Các câu hỏi tương tự
Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang cac tong sau lon hon 1
N = \(\frac{21}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-1}{45}+\frac{-1}{50}\)
Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang cac tong sau lon hon 1
M = \(\frac{3}{7}+\frac{3}{8}+\frac{3}{10}\)
Khong thuc hien phep tinh de tim ket qua.Hay chung minh rang cac tong sau lon hon 1
M = \(\frac{3}{7}+\frac{3}{8}+\frac{3}{10}\)
Chứng minh tổng sau lớn hơn 1 : \(P=\frac{41}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-11}{45}+\frac{-1}{36}\)
Chứng minh rằng : Các tổng sau lớn hơn 1
a) \(\frac{3}{8}+\frac{3}{7}+\frac{3}{15}\)
b) \(\frac{41}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-11}{45}+\frac{-1}{36}\)
khong thuc hien phep tinh o mau , hay so sanh cac phan so sau
a) A = \(\frac{244.395-151}{244+395.243}\)va B=\(\frac{423134.846267-423133}{4423133.846267+423134}\)
Ai giup minh voi
Khong thuc hien phep tinh o mau, hay so sanh cac phan so sau
b) M = \(\frac{53.71-18}{71.555552+53}\); N=\(\frac{54.107-53}{53.107+54}\)va P=\(\frac{135.269-133}{134.269+135}\)
thuc hien phep tinh
\(\frac{6}{7}+\frac{1}{7}.\frac{2}{7}+\frac{1}{7}.\frac{5}{7}\)
a) CHO TONG A = 270 + 3150 + 150 . KHONG THUC HIEN PHEP TINH XET XEM TONG TREN CO CHIA HET CHO 2 ; 3 ; 5 ;9
b) CHO B = 12+ 18 + 21 + x VOI x THUOC N . TIM DIEU KIEN CUA x DE A CHIA HET CHO 3 , DE A KHONG CHIA CHO 3
GIUP MINH VOI CA NHA OI . AI TRA LOI DUNG SE CO 3 LIKE