Tim x biet
a)\(\frac{8}{23}.\frac{46}{24}-x=\frac{1}{3}\)
b) \(\frac{10}{12}:x=\frac{28}{9}.\frac{3}{56}\)
c) \(\frac{x-12}{4}=\frac{1}{2}\)
Những câu hỏi liên quan
1. Tìm x:
a;\(\frac{x+1}{3}=\frac{x-2}{4}\)
b;\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
c;\(\frac{x+3}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\)
a) \(\frac{x+1}{3}=\frac{x-2}{4}\)
=> (x+1).4 = (x - 2) . 3
=> 4x + 4 = 3x - 6
=> 4x - 3x = - 6 - 4
=> x = - 10
b) \(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
\(\Rightarrow\left(\frac{x-6}{7}+1\right)+\left(\frac{x-7}{8}+1\right)+\left(\frac{x-8}{9}+1\right)=\left(\frac{x-9}{10}+1\right)+\left(\frac{x-10}{11}+1\right)+\left(\frac{x-11}{12}+1\right)\)
\(\Rightarrow\frac{x+1}{7}+\frac{x+1}{8}+\frac{x+1}{9}=\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}\)
\(\Rightarrow\frac{x+1}{7}+\frac{x+1}{8}+\frac{x+1}{9}-\frac{x+1}{10}-\frac{x+1}{11}-\frac{x+1}{12}\) = 0
\(\Rightarrow\left(x+1\right).\left(\frac{1}{7}+\frac{1}{8}+\frac{1}{9}-\frac{1}{10}-\frac{1}{11}-\frac{1}{12}\right)\)
Vì \(\frac{1}{7}+\frac{1}{8}+\frac{1}{9}-\frac{1}{10}-\frac{1}{11}-\frac{1}{12}\ne0\) nên x + 1 =0
=> x = -1
c) Xem lại đề
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Tìm x biết
a) x+2x+3x+4x+...+100x=-213
b)\(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)
c)3(x-2)+2(x-1)=10
d)\(\frac{x+1}{3}=\frac{x-2}{4}\)
e)\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
f)\(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\)
#)Giải :
a) x + 2x + 3x + ... + 100x = - 213
=> 100x + ( 2 + 3 + 4 + ... + 100 ) = - 213
=> 100x + 5049 = - 213
<=> 100x = - 5262
<=> x = - 52,62
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#)Giải :
b) \(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)
\(\Rightarrow\frac{1}{2}x+\frac{1}{4}x=\frac{1}{3}+\frac{1}{6}\)
\(\Rightarrow\frac{1}{2}x+\frac{1}{4}x=\frac{1}{2}\)
\(\Rightarrow\left(\frac{1}{2}+\frac{1}{4}\right)x=\frac{1}{2}\)
\(\Rightarrow\frac{3}{4}x=\frac{1}{2}\)
\(\Leftrightarrow x=\frac{2}{3}\)
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a) x + 2x + 3x + ... +100x = -213
=> x . (1 + 2 + 3 +... + 100) = - 213
=> x . 5050 = -213
=> x = - 213 : 5050
=> x = -213/5050
b) \(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)
=> \(\frac{1}{2}x-\frac{1}{4}x=\frac{1}{3}-\frac{1}{6}\)
=> \(x.\left(\frac{1}{2}-\frac{1}{4}\right)=\frac{1}{6}\)
=> \(x.\frac{1}{4}=\frac{1}{6}\)
=> \(x=\frac{1}{6}:\frac{1}{4}\)
=> \(x=\frac{2}{3}\)
c) 3(x-2) + 2(x-1) = 10
=> 3x - 6 + 2x - 2 = 10
=> 3x + 2x - 6 - 2 = 10
=> 5x - 8 = 10
=> 5x = 10 + 8
=> 5x = 18
=> x = 18:5
=> x = 3,6
d) \(\frac{x+1}{3}=\frac{x-2}{4}\)
=> \(4\left(x+1\right)=3\left(x-2\right)\)
=>\(4x+4=3x-6\)
=> \(4x-3x=-4-6\)
=> \(x=-10\)
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a,frac{3}{4}-x1 b,x+4frac{1}{5} c,x-frac{1}{5}2
d,x+frac{5}{3}frac{1}{81} e,x-frac{10}{3}frac{7}{15}.frac{3}{5} g,x+frac{3}{22}frac{27}{121}.frac{11}{9}
h,1-xfrac{49}{65}.frac{5}{7} i,frac{8}{23}.frac{46}{24}-xfrac{1}{3} k,frac{62}{7}.xfrac{29}{9}:frac{3}{56}
Đọc tiếp
\(a,\frac{3}{4}-x=1\) \(b,x+4=\frac{1}{5}\) \(c,x-\frac{1}{5}=2\)
\(d,x+\frac{5}{3}=\frac{1}{81}\) \(e,x-\frac{10}{3}=\frac{7}{15}.\frac{3}{5}\) \(g,x+\frac{3}{22}=\frac{27}{121}.\frac{11}{9}\)
\(h,1-x=\frac{49}{65}.\frac{5}{7}\) \(i,\frac{8}{23}.\frac{46}{24}-x=\frac{1}{3}\) \(k,\frac{62}{7}.x=\frac{29}{9}:\frac{3}{56}\)
- Thiếu đề bài bạn ơi !!
- Nếu là giải phương trình thì nghĩ bạn nên tự làm bởi toàn là chuyển vế cơ bản ỷ lại quá sẽ khó để làm đến phần thông hiểu, nâng cao ,.... nha
- Nếu cần kết quả để xem đúng hay sai thì ấn hỏi mình hoặc các bạn khác cũng được nha !
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- Vì bạn giải xong nên mình đưa kết quả bạn soát nha :
\(a,x=-\frac{1}{4}.b,x=-\frac{19}{5}.c,x=\frac{11}{5}.d,x=-\frac{134}{81}.e,x=\frac{271}{75}\)
\(g,x=\frac{3}{22}.h,x=\frac{6}{13}.i,x=\frac{1}{3}.k,\frac{5684}{837}\)
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Bài 1:Tìm x,biết
a) x-frac{20}{11.13}-frac{20}{13.15}-frac{20}{15.17}-...-frac{20}{53.55}frac{3}{11}
b)x+frac{15}{90.94}+frac{15}{94.98}+frac{15}{98.102}+...+frac{15}{146.150}frac{2}{3}
c)x-frac{1}{2}-frac{1}{6}-frac{1}{12}-frac{1}{20}-frac{1}{30}-frac{1}{42}-frac{1}{56}frac{5}{24}
d)8-frac{8-frac{8}{5}+frac{8}{25}-frac{8}{125}}{9-frac{9}{5}+frac{9}{25}-frac{9}{125}}:frac{161616}{151515}frac{4+frac{4}{73}-frac{4}{115}}{5+frac{5}{73}-frac{1}{23}}
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Bài 1:Tìm x,biết
a) \(x-\frac{20}{11.13}-\frac{20}{13.15}-\frac{20}{15.17}-...-\frac{20}{53.55}=\frac{3}{11}\)
b)\(x+\frac{15}{90.94}+\frac{15}{94.98}+\frac{15}{98.102}+...+\frac{15}{146.150}=\frac{2}{3}\)
c)\(x-\frac{1}{2}-\frac{1}{6}-\frac{1}{12}-\frac{1}{20}-\frac{1}{30}-\frac{1}{42}-\frac{1}{56}=\frac{5}{24}\)
d)\(8-\frac{8-\frac{8}{5}+\frac{8}{25}-\frac{8}{125}}{9-\frac{9}{5}+\frac{9}{25}-\frac{9}{125}}:\frac{161616}{151515}=\frac{4+\frac{4}{73}-\frac{4}{115}}{5+\frac{5}{73}-\frac{1}{23}}\)
a, Câu hỏi của Nguyễn Ánh Ngân - Toán lớp 6 - Học toán với OnlineMath
b, Câu hỏi của Vũ Xuân Hiếu - Toán lớp 6 | Học trực tuyến
c)
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Bài 1:
\(\frac{7}{12}+\frac{-8}{15}\) ; \(\frac{5}{12}+\frac{-8}{15}\)
Bài 2: Tìm x
a)x - 23 =-56
b)2x - 36 = 24
c)x - \(\frac{4}{5}=\frac{3}{2}\)
d)x - 46 =123
e)2x - 25= -45
f)x -\(\frac{2}{3}=\frac{-7}{5}\)
mn ơi giúp em vs trước tối nay có nha mn
cảm ơn mn
Bài 1:
\(\frac{7}{12}+\frac{-8}{15}=\frac{7}{12}-\frac{8}{15}=\frac{35}{60}-\frac{32}{60}=\frac{3}{60}=\frac{1}{20}\)
\(\frac{5}{12}+\frac{-8}{15}=\frac{5}{12}-\frac{8}{15}=\frac{25}{60}-\frac{32}{60}=\frac{-7}{60}\)
Bài 2:
\(a,x-23=-56\)
\(x=-56+23\)
\(x=-33\)
\(b,2x-36=24\)
\(2x=60\)
\(x=30\)
\(c,x-\frac{4}{5}=\frac{3}{2}\)
\(x=\frac{3}{2}+\frac{4}{5}=\frac{23}{10}\)
\(d,x-46=123\)
\(x=123+46=169\)
\(e,2x-25=-45\)
\(2x=-20\)
\(x=-10\)
\(f,x-\frac{2}{3}=-\frac{7}{5}\)
\(x=-\frac{7}{5}+\frac{2}{3}=-\frac{11}{15}\)
=.= hk tốt!!
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Đúng ghi Đ, sai ghi S vào chỗ chấm:a) frac{3}{7}+frac{1}{3}xfrac{3}{7}frac{16}{21}xfrac{3}{7}frac{16}{49} ......b)frac{5}{9}+frac{1}{5}xfrac{5}{6}frac{5}{9}xfrac{1}{6}frac{13}{18} ......c)frac{13}{9}-frac{7}{9}:frac{2}{3}frac{6}{9}:frac{3}{2}1 ......d)frac{11}{8}-frac{5}{8}:frac{3}{4}frac{11}{8}-frac{5}{8}xfrac{4}{3}frac{11}{8}-frac{10}{24}frac{23}{24} ......
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Đúng ghi Đ, sai ghi S vào chỗ chấm:
a) \(\frac{3}{7}+\frac{1}{3}x\frac{3}{7}=\frac{16}{21}x\frac{3}{7}=\frac{16}{49}\) ......
b)\(\frac{5}{9}+\frac{1}{5}x\frac{5}{6}=\frac{5}{9}x\frac{1}{6}=\frac{13}{18}\) ......
c)\(\frac{13}{9}-\frac{7}{9}:\frac{2}{3}=\frac{6}{9}:\frac{3}{2}=1\) ......
d)\(\frac{11}{8}-\frac{5}{8}:\frac{3}{4}=\frac{11}{8}-\frac{5}{8}x\frac{4}{3}=\frac{11}{8}-\frac{10}{24}=\frac{23}{24}\) ......
Mai Hồng Ngọc? Vũ Thị Thu Hằng? Ai đúng dzậy -_-*
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Xem thêm câu trả lời
tính A=\(\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+\frac{4}{5}+......+\frac{2015}{2016}\)
tim x \(\frac{x-2}{12}+\frac{x-2}{20}+\frac{x-2}{30}+\frac{x-2}{42}+\frac{x-2}{56}+\frac{x-2}{72}+\frac{16}{9}\)
bài 2 tìm xa,frac{-2}{3}.x+frac{1}{5}frac{3}{10}b,left|xright|-frac{3}{4}frac{5}{3}c,frac{2}{3}.x-frac{1}{2}frac{1}{10}d,frac{3}{5}+frac{4}{9}:xfrac{2}{3}e,left|x+75%right|2frac{1}{5}i,left(x+frac{1}{2}right).left(frac{2}{3}-2.xright)0k,frac{4}{7}.x-frac{2}{3}frac{1}{5}l,frac{2}{3}.x-frac{3}{2}.xfrac{5}{12}m,left|2.x-frac{1}{3}right|+frac{5}{6}1n,frac{1}{3}-frac{7}{8}.xfrac{1}{3}11,frac{x+2}{5}frac{7}{12}-1frac{1}{4}12,left(2frac{4}{5}.x-50right):frac{2}{3}5113,frac{2}{5}+frac{3}{5}.left(3.x-3,7...
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bài 2 tìm x
a,\(\frac{-2}{3}.x+\frac{1}{5}=\frac{3}{10}\)
b,\(\left|x\right|-\frac{3}{4}=\frac{5}{3}\)
c,\(\frac{2}{3}.x-\frac{1}{2}=\frac{1}{10}\)
d,\(\frac{3}{5}+\frac{4}{9}:x=\frac{2}{3}\)
e,\(\left|x+75\%\right|=2\frac{1}{5}\)
i,\(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2.x\right)=0\)
k,\(\frac{4}{7}.x-\frac{2}{3}=\frac{1}{5}\)
l,\(\frac{2}{3}.x-\frac{3}{2}.x=\frac{5}{12}\)
m,\(\left|2.x-\frac{1}{3}\right|+\frac{5}{6}=1\)
n,\(\frac{1}{3}-\frac{7}{8}.x=\frac{1}{3}\)
11,\(\frac{x+2}{5}=\frac{7}{12}-1\frac{1}{4}\)
12,\(\left(2\frac{4}{5}.x-50\right):\frac{2}{3}=51\)
13,\(\frac{2}{5}+\frac{3}{5}.\left(3.x-3,7\right)=-\frac{53}{10}\)
14,\(\frac{7}{9}:\left(2+\frac{3}{4}.x\right)+\frac{5}{9}=\frac{23}{27}\)
Bài 1:Tìm x Biết
a\ \(x-\frac{10}{3}=\frac{7}{15}\times\frac{3}{5}\)
b\ \(x+\frac{3}{22}=\frac{27}{121}\times\frac{11}{9}\)
c\ \(\frac{8}{23}\times\frac{46}{24}-x=\frac{1}{3}\)
d\ \(1-x=\frac{49}{65}\times\frac{5}{7}\)
a) \(x-\frac{10}{3}=\frac{7}{15}\cdot\frac{3}{5}\) b) \(x+\frac{3}{22}=\frac{27}{121}\cdot\frac{11}{9}\)
\(\Leftrightarrow x-\frac{10}{3}=\frac{7}{25}\) \(\Leftrightarrow x+\frac{3}{22}=\frac{3}{11}\)
\(\Rightarrow x=\frac{7}{25}+\frac{10}{3}\) \(\Rightarrow x=\frac{3}{11}-\frac{3}{22}\)
\(x=\frac{271}{75}\) \(x=\frac{3}{22}\)
c) \(\frac{8}{23}.\frac{46}{24}-x=\frac{1}{3}\) d) \(1-x=\frac{49}{65}.\frac{5}{7}\)
\(\Leftrightarrow\frac{2}{3}-x=\frac{1}{3}\) \(\Leftrightarrow1-x=\frac{7}{13}\)
\(\Rightarrow x=\frac{2}{3}-\frac{1}{3}\) \(\Rightarrow x=1-\frac{7}{13}\)
\(x=\frac{1}{3}\) \(x=\frac{6}{13}\)
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