\(\frac{8.5-8.2}{16}\)

\(=\frac{8.\left(5-2\right)}{8.2}=\frac{8.3}{8.2}=\frac{3}{2}\)

\(\frac{8.5-8.2}{16}\)

\(=\frac{8.\left(5-2\right)}{16}\)

\(=\frac{8.3}{16}\)

\(=\frac{4.2.3}{4.4}\)

\(=\frac{6}{4}=\frac{3}{2}\)

\(\frac{8.5-8.2}{16}=\frac{8.\left(5-2\right)}{8.2}=\frac{8.3}{8.2}=\frac{1.3}{1.2}\)

                                                                       =  \(\frac{3}{2}\)

Hoc tốt

3/2=1,5

cách giải thế nào đã rồi mình tick cho

bạn thảo  diễn giải ra jùm mình 

\(=2\frac{4}{\sqrt{5}}-5\frac{3}{5\sqrt[]{5}}-6\frac{11}{3\sqrt{5}}\)

\(=\frac{2.4.15-5.3.3-6.11.5}{15\sqrt{5}}\)

\(=\frac{-255}{15\sqrt{5}}=\frac{-17\sqrt{5}}{5}\)

*Rút gọn :

`(8.5-8.2)/16=(8.(5-2))/(8.2)=(8.3)/(8.2)=3/2`

`(11.4-11)/(2-13)=(11.(4-1))/(-11)=(11.3)/(-1.11)=3/(-1)=-3`

*Quy đồng :

- Ta có : `-3=(-3)/1`

UCLN(2,1)=2

$\to\begin{cases} \dfrac32=\dfrac32\\\dfrac{-3}1=\dfrac{-6}2\end{cases}$

a) \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{0,3\cdot10}{16\cdot10}=\dfrac{3}{160}\)

b) \(\dfrac{17\cdot5-17}{3-20}=\dfrac{17\cdot\left(5-1\right)}{-17}=\dfrac{1\cdot4}{-1}=-4\)

a)

\(\dfrac{8\cdot5-8\cdot2}{16}=\dfrac{8\left(5-2\right)}{16}=\dfrac{3}{2}\)

b)

\(\dfrac{17\cdot5-17}{3-20}=\dfrac{17\left(5-1\right)}{-17}=\dfrac{4}{-1}=-4\)

a, \(=\frac{8\left(x+2y\right)^5}{2\left(x+2y\right)}=8\left(x+2y\right)^4\)

b,\(=\left(\frac{3}{4}\right)^{45}:\left(\left(\frac{3}{4}\right)^2\right)^{10}\)

\(=\left(\frac{3}{4}\right)^{45}:\left(\frac{3}{4}\right)^{2.10}=\left(\frac{3}{4}\right)^{25}\)

thiếu nè 8:2=4 nha sửa lại cái

ad em giải nhanh nhất 

Bài làm

\(C=\frac{2.5^{22}-9.5^{21}}{25^{10}}:\frac{5.\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)

\(C=\frac{2.5^{21}.5-9.5^{21}}{25^{10}}:\frac{5.\left(3.7^{14}.7-19.7^{14}\right)}{7^{16}.7+3.7^{15}}\)

\(C=\frac{5^{21}.\left(2-9\right).5}{\left(5.5\right)^{10}}:\frac{5.[7^{15}.\left(3-19\right)].7}{7^{15}.\left(3+1\right).7}\)

\(C=\frac{5^{21}.\left(-7\right).5}{5^{10}.5^{10}}:\frac{5.7^{15}.\left(-16\right).7}{7^{15}.4.7}\)

\(C=\frac{5^{21}.\left(-35\right)}{5^{10}.5^{10}}:\frac{7^{15}.\left(-112\right).5}{7^{15}.28}\)

\(C=5.\left(-35\right):\frac{7^{15}.560}{7^{15}.28}\)

\(C=5.\left(-35\right):\frac{1.560}{1.28}\)

\(C=5.\left(-35\right):20\)

\(C=5.\left(-35\right).\frac{1}{20}\)

\(C=-\frac{175}{20}\)

\(C=-\frac{35}{4}\)

Vậy biểu thức trên \(C=\frac{2.5^{22}-9.5^{21}}{25^{10}}:\frac{5.\left(3.7^{15}-19.7^{14}\right)}{7^{16}+3.7^{15}}\)bằng \(C=-\frac{35}{4}\)

# Chúc bạn học tốt #

cô giáo bn chữa bài đó chưa, mình làm đúng hay sai vậy

\(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.2^{10}}=\frac{2^{2.5}.3^{2.4}-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^0}=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^8.3^8}=\frac{2^{10}.3^8\left(1-3\right)}{2^8.3^8\left(2^2+1\right)}=\frac{4.-2}{5}=-\frac{8}{5}\)

ban kia lam dung roi do

k tui nha

thanks

\(I=\frac{\frac{25}{17}-\frac{25}{27}-\frac{25}{37}-\frac{25}{47}}{\frac{45}{17}-\frac{45}{27}-\frac{45}{37}-\frac{45}{47}}\)

\(I=\frac{25.\left(\frac{1}{17}-\frac{1}{27}-\frac{1}{37}-\frac{1}{47}\right)}{45.\left(\frac{1}{17}-\frac{1}{27}-\frac{1}{37}-\frac{1}{47}\right)}\)

\(I=\frac{25}{45}=\frac{5}{9}\)