2}{8}\):y=\(5\frac{2}{8}\)
1.y+17,28=17,28
=>y=0
2.18/9x y=2 (chịu)
3.y:6=0
=>y=0
4.\(5\frac{2}{8}:y=5\frac{2}{8}\)
=>\(\frac{5}{4}:y=\frac{5}{4}\)
=>y=1
Nhớ k mk nha
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Chứng minh rằng : Các tổng sau lớn hơn 1
a) \(\frac{3}{8}+\frac{3}{7}+\frac{3}{15}\)
b) \(\frac{41}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-11}{45}+\frac{-1}{36}\)
thuc hien phep tinh
\(2\frac{1}{3}+\left(-0,25\right)+\frac{17}{22}-\frac{3}{4}+\frac{5}{22}\) \(\frac{4}{23}+\frac{5}{21}-\frac{4}{23}+\frac{1}{2}+\frac{16}{21}\)
thuc hien phep tinh \(A=\frac{2.5^{22}-9.5^{21}}{25^{10}}\div\frac{5.\left(3.7^{15}-14\right)}{7^{15}.3.7^{15}}\)
Khong thuc hien phep tinh cong , hay so sanh tong M = 21/23 + 12/37 voi N = 57/59 + 3/8.